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29 votes
1 answer
60k views

Can we express sum of products as product of sums?

I've got an expression which is sum of products like: $$a_1 a_2 + b_1 b_2 + c_1 c_2 + \cdots,$$ but the real problem I'm solving could be easily solved if I could convert this expression into ...
lavee_singh's user avatar
28 votes
2 answers
15k views

How to interchange a sum and a product?

I have this expression: $$\sum_{\{\vec{S}\}}\prod_{i=1}^{N}e^{\beta HS_{i}}=\prod_{i=1}^{N}\sum_{S_{i}\in\{-1,1\}}e^{\beta HS_{i}} \qquad (1)$$ Where $\sum_{\{\vec{S}\}}$ means a sum over all possible ...
Ana S. H.'s user avatar
  • 943
26 votes
1 answer
860 views

Is this algebraic identity obvious? $\sum_{i=1}^n \prod_{j\neq i} {\lambda_j\over \lambda_j-\lambda_i}=1$

If $\lambda_1,\dots,\lambda_n$ are distinct positive real numbers, then $$\sum_{i=1}^n \prod_{j\neq i} {\lambda_j\over \lambda_j-\lambda_i}=1.$$ This identity follows from a probability calculation ...
user avatar
17 votes
2 answers
862 views

proof of $\sum\nolimits_{i = 1}^{n } {\prod\nolimits_{\substack{j = 1\\j \ne i}}^{n } {\frac{{x_i }}{{x_i - x_j }}} } = 1$ [duplicate]

i found a equation that holds for any natural number of n and any $x_i \ne x_j$ as follows: $$\sum\limits_{i = 1}^{n } {\prod\limits_{\substack{j = 1\\j \ne i}}^{n } {\frac{{x_i }}{{x_i - x_j }}} } ...
Heejin Joung's user avatar
12 votes
1 answer
588 views

New Year Maths 2015

In the spirit of the festive period and in appreciation of the encouraging response to my Xmas Combinatorics 2014 problem posted recently, here's one for the New Year! Express the following as a ...
Hypergeometricx's user avatar
12 votes
1 answer
885 views

Showing $\sum\limits^N_{n=1}\left(\prod\limits_{i=1}^n b_i \right)^\frac1{n}\le\sum\limits^N_{n=1}\left(\prod\limits_{i=1}^n a_i \right)^\frac1{n}$?

If $a_1\ge a_2 \ge a_3 \ldots $ and if $b_1,b_2,b_3\ldots$ is any rearrangement of the sequence $a_1,a_2,a_3\ldots$ then for each $N=1,2,3\ldots$ one has $$\sum^N_{n=1}\left(\prod_{i=1}^n b_i \right)^...
Henry B.'s user avatar
  • 2,048
11 votes
2 answers
387 views

Prove $\sum_{k=0}^n \binom{n}{k}(-1)^k \frac{x}{x+k} = \prod_{k=1}^n \frac{k}{x+k}$ and more

The current issue (vol. 120, no. 6) of the American Mathematical Monthly has a proof by probabilistic means that $$\sum_{k=0}^n \binom{n}{k}(-1)^k \frac{x}{x+k} = \prod_{k=1}^n \frac{k}{x+k} $$ for ...
marty cohen's user avatar
11 votes
0 answers
241 views

Are $(2,28)$ and $(5,3207)$ the only solutions $(m,n)\in\mathbb{N}^2$?

I noticed something as I was playing around with prime numbers. By denoting $p_i$ the $i^{\text{th}}$ prime number, I discovered the following: $$ \begin{align}\prod_{i=1}^2\left(p_i^{ \ 2}+i\right)&...
Mr Pie's user avatar
  • 9,487
10 votes
1 answer
717 views

Product of Sines and Sums of Squares of Tangents

There is a nice formula for products of cosines, found by multiplying by the complementary products of sines and using the double angle sine formula (as I asked in my question here): $$\prod_{k=1}^n \...
D.R.'s user avatar
  • 8,945
10 votes
4 answers
370 views

Geometry problem boils down to finding a closed form for $\sum_{n=1}^{k}{\arctan{\left(\frac{1}{n}\right)}}$

I was solving the following problem: "Find $\angle A + \angle B + \angle C$ in the figure below, assuming the three shapes are squares." And I found a beautiful one-liner using complex numbers: $(1+...
Shrey Joshi's user avatar
10 votes
1 answer
508 views

Why is this sum equal to $0$?

