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0 votes
1 answer
82 views

How to prove that $\sin\left(\frac{\pi}{2n}\right)\sum_{k=1}^{n}\sin\left(\frac{2k-1}{2n}\pi\right)=1$? [closed]

How to prove that $$\sin\left(\frac{\pi}{2n}\right)\sum_{k=1}^{n}\sin\left(\frac{2k-1}{2n}\pi\right)=1$$ ?
El Mismo Sol's user avatar
1 vote
0 answers
58 views

Deduce that $\sum_{n=1}^\infty\frac{1}{1+n^2}=\frac{1}{2}(\pi\coth\pi-1)\quad$ [duplicate]

I am having problems showing that $$\sum_{n=1}^\infty\frac{1}{1+n^2}=\frac{1}{2}(\pi\coth\pi-1)\quad $$ Here's my attept to this point: I tried to express each term using a partial fraction ...
Bagaringa's user avatar
  • 402
0 votes
0 answers
32 views

$\sum_{k=1}^{2m+1}\cos\left(\frac{2k\pi-\operatorname{cos^{-1}}(x)}{2m+1}\right)^n$ - $n$th power of the root of a polynomial of odd degree

Context I started with the following (very common) problem: Given this polynomial $p(x)$, calculate the sum/the sum of the squares/of the cubes of the roots" So I wanted to see if I could find ...
Math Attack's user avatar
1 vote
1 answer
36 views

Summation of infinite cos series and determining theta

Question: In the figure, $A_0A_1,A_2A_3,A_4A_3...$ are all perpendicular to $L_1$ ​ $A_1A_2,A_3A_4,A_5A_6...$ ​ are all perpendicular to $L_2$ ​If $A_0A_1=1$ ​And $A_0A_1+A_1A_2+A_2A_3+A_3A_4......\...
Shivansh Tiwari's user avatar
1 vote
0 answers
98 views

Restructuring Jacobi-Anger Expansion

In Jacobi-Anger expansion, $$e^{\iota z \sin(\theta)}$$ can be written as: $$e^{\iota z \sin(\theta)} = \sum_{n=-\infty}^{\infty} J_n(z)e^{\iota n \theta}$$ where $J_n(z)$ is the Bessel function of ...
SiPh's user avatar
  • 31
1 vote
1 answer
170 views

How to derive the sum $ \sum_{k=1}^{n-1} \frac{1}{\cosh^2\left(\frac{\pi k}{n}\right)}$

\begin{align*} \sum_{k=1}^{n-1} \frac{1}{\cosh^2\left(\frac{\pi k}{n}\right)}\end{align*} I tried to solve with mathematica that shows Does anyone know how to derive this and does it is possible for ...
Mods And Staff Are Not Fair's user avatar
8 votes
1 answer
250 views

Compute $\sum^{2024}_{k=1} \frac{2023-2022 \cos \left(\frac{\pi(2k-1)}{2024} \right)}{2021-2020 \cos \left(\frac{\pi(2k-1)}{2024} \right)}$

Question: Compute $$\sum^{2024}_{k=1} \frac{2023-2022 \cos \left(\frac{\pi(2k-1)}{2024} \right)}{2021-2020 \cos \left(\frac{\pi(2k-1)}{2024} \right)}$$ I began by rearranging the sum as follows: $$\...
Indecisive's user avatar
0 votes
1 answer
84 views

If $\sum_{r=1}^5 cos(rx)=5$ find the number solutions it has in $[0,2\pi]$

if $$\sum_{r=1}^5 \cos(rx)=5$$ then find the number of solutions it has in $[0,2\pi]$. I've tried two different methods to find the solution(s), but both of which are proving to be very lengthy. ...
math and physics forever's user avatar
6 votes
2 answers
296 views

