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-4 votes
1 answer
66 views

Cannot understand this identity between kronecker and metric tensor [closed]

I'm working on Lorentz generators and I am really not able to understand this relation: $$\omega_{\rho \sigma} \eta^{\rho\mu} \delta^{\alpha}_{\nu} = \frac{1}{2}\omega_{\rho \sigma} \left(\eta^{\rho\...
Heidegger's user avatar
  • 361
0 votes
0 answers
29 views

Unclear passage in Lorentz generators derivation

It's not clear to me a passage, in the extraction of the generators of Lorentz's group acting on the Minkowksi's space points: we have \begin{equation*} \begin{split} x^{' \alpha} & = \Lambda^{\...
Heidegger's user avatar
  • 361
1 vote
1 answer
91 views

Questions about Lorentz Matrices and Lorentz Metric

(I use the abstract index notation convention in this post) In $\mathbb{R}^4$, denote the Lorentz Metric as $g_{\mu\nu}=$diag$(-1,1,1,1)$, then we can define the Lorentz Matrices to be all $4\times 4$ ...
BoyanLiu's user avatar
1 vote
1 answer
94 views

Why does the full contraction of a tensor and its (Hodge) dual is a pseudoscalar?

I'm trying to prove that the contraction between a tensor and its dual is a pseudoscalar, while the contraction of the dual with itself is just a scalar. I'm using index notation and every time I try ...
Edoardo Bertoli's user avatar
0 votes
1 answer
83 views

How can I calculate the square of Pauli-Lubanski vector in a rest frame?

recently I've been trying to demonstrate that, $$\textbf{W}^2 = -m^2\textbf{S}^2$$ in a rest frame, with $W_{\mu}$ defined as $$W_{\mu} = \dfrac{1}{2}\varepsilon_{\mu\alpha\beta\gamma}M^{\alpha\beta}p^...
clebbf's user avatar
  • 1
0 votes
1 answer
209 views

Formulation of the Bianchi identity in EM

I'm trying to understand, as a self learner, the covariant formulation of Electromagnetism. In particular I've been stuck for a while on the Bianchi identity. As I've come to understand, when we ...
Luke__'s user avatar
  • 540
0 votes
1 answer
69 views

Doubt about product of four-vectors and Minkowski metric [closed]

Given the Minkowski metric $\eta_{\mu\nu}$ And $\eta^{\mu\nu}\eta_{\mu\nu}$=4 I can write $\eta^{\mu\nu}\eta_{\mu\nu}k^{\mu}k^{\nu}$=$4k^{\mu}k^{\nu}$ But $\eta^{\mu\nu}\eta_{\mu\nu}k^{\mu}k^{\nu}$=$\...
rafa's user avatar
  • 13
-1 votes
2 answers
95 views

Confusion with Lorentz indices notation

Apologies in advance if this question has been asked before (if it has, I can't find it). I am really confused with the right-left index notation of the Lorentz matrix. In the very first exercise of ...
Hrach's user avatar
  • 280
0 votes
0 answers
432 views

How to know if a matrix is a (0,2) tensor, a (2,0) tensor or a (1,1) tensor?

For example: $$ X = \begin{bmatrix} 1 & -1 & 0 & 0 \\ -1 & 0 & 5 & 3 \\ -2 & 1 & 0 & 0 \\ 0 & 1 & 0 & 2 ...
Firestar-Reimu's user avatar
1 vote
1 answer
516 views

Contraction of Levi-Civita tensor in Minkowski space-time (or any space-time)

I know that $\varepsilon_{i_1 i_2\cdots i_n}\varepsilon^{i_1 i_2\cdots i_n} = n!$ in Euclid space. But in Minkowski space-time, the metric tensor is: $$ \eta_{\mu\nu} = \mathrm{diag}\{-1, 1, 1, 1\} $$ ...
Firestar-Reimu's user avatar
2 votes
0 answers
124 views

Weinberg's proof that $F^{\alpha \beta}$ is a tensor

I am interested in Weinberg's approach to proving that $F^{\alpha \beta}$ is a tensor in his book Gravitation and Cosmology. He begins by rewritting the Maxwell equations as: $$\frac{\partial}{\...
jake walsh's user avatar
1 vote
1 answer
87 views

Electromagnetic tensor and its components

I'm dealing with the covariant formulation of electromagnetism and I've come across the Electromagnetic tensor after learning a bit about the covariant notation. In particular I've problems ...
Alessandro Tassoni's user avatar
1 vote
3 answers
636 views

Difference between upper and lower indices in Einstein notation

Consider a $(2,0)$ tensor $X^{\mu \nu}$ that can be represented in matrix form by: $$X^{\mu \nu} = \pmatrix{ a & b & c & d \\ e & f & g & h \\ i & j & k & l \\ m &...
pll04's user avatar
  • 337
2 votes
0 answers
74 views

Find the energy-impulse tensor of a fluid of charged dust from the action principle

I have the total action given by: $$S_{tot} = -\frac{1}{16\pi c}\int d\Omega\ F^{\mu \nu}F_{\mu \nu} + \sum_{i=1}^{N}\bigg(-\frac{q}{c}\int dx_i^\mu A_\mu - mc \int ds_i\bigg) \\= \int d\Omega\ \frac{...
Serena Bruzzesi's user avatar
1 vote
1 answer
188 views

Null surfaces in Lorentzian manifold

Null Hypersurface of Lorentzian Manifold: A hypersurface that admits a null-like normal vector field($N^a$) to it. i.e. $g_{ab}N^a N^b=0$ (metric signature$(-1,1,1,1,...)$) In Minkowski spacetime the ...
Antonio's user avatar
  • 27

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