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1 vote
1 answer
36 views

Summation of infinite cos series and determining theta

Question: In the figure, $A_0A_1,A_2A_3,A_4A_3...$ are all perpendicular to $L_1$ ​ $A_1A_2,A_3A_4,A_5A_6...$ ​ are all perpendicular to $L_2$ ​If $A_0A_1=1$ ​And $A_0A_1+A_1A_2+A_2A_3+A_3A_4......\...
Shivansh Tiwari's user avatar
8 votes
2 answers
166 views

Given $\varphi$ is golden ratio, how do I prove this $\sum \limits_{j=1}^{\infty}\frac{(1-\varphi)^j}{j^2}\cos{\frac{3j\pi}{5}}=\frac{\pi^2}{100}$?

Given $ \varphi$ is golden ratio, how do I prove this: $ \displaystyle \tag*{}\sum \limits_{j=1}^{\infty}\frac{(1-\varphi)^j}{j^2}\cos{\frac{3j\pi}{5}}=\frac{\pi^2}{100}$ My approach: We can reduce ...
user avatar
3 votes
1 answer
203 views

How do I simplify this sum of arccosines?

After trying to solve a geometry problem, represented by the following image I've arrived at this expression: $\alpha=\arccos\left(\frac{d+r \cos \left(\varphi+\frac{\vartheta}2\right)}{\sqrt{d^2+r^2+...
WordP's user avatar
  • 507
2 votes
2 answers
1k views

Proving $\sum_{k=0}^{n-1} \text{cos}\left(\frac{2\pi k}{n} \right) = \sum_{k=0}^{n-1} \text{sin}\left(\frac{2\pi k}{n} \right) = 0$ [duplicate]

I would like to prove the following, $$\sum_{k=0}^{n-1} \text{cos}\left(\frac{2\pi k}{n} \right) = \sum_{k=0}^{n-1} \text{sin}\left(\frac{2\pi k}{n} \right) = 0$$ This is equivalent to showing that if ...
user avatar
1 vote
1 answer
148 views

Geometry formulas, how to show identities.

Given $d$ is integer: How do I show: $$\frac{1}{(e^{\frac{2i\pi p}{d}}-1)}=\frac{-i}{2\tan(\frac{\pi p}{d})}-\frac{1}{2}$$ How do I rewrite and show, for $k$ is an integer: $$ \sum_{p=1}^{d-1}\frac{\...
Gerben's user avatar
  • 593
47 votes
1 answer
2k views

Why does this ratio of sums of square roots equal $1+\sqrt2+\sqrt{4+2\sqrt2}=\cot\frac\pi{16}$ for any natural number $n$?

Why is the following function $f(n)$ constant for any natural number $n$? $$f(n)=\frac{\sum_{k=1}^{n^2+2n}\sqrt{\sqrt{2n+2}+{\sqrt{n+1+\sqrt k}}}}{\sum_{k=1}^{n^2+2n}\sqrt{\sqrt{2n+2}-{\sqrt{n+1+\...
mathlove's user avatar
  • 144k