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2 votes
1 answer
67 views

Differential surface element and nabla operator

If we have the vector field $\vec{u}=\vec{A}\times \vec{v}$, where $\vec{A}=\text{const.}$ and we integrate over some closed curve, by using Stokes' theorem we get: $$ \begin{align} \oint_{\partial S}...
Krum Kutsarov's user avatar
0 votes
0 answers
120 views

How do I simplify $\delta_{ij} \delta^{jk}$?

How do I simplify $\delta_{ij} \delta^{jk}$? I know that $\delta_{ij} \delta_{jk}=\delta_{ik}$, but what do I do if the there's a Kronecker Delta symbol with upper indices and one with lower indices?
math's user avatar
  • 93
0 votes
0 answers
34 views

Can you define a tensor by integrating one vector with respect to another?

I was reading this question, simply I was wondering about integrating a vector with respect to another vector field. In the question, the OP asks if the following quantity has any sensible meaning: $$\...
FizzKicks's user avatar
  • 211
0 votes
2 answers
236 views

Power of a second-order tensor

I have the following equation: $$ \dfrac{\mathbf{V}^T \cdot \mathbf{V}}{\mathbf{V}^T : \mathbf{V}} + \dfrac{\mathbf{V} \cdot \mathbf{V}^T}{\mathbf{V} : \mathbf{V}^T} = \dfrac{\mathbf{D}^2}{\left \| \...
user avatar
0 votes
1 answer
379 views

$C_{ij}=T_{ijklmn} D_{kl} D_{mn}$ where $T_{ijklmn}$ is a rank 6 isotropic tensor, $C_{ij}$ is symmetric and $D_{ij}$ is antisymmetric

I was doing a question on Tensors and hit a roadblock The Question: Suppose that $C_{ij}$ and $D_{ij}$ satisfy the quadratic relationship $C_{ij} = T_{ijklmn} D_{kl}D_{mn}$, where $T_{ijklmn}$ is an ...
Swapna's user avatar
  • 23
1 vote
1 answer
1k views

How should I calculate fourth order tensor times second order tensor?

Let's say I have two second-order tensors ${\mathbf{S}} = {S_{ij}}{{\mathbf{e}}_i} \otimes {{\mathbf{e}}_j}$ and ${\mathbf{T}} = {T_{ij}}{{\mathbf{e}}_i} \otimes {{\mathbf{e}}_j}$ . Then, I know ${\...
ENHorse's user avatar
  • 11
0 votes
1 answer
119 views

Index notation: associative property

I have given the following term, that I can write in index notation as following: $$ (\mathbf{a} \cdot \nabla)\mathbf{b} = a_j \partial_j b_i$$ Now I can exchange the order and get $$ \partial_j b_i ...
Phobos's user avatar
  • 163
0 votes
0 answers
41 views

Two questions about vector equations

Q1. How to write the following equation in a form of $\vec{a}= something$? From the question posted in Physics SE, I found the following process is wrong. For any $ \vec{v}\ne\vec{0}$ $$ \vec{v}\...
SOQEH's user avatar
  • 45
0 votes
0 answers
50 views

How would you express $(\underline{a} \times \underline{b}) \times (\underline{a} \times \underline{c})$ in index notation?

At a guess, I would have said that the answer is $\varepsilon_{ijk}\varepsilon_{jlm}a_{l}b_{m}\varepsilon_{kpq}a_{p}c_{q}$, but I'm guessing that this is incorrect. What is the corrdct expression? ...
M Smith's user avatar
  • 2,737
4 votes
1 answer
10k views

Divergence of stress tensor in momentum transfer equation

Let suppose that we work in a 2D cartesian coordinates. what will be x and y components of $\nabla.\left[-p I+\mu \left(\nabla \text{u}+(\nabla \text{u})^T\right)-\frac{2}{3} \mu (\nabla.\text{u}) I \...
Ghartal's user avatar
  • 4,358