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3
questions
2
votes
2
answers
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Derivation or intuition on the covariant derivative for higher rank tensors
So the derivation in my textbook for the covariant derivative of a vector field $\vec{u}$ in curvilinear coordinates $\xi^k$ is the following:
$$\frac{\partial \vec{u}}{\partial\xi^j}=\frac{\partial (...
- 379
0
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1
answer
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Matrix differential equation set to zero
I have a bijective continuous function $f$, which maps an $(n\times1)$ dimensional column vector $t=[t_1,...t_n]'$ to another $(n\times1)$ dimensional column vector $f(t)=[f_1(t),...f_n(t)]'$. I ...
- 766
1
vote
2
answers
969
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How do I calculate numerically a tensor in polar coordinates?
You can formulate the question also like this: What is the easiest way of calculating directed derivative of a function if its values are evaluated in a cartesian grid?
a) fit a (spline) surface, ...
- 111