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4 votes
2 answers
84 views

Internally Inhabited Object Which Is Not Externally Inhabited

What is the simplest example of a topos with an object $X$ which is internally ($X\to \mathbf{1}$ is epi) but not externally (no $\mathbf{1}\to X$) inhabited? I think that for all categories $C$, in ...
fweth's user avatar
  • 3,584
6 votes
1 answer
166 views

Cohomology and axiom of choice

I was reading this paper talking about how cohomology theories are related to the axiom of choice. I would like to have a better understanding of one of the first topics discussed. At the bottom of ...
FreeFunctor's user avatar
4 votes
1 answer
68 views

Uniform Choice Functions and Naturality

Some choice functions can be specified explicitly, while in other cases no definite choice function is known. An example of the former is a choice function for non-empty subsets of natural numbers, ...
vigenary's user avatar
6 votes
2 answers
181 views

Defining subcategories and axiom of choice

Questions: 1. When do objects of a category form a set? Is there a choice function when I have a set of categories (as opposed to a set of sets)? Is there an axioma schema of separation for defining (...
red whisker's user avatar
  • 1,274
2 votes
2 answers
234 views

Where is choice used in "Every category monadic over Set is regular"

From Johnstone's notes: If $\mathbb{T}$ is a monad on $\mathcal{C}$ whose functor part $T$ preserves covers then the functoriality of image factorisation induces a unique algebra structure on the ...
Oddly Asymmetric's user avatar
3 votes
0 answers
62 views

Could a small category have non-isomorphic skeletons without the axiom of choice?

Without the axiom of choice, could there be a small category with two non-isomorphic skeletons? Let $C$ be a small category and $S$ and $S'$ be two skeletons of $C$ (i.e., full subcategories ...
Geoffrey Trang's user avatar
7 votes
0 answers
305 views

(Proper) classes and the General Adjoint Functor Theorem

Original problem A few days ago I asked the following question on Stackexchange. Essentially, I was asking how to verify via one of the adjoint functor theorems that the forgetful functor from $\...
Margaret's user avatar
  • 1,769
6 votes
2 answers
289 views

Characterization of basis in terms of universal property: axiom of choice

I wonder if the proof of the following statement requires the axiom of choice: (Characterization of basis in terms of universal property) Let $V$ be a vector space, and let $S$ be a non-empty subset ...
metaverse's user avatar
  • 361
8 votes
1 answer
259 views

Which presheaf toposes satisfy the axiom of choice?

Which toposes of presheaves $\mathbf{Set}^{C^\mathrm{op}}$ satisfy the axiom of choice (every epimorphism splits)? Can one formulate a condition on $C$ that yields a necessary or sufficient condition ...
user1009651's user avatar
10 votes
1 answer
525 views

Epic morphisms in the category of vector spaces. Is AC needed?

In $\mathsf{FinVect}_k$, the category of finite-dimensional $k$-vector spaces, all epis are surjective, by the argument given in this answer. I know how to generalize this argument to $\mathsf{Vect}_k$...
Elías Guisado Villalgordo's user avatar
5 votes
1 answer
96 views

Isomorphism of products in a category: Does it involve the axiom of choice?

Let $(X_i), (Y_i)$ be two families of objects indexed by the same index set $I$ in a category with products. It seems obvious that if $X_i, Y_i$ are isomorphic for all $i$, then also the products $\...
Kritiker der Elche's user avatar
1 vote
1 answer
138 views

A proof about skeletons without axiom of choice

I'm trying to prove this statement and I found two different proofs: the first seems to work without explicit use of AC while the second uses it precisely where I expected it. (T) Let $i$ be a ...
MphLee's user avatar
  • 2,512
2 votes
1 answer
125 views

Axiom of choice in sheafification?

Let $(\mathbb{C}, J)$ be a small site, and let $F : \mathbb{C}^{\mathsf{op}} \to \mathsf{Set}$ be a separated presheaf with respect to $(\mathbb{C}, J)$. In the usual proof that $F^+ : \mathbb{C}^\...
User7819's user avatar
  • 1,621
1 vote
2 answers
175 views

The axiom of choice for a category

I am currently studying the counterpart of axiom of choice in ETCS which is the axiom that every surjective function has a right inverse. In category of sets the surjective functions are epimorphsims ...
Elise's user avatar
  • 183
0 votes
0 answers
47 views

Every surjective function has a right inverse [duplicate]

I am studying the counterpart of the axiom of choice in ETCS which is that "Every surjective fucntion has a right inverse". I am trying to see why it implies the axiom of choice and this is ...
Elise's user avatar
  • 183

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