While solving a differential equation problem involving power series, I stumbled upon a sum (below) that seemed to be always equal to $0$, for any positive integer $s$. $$ \sum_{k=0}^s \left( \frac{ \...
JungHwan Min's user avatar
10 votes
1 answer
476 views

If integration is a continuous analog of summation (Addition), what is the continuous analog of multiplication (Product)?

One definition of integration over a continuous interval [a,b] into n subintervals with equal width $\Delta x$, and from each interval choose a point $x_i^*$. Then the definite integral of $f(x)$ ...
Sam Castillo's user avatar
9 votes
3 answers
487 views

Question about Euler's approach to find $\sum_{n=1}^\infty\frac1{n^2}=\frac{\pi^2}6$

For a freshman calculus project, I used Euler's approach to find $\sum_{n=1}^\infty\frac1{n^2}=\frac{\pi^2}6$, and noted from Wikipedia's explanation that the infinite product representation of $\frac{...
user99980's user avatar
  • 265
8 votes
4 answers
21k views

Change from product to sum

We know that : $$a \times b = \underbrace{a + a + a + ... + a}_{\text{b times}}$$ That's how we convert from a product to a sum. So what happens if we go a little further? That is : $$\prod\limits_{a}^...
NeilRoy's user avatar
  • 2,221
8 votes
2 answers
373 views

Showing an indentity with a cyclic sum

Let $n\geqslant2$, and $k\in \mathbb{N}$ Let $z_1,z_2,..,z_n$ be distinct complex numbers Prove that $$ \sum_{i=1}^{n}\frac {{z}_{i}^{n-1+k}} { \prod \limits_{\substack{j = 1\\j \ne i}}^{ n }{ (z_i-...
Gabriel Romon's user avatar
8 votes
1 answer
467 views

Identity in Number Theory Paper

In this paper by Jerry Hu, he defines the function $$f_{s,k,i}\left(u\right)=\prod_{p\mid u} \left(1-\frac{\sum_{m=i}^{k-1}{s \choose m}\left(p-1\right)^{k-1-m}}{\sum_{m=0}^{k-1}{s \choose m}\left(p-...
Brian's user avatar
  • 2,155
8 votes
0 answers
258 views

Help me to get deeper understanding of Euler's proof of his Arithmetical Theorem

With distinct numbers $a_1, a_2, \ldots, a_n$, let's denote the products of the differences of each of these numbers with the each of the rest of them by the following principle: \begin{align} (...
Rusurano's user avatar
  • 848
7 votes
1 answer
365 views

How to prove the following discovery of Euler?

There exists a series of formulas. \begin{align*} \ & \dfrac{1}{(a-b)(a-c)}+\dfrac{1}{(b-a)(b-c)}+\dfrac{1}{(c-a)(c-b)} = 0, \\ \ & \dfrac{a}{(a-b)(a-c)}+\dfrac{b}{(b-a)(b-c)}+\dfrac{c}...
Rusurano's user avatar
  • 848
7 votes
3 answers
1k views

Summation series ($\Sigma$) is to Integral ($\int$)... as Product series ($\Pi$) is to ??

