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1 vote
0 answers
27 views

Mean term in simple linear regression

I am trying to derive the expression for the $E(y_i \epsilon_i)$ in simple linear regression. I substitute using $Cov(X,Y) = E(XY) - E(X)E(Y)$, so $E(y_i \epsilon_i) = Cov(y_i , \epsilon_i)- (E(y_i)...
Beth's user avatar
  • 111
5 votes
1 answer
500 views

Zero Covariance vs Independence of Slope and Intercept Estimators in Linear Models with Least Squares

$\newcommand{\Cov}{\operatorname{Cov}}$Problem Statement: Under the assumptions of Exercise 11.16, find $\Cov\big(\hat\beta_0,\hat\beta_1\big).$ Use this answer to show that $\hat\beta_0$ and $\hat\...
Adrian Keister's user avatar
0 votes
0 answers
76 views

Zero conditional expectation implying zero covariance?

Proof: E[X|Y]=0 implies COV[X,Y]=0 I was thinking maybe the law of total covariance or tower rule but couldn't come up with the proof
Confused's user avatar
0 votes
0 answers
59 views

Finding Cov(X,Y) given pdf(X,Y)

Could you please guide me in the right direction for the problem below? I don't know if I am right, but here is a headstart Cov(X,Y) = E(XY) - E(X)E(Y) = $\int_{0}^{\infty}\int_{0}^{\infty} ...
piby180's user avatar
  • 101
1 vote
1 answer
48 views

Proving covariance

is this the right method of proving: \begin{align} Cov(a_0+a_1R_1+a_2R_2, Q_1)=a_1Cov(R_1,Q_1)+a_2(R_2,Q_1) \end{align} By \begin{align} =Cov(a_0+a_1R_1+a_2R_2, Q_1) \end{align} \begin{align} =Cov(...
Mataunited17's user avatar
0 votes
2 answers
97 views

Proving covariance using (Pearson) correlation coefficient

Could anyone guide or show me how to prove the covariance $$2\cdot Cov\left(\frac{X}{\sigma_X},\frac{Y}{\sigma_Y}\right)=\frac{2}{\sigma_X\sigma_Y}Cov(X,Y)$$ with $$Cov(X,Y) = E(X − E(X))(Y − E(Y ))...
Mataunited17's user avatar
2 votes
0 answers
190 views

Understanding Autocovariance under Gaussian Random Process

I'm recently been trying to understand time series better,and would really appreciate if someone can show me this: I found this online under a lecture slide by J. McJames of Portland Univ., and I ...
pikachumonster's user avatar
9 votes
2 answers
11k views

Covariance of two sample means

I am trying to derive the covariance of two sample means and get confused at one point. Given is a sample of size $n$ with paired dependent observations $x_i$ and $y_i$ as realizations of RVs $X$ and $...
tomka's user avatar
  • 6,624
2 votes
1 answer
193 views

Finding $Cov(2X+7, X^2 +3X - 12)$

So I have this pdf, $f(x)=3x^2$ for $x\in (0,1)$ and I need to find $Cov(2X+7, X^2+3X-12)$. My main concern about how I answer this is, what is the joint pdf for these two distributions? I guess it'...
Addem's user avatar
  • 489
5 votes
1 answer
114 views

Question regarding covariance

I'm trying to prove a theorem, where it is given that each $X_i$ is independent and identically distributed with mean $\mu$ and variance $\sigma^2$. Within this theorem, I have multiple sub-results to ...
Savage Henry's user avatar
4 votes
1 answer
162 views

Sample covariance mean-corrected vector proof

Prove that $$(n-1)S = X^TX -{1\over{n}}(X^T\vec1)(\vec1^TX) = X^TX-n\vec{\bar x}\vec{\bar x}^T$$ My attempt so far goes like this $$S = {1\over{n-1}}X_m^TX_m$$ Edit: Where $X_m$ is the mean ...
user123965's user avatar
2 votes
1 answer
56 views

Covariance help

Consider an experiment in which a fair coin is tossed 10 times in a row (the tosses are independent of each other). Let X denote the number of heads observed and let Y=X^2. Find the covariance between ...
user42276's user avatar
8 votes
2 answers
11k views

Covariance term in simple linear regression

I am trying to derive the expression for the variance of $\hat{\beta_0}$ in simple linear regression. I substitute $\bar{y} - \hat{\beta_1} \bar{x}$ for $\hat \beta_0$, but in the intermediate steps ...
user2350622's user avatar
2 votes
1 answer
3k views

Covariance with conditional expectation

Suppose $X$ and $Y$ are random variables, $E(Y^2) < \infty$ and $\varepsilon = Y - E(Y|X)$ so that $Y = E(Y|X) + \varepsilon$. Given that $E(\varepsilon | X) = E(\varepsilon) = 0$, show that $Cov(\...
Karnage2015's user avatar
6 votes
1 answer
338 views

Why is Pearson's correlation coefficient defined the way it is?

$$ r = \frac{{\rm Cov}(X,Y)}{ \sigma_{X} \sigma_{Y}} $$ I do not understand this equation at all. Where does it come from? From my personal understanding ${\rm Cov}(X,Y)$ comes from that fact that $...
Person's user avatar
  • 406

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