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1 vote
1 answer
259 views

Finding the Jacobian of Taylor series of a vector valued function

This question is related to one I asked over on physics stackexchange, but at this point it is purely mathematical in nature and I thought it would make sense to ask here. As the title suggests, I ...
fulis's user avatar
  • 123
2 votes
1 answer
95 views

Solving a linear system in matrix notation

I'm trying to implement the paper "Conformation Constraints for Efficient Viscoelastic Fluid Simulation": https://www.gmrv.es/Publications/2017/BGAO17/SA2017_BGAO.pdf In implementing eqn. 6, they ...
nialltl's user avatar
  • 21
3 votes
1 answer
150 views

Divergence of tensor times vector equals divergence of vector times tensor

Does the following equation hold? $\vec T := \vec T(\vec x)$ is a tensor field, $\vec v := \vec v(\vec x)$ a vector field: $\text{div} \vec T \cdot \vec a = \text{div}(\vec a \cdot \vec T)$ I think ...
Alduno's user avatar
  • 193
1 vote
1 answer
1k views

If the derivative of tensors are not generally tensors, why does vector calculus work?

There's this chart on Wikipedia (source: https://en.wikipedia.org/wiki/Matrix_calculus) Suppose I have the function $$f(x,y) = x^2y^3$$ and I compute the gradient $$\nabla f(x,y) = (2xy^3,3x^2y^...
Stan Shunpike's user avatar
1 vote
2 answers
670 views

divergence of gradient of scalar function in tensor form

I found simple expression in tensor notation for a divergence of product vector and gradient of scalar function: $$\operatorname{div}(\mathbf{j}) = 0 \text{, where } \mathbf{j} = \mathbf{m}\times \...
DJNZ's user avatar
  • 29
1 vote
1 answer
163 views

Tensor chain rule reference request

I am a Maths major student. Question: Given a function $f:\mathbb{R}^2\to\mathbb{R},$ $g:\mathbb{R}^2\to\mathbb{R}^2$ and $(a_1,a_2)\in \mathbb{N}^2.$ Assume that $f$ and $g$ are infinitely ...
Idonknow's user avatar
  • 15.9k
0 votes
1 answer
300 views

Tensor form of $\nabla \times (\phi \vec{V})$

So i'm given to find the tensor/index notation of this Vector identity: (1) $\nabla\times(\phi{V})=\phi(\nabla\times\vec{V})-\vec{V}\times(\nabla\phi)$ would this just be $$=\partial_i\epsilon_{ijk}...
UnderGrad1993's user avatar
0 votes
0 answers
41 views

Two questions about vector equations

Q1. How to write the following equation in a form of $\vec{a}= something$? From the question posted in Physics SE, I found the following process is wrong. For any $ \vec{v}\ne\vec{0}$ $$ \vec{v}\...
SOQEH's user avatar
  • 45
0 votes
1 answer
78 views

Inverse for a sum of two matrices

What is the inverse of the 3x3 matrix $(\vec{a} \vec{a}+cI)^{-1}$ Where $\vec{a} \vec{a} $ is a dyad and $I$ is the identity matrix, $c$ is constant, $\vec{a}=(a_1,a_2,a_3)$ is a 3x1 vector $\vec{a}...
user591849's user avatar
4 votes
0 answers
101 views

What is a neat way to solve $\nabla\mathbf{u}+\nabla\mathbf{u}^T=\mathbf{\mathbf{C}}$?

Let $\mathbf{u}:\mathbb{R}^3\to\mathbb{R}^3$ be a smooth enough vector field that satisfies the following equation $$\nabla\mathbf{u}+\nabla\mathbf{u}^T=\mathbf{C},\tag{1}$$ where $\nabla\mathbf{u}$ ...
Hosein Rahnama's user avatar
1 vote
2 answers
1k views

Time derivative of scalar function that takes vector as argument

Let's say I have scalar function $\phi$ that is function of some vectors $\vec{\bf{p}}$ and $\vec{\bf{r}}$ such that $\phi = \phi(\vec{\bf{p}}-\vec{\bf{r}})$, also vector $\bf{r}$ is function of time, ...
MrVragilije's user avatar
6 votes
2 answers
8k views

Formula of the gradient of vector dot product

On Wikipedia in the article "Vector calculus identities" (https://en.m.wikipedia.org/wiki/Vector_calculus_identities) there are the following two formulas for computing the gradient of vector dot ...
Tanya's user avatar
  • 61
1 vote
1 answer
249 views

Proving zero identities in vector calculus with simple arguments involving index counting or symmetry?

Consider the following table describing four second derivative operators. ...
user avatar
1 vote
1 answer
1k views

Divergence of a dot product of tensor and vector

Hei, I am trying to derive energy equation from Navier-Stokes equation and I come across this: $$\nabla.(\sigma.v)=(\nabla.\sigma).v +\sigma:\nabla v$$ $\sigma $ is the stress tensor V :is the ...
F.O's user avatar
  • 323
2 votes
0 answers
445 views

Show that the derivative of a second order tensor gives a third order tensor

Let $U_{i,j}$ be a second order tensor. Show that $\frac{\partial U_{i,j}}{\partial x_{k}}$ is a third order tensor. I know how to prove that the gradient of a scalar field (which is a tensor of ...
julix's user avatar
  • 21

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