If a Summation series ($\Sigma$) is to an Integral ($\int$)... is there a corresponding concept for a Product series ($\Pi$)? Summation series ($\Sigma$) is to Integral ($\int$)... as Product series (...
Charles Richards's user avatar
7 votes
2 answers
200 views

Elementary proof of "generalized reverse Bernoulli inequality"

I've stumbled upon the following exercise in an early chapter of an analysis textbook: Let $a_n$ be a finite, nonnegative sequence such that $\sum_{i=0}^n a_i\le 1$. Prove $$ \prod_{i=1}^n (1 + a_i) \...
univalence's user avatar
6 votes
2 answers
359 views

Simplify $\prod_{k=1}^5\tan\frac{k\pi}{11}$ and $\sum_{k=1}^5\tan^2\frac{k\pi}{11}$

My question is: If $\tan\frac{\pi}{11}\cdot \tan\frac{2\pi}{11}\cdot \tan\frac{3\pi}{11}\cdot \tan\frac{4\pi}{11}\cdot \tan\frac{5\pi}{11} = X$ and $\tan^2\frac{\pi}{11}+\tan^2\frac{2\pi}{11}+\tan^2\...
Pratyush's user avatar
  • 2,586
6 votes
2 answers
144 views

Combinatorics Problem on proving that a particular sum is 0

I'm having some issues with proving that the following sum is $0$ for any value of $n \geq 2$: $$ \sum_{j=1}^{n} \frac{1}{\prod_{i=1,i\neq j}^{n}(a_{j}-a_{i})} $$ where the $a_i$ are non-zero and ...
Joshua's user avatar
  • 63
6 votes
2 answers
199 views

Calculate $\sum_{i = 0}^{n}\ln\binom{n}{i}\Big/n^2$

Calculate $$\sum_{i = 0}^{n}\ln\binom{n}{i}\Big/n^2$$ I can only bound it as follows: $$\binom{n}{i}<\left(\dfrac{n\cdot e}{k}\right)^k$$ $$\sum_{i = 0}^{n}\ln\binom{n}{i}\Big/n^2<\dfrac{1}{n}\...
Colliot's user avatar
  • 884
6 votes
0 answers
97 views

Prove that if $x_{1}x_{2}...x_{n}=1$ then $\frac{1}{1+x_{1}+x_{1}x_{2}}+...+\frac{1}{1+x_{n-1}+x_{n-1}x_{n}}+\frac{1}{1 +x_{n}+x_{n}x_{1}}\ge 1$ [duplicate]

Prove that if $x_{1}x_{2}...x_{n}=1$ then $\frac{1}{1+x_{1}+x_{1}x_{2}}+...+\frac{1}{1+x_{n-1}+x_{n-1}x_{n}}+\frac{1}{1 +x_{n}+x_{n}x_{1}}\ge 1$. $x_{1},x_{2},...,x_{n}$ are positive real numbers, and ...
nowepas's user avatar
  • 288
5 votes
4 answers
485 views

Big Greeks and commutation

Does a sum or product symbol, $\Sigma$ or $\Pi$, imply an ordering? Clearly if $\mathbf{x}_i$ is a matrix then: $$\prod_{i=0}^{n} \mathbf{x}_i$$ depends on the order of the multiplication. But, ...
Lucas's user avatar
  • 1,489
5 votes
3 answers
3k views

swap summation and multiple

In which case can we swap summation and multiple? ie. $$\sum_{i=1}^n\prod_{j=1}^na_{ij}=\prod_{j=1}^n\sum_{i=1}^na_{ij}$$ if we can't swap like this, please tell me how can we swap them?
maple's user avatar
  • 2,883
5 votes
2 answers
151 views

An equality between a product and a combinatorial sum

I'm trying to prove the following identity (of which I numerically verified the truth) : $$\text{For every $n\in\mathbb{N}^*$ and $\alpha \in \mathbb{R}\setminus\lbrace-2k\text{ }|\text{ }k\in\mathbb{...
Harmonic Sun's user avatar
  • 1,984
5 votes
3 answers
195 views

Prove that $\frac{\sqrt[n]{\prod_{k = 1}^nx_n}}{m} \ge n - 1$ where $\sum_{k = 1}^n\frac{1}{x_k + m} = \frac{1}{m}$.

