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1 vote
0 answers
26 views

Proving that the Faddeev-Popov path integral is independent of the gauge choice? [duplicate]

I know that the Faddeev-Popov path integral is gauge invariant. But how does one show that \begin{equation} I = \int \mathcal{D}\mathcal{A}_\mu \bigg|\frac{\delta\mathcal{G}}{\delta{\omega}}\bigg|\...
QFTheorist's user avatar
0 votes
1 answer
480 views

Use of background field method

How do we use the background field method for renormalize a gauge theory?
Olandelie's user avatar
3 votes
1 answer
403 views

What is the "volume of the gauge group"?

I often see the term "volume of the gauge group" and I am not clear on what this is referring to. For example, in the second volume of Weinberg (page 22), he says ...the volume of the gauge ...
CBBAM's user avatar
  • 3,350
7 votes
3 answers
903 views

How does the absence of quadratic terms in the Lagrangian imply massless quanta?

When studying gauge theory, I often see the statement that gauge invariance does not allow the Lagrangian of the theory to contain terms that are quadratic in the gauge field. For example, to quote ...
CBBAM's user avatar
  • 3,350
1 vote
0 answers
67 views

Arbitrary heat kernel coefficients of covariant Laplacian with instanton

The heat kernel coefficients $b_{2k}(x,y)$ of the covariant Laplacian in an $SU(2)$ instanton background (for simplicity let's say $q=1$ topological charge, so the 't Hooft solution) on $R^4$ is ...
Fetchinson0234's user avatar
3 votes
1 answer
106 views

Can we eliminate gauge degrees of freedom in QFT by quantizing the field strength directly?

In Matthew Schwartz's Quantum Field Theory and the Standard Model, he says (section 8.6, page 132) that it is possible to avoid introducing the redundant gauge degrees of freedom in QED by quantizing $...
Astute Reader's user avatar
5 votes
1 answer
107 views

Is the Hamiltonian some sort of connection/gauge field?

I'm not sure if this is a well-defined question, but I was just looking through some old notes and noticed that the Hamiltonian in usual QM has a similar transformation as gauge fields in QFT: under ...
Wihtedeka's user avatar
  • 2,068
2 votes
1 answer
248 views

Difference between Gauge invariance and BRST invariance

Which is the difference between gauge invariance and BRST invariance? Is it the same symmetry? Is the BRST the extention of the gauge symmetry even on the ghost fields?
nabla_quadro's user avatar
0 votes
0 answers
46 views

Non-linear symmetry and symmetry at quantum level

Can anyone explain me what does the statement mean: "the BRST symmetry is a non-linear symmetry, so the BRST is also a symmetry at the quantum level"? What does "at the quantum level&...
nabla_quadro's user avatar
2 votes
1 answer
121 views

Magnetic field due to singular gauge transformation

In $SU(2)$ gauge theory over $\mathbb R^3$, consider the following gauge transformation (in spherical polar coordinates) $$ \Omega=\begin{bmatrix}e^{i\phi}\cos(\theta/2)&\sin(\theta/2)\\-\sin(\...
dennis's user avatar
  • 742
3 votes
0 answers
180 views

Witten anomaly and bound states of fermions

In his famous paper "An SU(2) anomaly", Witten begins by noting that an SU(2) gauge theory with a single fermion in the doublet representation is weird, since there is "no obvious ...
AccidentalFourierTransform's user avatar
1 vote
0 answers
46 views

Group factors in scalar-gauge box diagram

So, I'm currently writing my Thesis, which involves one-loop beta functions of a general $SU(N)$ for scalars and fermions fields, Yukawa coupling and one scalar self-coupling. To this moment I was ...
Lp_cam's user avatar
  • 21
3 votes
1 answer
180 views

What does the dual gauge field have to do with topology?

The dual gauge field, $V$, is defined by $$^{\star}F(V)=F(A),$$ where $F$ is the field strength. The 't Hooft operator $\exp(i\int_C V)$ creates the trajectory of a magnetic particle along $C$. But I ...
dennis's user avatar
  • 742
1 vote
1 answer
131 views

Why is the Gribov ambiguity not seen in perturbation theory?

I have read that the Gribov ambiguity doesn't appear in perturbation theory. Can anyone say why? I found the following line in "Gribov copies and confinement" by Anton Ilderton [1]: Recall ...
dennis's user avatar
  • 742
0 votes
2 answers
157 views

Explicit formula for a gauge transformation with winding number?

Does anyone know of an explicit expression for a gauge transformation, $\Omega:S^3\to G$, with a non-zero winding number (with $G=SU(n)$ say)?
dennis's user avatar
  • 742

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