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Questions tagged [axiom-of-choice]

The axiom of choice is a common set-theoretic axiom with many equivalents and consequences. This tag is for questions on where we use it in certain proofs, and how things would work without the assumption of this axiom. Use this tag in tandem with (set-theory).

1 vote
0 answers
52 views

Countable Choice from Finite Sets

Consider the following 4 statements: Axiom of countable choice Axiom of countable choice from finite sets Axiom of countable choice from Dedekind finite sets Existence of a choice function for any ...
svq0231's user avatar
  • 11
3 votes
0 answers
82 views

A union of unions needn't be a union? (Sans AC) [duplicate]

For any collection $\mathscr C$ of sets, write $\Upsilon(\mathscr C)$ for the collection of arbitrary unions in $\mathscr C$. Now, I ask the innocent question of idempotency of $\Upsilon$: Is $\...
Atom's user avatar
  • 4,119
2 votes
1 answer
76 views

Does $A$-fold choice imply $|A| + |A| = |A|$ and $|A|\cdot |A| = |A|$?

Let $A$ be an infinite set. Then Zorn's lemma can be used to conclude that $A\times\{0, 1\}$, $A\times A$ and $A$ are all equinumerous (a proof is presented here). However, I am aware that for $A$ ...
Atom's user avatar
  • 4,119
0 votes
0 answers
41 views

Is there a model of ZF not C where not every set of reals is Lebesgue measurable? [duplicate]

I know that there is a model of ZF set theory plus the negation of the axiom of choice where every set of reals is Lebesgue measurable. But is there also a model where not every set of reals is ...
user107952's user avatar
  • 21.5k
2 votes
0 answers
65 views

Principle in between BPI and AC

I have searched extensively in the literature, but all references I have consulted always place BPI (the Boolean Prime Ideal Theorem) as a sort of "cover" of the Axiom of Choice as far as ...
Rodrigo Nicolau Almeida's user avatar
6 votes
1 answer
77 views

Is every (infinite) permutation the composition of 2 involutions in ZF?

It is well known that any permutation on a finite set is the product of two involutions. I've wondered about what can happen in infinite sets. Asuming the axiom of choice, every permutation is still a ...
Carla_'s user avatar
  • 457
3 votes
0 answers
43 views

Discontinuous linear map and AC

The question arises when I am constructing an elementary proof for the following claim: Given a normed vector space $V$, the following are equivalent: $V$ is finite dimensional Every linear map $T:V\...
Akira Satou's user avatar
0 votes
1 answer
26 views

Axiom of Choice in characterizing openness in subspace

Below is the typical characterization of open sets in a subspace $Y$ of a metric space $X$. $E$ is $Y$-open iff there exists an $X$-open $S$ such that $E = S \cap Y$. The forwards direction usually ...
n1lp0tence's user avatar
2 votes
0 answers
132 views

Why is the Axiom of Choice Necessary in ZFC

Within the framework of Zermelo-Fraenkel set theory with the Axiom of Choice $(ZFC)$, when we considered the method of constructing the set of natural numbers, we regarded it as the smallest inductive ...
Bezina Taki's user avatar
1 vote
2 answers
138 views

Are the sets of the form $a=\{a\}$ different?

Suppose we adopt all the ZF axioms except the axiom of foundation. I suppose even adding the AC would not harm my question. Somewhere on the internet, I read that in this case, the axiom of ...
Bumblebee's user avatar
  • 18.4k
0 votes
2 answers
63 views

Truncated Tarski's theorem without axiom of choice

I read there that the fact about equivalence of $A$ and $A^2$ for any infinite set $A$ and the axiom of choice are equivalent. But what if we prove it only for sets that have cardinality of $\aleph_n,...
nyekitka's user avatar
  • 103
1 vote
1 answer
41 views

uniform well-ordering and constructibility

When comparing between V=L and AC, one of the things that gets my attention is that, if we switch to an external perspective and don't care about first-order expressibility, in models of V=L we have a ...
Raczel Chowinski's user avatar
0 votes
1 answer
64 views

Is ACC implicitely involved in a construction?

Suppose that $X$ is a (edit: separable) complete metric space and $\{X_j:j\ge 1\}$ is a partition of $X$ (each $X_j\ne \emptyset$). Given a (continuous) function $f:X\to \mathbb{R}$, I construct $$ h(...
Robert W.'s user avatar
  • 724
1 vote
0 answers
38 views

The relation between the cardinality of Bore $\sigma$-algebra and axiom of choice

Under axiom of choice, the cardinality of Borel $\sigma$-algebra $B$ is $\mathfrak{c}$. In this proof axiom of choice is used three times: To prove $\omega_1$-times recursion is sufficient, each $|B_{...
Gizerst Nanari's user avatar
0 votes
3 answers
71 views

Construction of Proof: Zorn's lemma implies Axiom of choice

I have come across the prove that [Zorn's Lemma ==> AC] but am confused about the central statement, namely that we can take a set of all choice functions on subsets of X (lets just call it X, I ...
CopperCableIsolator's user avatar

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