How do we prove that :$\tan^2(10)+\tan^2(50)+\tan^2(70) =9$

Prove : $\tan^2(10) + \tan^2(50) + \tan^2(70) =9$ my attempt Let $\text{t} :=\tan(10)$ $$\tan^2(10) + \tan^2(50) + \tan^2(70) = \tan^2(10) + \tan^2(60-10) + \tan^2(60+10)=t^2 + \left({\frac{\sqrt{...
Mostafa's user avatar
  • 2,288
4 votes
0 answers
87 views

How deduce $\prod_{k=1}^{(n-1)/2} \sin^2 \frac{k\pi}{n} =\frac{n}{2^{n-1}}$ from $\prod_{k=1}^{n-1} \sin \frac{k\pi}{n} =\frac{n}{2^{n-1}}$?

I know that $\displaystyle\prod_{k=1}^{n-1} \sin \frac{k\pi}{n} =\frac{n}{2^{n-1}}$ for any integer $n \geq 1$ is true. Now, suppose that $n$ is odd, how show $$ \prod_{k=1}^{(n-1)/2} \sin^2 \frac{k\...
Liam's user avatar
  • 323
4 votes
0 answers
135 views

Simplify a summation in the solution of $\displaystyle\int_{0}^{\infty}e^{-cx}x^{n}\arctan(ax)\mathrm{d}x$

Context I calculated this integral: $$\begin{array}{l} \displaystyle\int_{0}^{\infty}e^{-cx}x^{n}\arctan(ax)\mathrm{d}x=\\ \displaystyle\frac{n!}{c^{n+1}}\left\lbrace\sum_{k=0}^{n}\left[\text{Ci}\left(...
Math Attack's user avatar
16 votes
2 answers
666 views

Simplifying $3S_1 + 2S_2 + 2S_3$, where $S_1=2\sum_{k=0}^n16^k\tan^4{2^kx}$, $S_2=4\sum_{k=0}^n16^k\tan^2{2^kx}$, $S_3=\sum_{k=0}^n16^k$

If $$S_1=2\sum_{k=0}^n 16^k \tan^4 {2^k x} $$ $$S_2=4\sum_{k=0}^n 16^k \tan^2 {2^k x} $$ $$S_3= \sum_{k=0}^n 16^k $$ Find $(3S_1 + 2S_2 + 2S_3)$ as a function of $x$ and $n.$ In the expression asked ...
Maths's user avatar
  • 491
3 votes
1 answer
214 views

Sum with Binomial Coefficients and Sine; $S=\sum_{k=0}^n \binom{n}{k} \sin(kx)$

Sum with Binomial Coefficients Let $n ∈ ℕ₀$ and $x ∈ ℝ$. $$S=\sum_{k=0}^n \binom{n}{k} \sin(kx)$$ Simplify the sum to a polynomial in n. I tried to use Euler's Formula and the Binomial Theorem, ...
Julian P's user avatar
10 votes
1 answer
389 views

Is there an identity for $\sum_{k=0}^{n-1}\csc(w+ k \frac{\pi}{n})\csc(x+ k \frac{\pi}{n})\csc(y+ k \frac{\pi}{n})\csc(z+ k \frac{\pi}{n})$?

What I'd like to find is an identity for $$\sum_{k=0}^{n-1}\csc\left(w+ k \frac{\pi}{n}\right)\csc\left(x+ k \frac{\pi}{n}\right)\csc\left(y+ k \frac{\pi}{n}\right)\csc\left(z+ k \frac{\pi}{n}\right)$$...
onepound's user avatar
  • 1,379
3 votes
1 answer
90 views

Closed form for $\sum_{n=1}^{\infty}\frac{(2\log\phi)^{2n+3}B_{2n}}{2n(2n+3)!}$

I need a closed form for the sum $$\sum_{n=1}^{\infty}\frac{(2\log\phi)^{2n+3}B_{2n}}{2n(2n+3)!} $$ where $\phi=\frac{1+\sqrt{5}}{2}$ is the golden ratio and $B_n$ are the Bernoulli numbers. I tried ...
Max's user avatar
  • 840

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