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6 votes
2 answers
358 views

Introduce Ghost Field to eliminate unphysical degrees of freedom in case of Photon Field

In wikipedia's article about ghost fields is stated the following which requires a bit more clarification: An example of the need of ghost fields is the photon, which is usually described by a four ...
user267839's user avatar
  • 1,395
1 vote
1 answer
159 views

Calculating a Gaussian-like path integrals with Grassmann variables and real variables

I want to compute the following path integral $$Z[w] = \frac{1}{(2\pi)^{n/2}}\int d^n x \: \prod_{i=1}^{n}d\overline{\theta}_id\theta \: \exp{\left(-\overline{\theta}_i \partial_j w_i(x)\theta_j -\...
Geigercounter's user avatar
2 votes
0 answers
56 views

Typo of P&S' QFT eq.(16.40)

First, begin with P&S's QFT eq.(16.39): $$ \frac{1}{2}\left[\left(i \mathcal{M}^{\mu \nu} \epsilon_\mu^{-*} \epsilon_\nu^{+*}\right)\left(i \mathcal{M}^{\prime \rho \sigma} \epsilon_\rho^{+} \...
Daren's user avatar
  • 1,421
3 votes
2 answers
147 views

Motivation of Grassmann fields in the Faddeev-Popov method for free Gluon fields

The Faddeev-Popov approach to make the generating functional corresponding to free gluon fields well defined, introduces two independent Grassmann fields. Since these are scalar, their quanta can be ...
Tjommen's user avatar
  • 311
3 votes
2 answers
556 views

BRST Symmetry and Single Particle States

I am studying about BRST symmetry from the book of P&S (Peskin's and Schroeder's "An Introduction to QFT", Chapter 16.4). The authors construct a nilpotent charge operator and then they ...
schris38's user avatar
  • 3,992
2 votes
1 answer
251 views

Applying the Optical Theorem in Non-Abelian Gauge Theories

I am reading P&S (Peskin's and Schroeder's book on QFT), Chapter 16.3 entitled Ghosts and Unitarity. The authors employ the optical theorem to calculate the imaginary part of a $f\bar{f}\...
schris38's user avatar
  • 3,992
3 votes
1 answer
504 views

How does the BRST transformation act on ghost fields?

I understand the general idea behind constructing the BRST symmetry: take a generic gauge transformation $$\begin{equation} e^\omega, \end{equation}\tag{1}$$ where $\omega$ is Lie-algebra valued, and ...
y9QQ's user avatar
  • 71
1 vote
0 answers
73 views

Is there still a Gribov ambiguity when the Faddeev-Popov determinant is treated without ghosts?

In this document (Gribov Ambiguity by Thitipat Sainapha) the setup leading to the equation $3.77$ seems to strongly depend on the treatment of the Faddeev-Popov determinants with ghosts. Indeed the ...
Jeanbaptiste Roux's user avatar
2 votes
1 answer
121 views

Do Faddeev-Popov ghost contribute to vacuum polarisation?

I can imagine how one can draw a Feynman diagram for a boson self-energy with a ghost loop. My question is, shouldnt't the amplitude of that process be 0 as the ghosts are merely a mathematical tool?
pablo bilbao's user avatar
5 votes
4 answers
504 views

Gauge ghosts & unphysical states in gauge theory

I have a general question about a statement from Wikipedia about ghost states as occuring in gauge theory: "In the terminology of quantum field theory, a ghost, ghost field, or gauge ghost is an ...
user267839's user avatar
  • 1,395
7 votes
1 answer
819 views

Why can't Faddeev-Popov ghosts be replaced with bosons?

Faddeev-Popov ghosts are introduced in the quantization of Yang-Mills theory to absorb the Faddeev-Popov determinant into the action, $$\det \Delta_{\text{FP}} = \int \mathcal{D} \bar{c} \mathcal{D} c ...
knzhou's user avatar
  • 103k
9 votes
2 answers
1k views

Why don't high-energy experimentalists ever include Faddeev-Popov ghosts in their Feynman diagrams?

To correctly calculate scattering amplitudes in nonabelian gauge theory, one must include Feynman diagrams with internal Faddeev-Popov ghosts (fictitious fermionic scalars that only appear internally ...
tparker's user avatar
  • 48.4k
2 votes
3 answers
829 views

How to prove that Faddeev-Popov ghosts are unnecessary for Yang-Mills theory with axial gauge?

In the book it says that in Yang-Mills theory with axial gauge: $n_{\mu}A^{\mu}=0$ using Faddeev-Popov ghosts are needless. Does anyone know how to prove this?
user avatar
1 vote
1 answer
272 views

Anti-ghost translation invariance$.$

The Faddeev-Popov gauge-fixed Yang-Mills Lagrangian is invariant under $$ \bar c\to\bar c+\chi $$ for any odd constant $\chi$. What is the physical interpretation of this invariance? What does this ...
AccidentalFourierTransform's user avatar
5 votes
1 answer
350 views

How does Faddeev-Popov work for higher-spin fields? (or does it?)

Take for example a spin $2$ field $h_{\mu\nu}$ and some gauge-invariant Lagrangian. Does the Faddeev-Popov trick work here? by work I mean: does it lead to a consistent and unitary theory? is the ...
AccidentalFourierTransform's user avatar

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