Given positives $x_1, x_2, \cdots, x_{n - 1}, x_n$ such that $$\large \sum_{k = 1}^n\frac{1}{x_k + m} = \frac{1}{m}$$. Prove that $$\large \frac{\displaystyle \sqrt[n]{\prod_{k = 1}^nx_n}}{m} \ge n - ...
Lê Thành Đạt's user avatar
5 votes
1 answer
1k views

Sum operator precedence

I'm trying to read some simple equations and in order to interpret them in the right way I need to know $\sum$ and $\prod $ operator range/precedence. $$ \sum p(s, a) +\gamma $$ is equal to $\sum(p(...
Most Wanted's user avatar
5 votes
1 answer
225 views

Proving $(1+\frac 1n)^{n} = 1 + \sum_{k=1}^n({\frac 1{k!}\prod_{r=0}^{k-1}(1-\frac rn))}$ using the binomial theorem

$$\left(1+\frac 1n\right)^{n} = 1 + \sum\limits_{k=1}^n \left\{\frac 1{k!}\prod_{r=0}^{k-1}\left(1-\frac rn\right)\right\}$$ this exercise is taken from Apostol's Calculus I (page 45) and it's ...
Bog's user avatar
  • 135
5 votes
1 answer
320 views

Operators - sums, products, exponents, etc.

$(x + x + \cdots + x)$, where $x$ added $n$ times can be written as $x * n$. $(x * x * \cdots * x)$, where $x$ multiplied $n$ times can be written as $x ^ n$. Is there an operator, such that if $x^{...
ctype.h's user avatar
  • 711
5 votes
2 answers
169 views

Prove that $\sum_{k=1}^n\frac{\prod_{1\leq r\leq n, r\neq m}(x+k-r)}{\prod_{1\leq r\leq n, r\neq k}(k-r)}=1$

For arbitrary $x$ and $1\leqslant m\leqslant n$, prove the following: $$\sum_{k=1}^n\frac{\prod_{1\leq r\leq n, r\neq m}(x+k-r)}{\prod_{1\leq r\leq n, r\neq k}(k-r)}=1$$ I'm looking for a proof that ...
Rusurano's user avatar
  • 848
5 votes
1 answer
468 views

Average weighted by inverse distance to median equal to median?

Problem Statement I have a set of $N$ ordered elements such that $x = \{x_1, x_2, ..., x_q, x_p, ..., x_N\}$ where $x_q \le x_m \le x_p$ and $x_m$ is the median of the set $x$. I define a particular ...
zephyr's user avatar
  • 205
5 votes
1 answer
156 views

Permutations of Independent Probabilities

Problem: Say that I have a list of $n$ tasks to complete. Each of the tasks have independent probabilities $p_1, p_2, ..., p_n$ of completing that task. There is a particular task on the list that I ...
Skylar Reede's user avatar
4 votes
2 answers
272 views

Sum of positive elements divided by their "weighted" product - inequality

I have following expression, $$ \frac{\sum_{i=1}^n x_i}{\prod_{i=1}^nx_i^{p_i}} $$ where $p_i$s satisfy $\sum p_i = 1$ and $p_i \in [0,1]$ and $x_i\geq0$, $\forall i \in 1\dots n$. I think that ...
Michael Mark's user avatar
4 votes
3 answers
867 views

Finding $\frac{\sum_{r=1}^8 \tan^2(r\pi/17)}{\prod_{r=1}^8 \tan^2(r\pi/17)}$

I have tried to wrap my head around this for some time now, and quite frankly I am stuck. Given is that : $$a=\sum_{r=1}^8 \tan^2\left(\frac{r\pi}{17}\right) \qquad\qquad b=\prod_{r=1}^8 \tan^2\left(\...
Mpaparazzi's user avatar
4 votes
2 answers
191 views

sum of an infinite series $\sum_{k=1}^\infty \left( \prod_{m=1}^k\frac{1}{1+m\gamma}\right) $

I am trying to find a closed form expression of $$ \sum_{k=1}^\infty \left( \prod_{m=1}^k\frac{1}{1+m\gamma}\right) $$ where $\gamma>1$. I've been trying this for a long time. Is there an easy way ...
huighlh's user avatar
  • 143
4 votes
2 answers
590 views

Coefficients of $(x-1)(x-2)\cdots(x-k)$

I'm interested in the coefficients of $x$ in the expansion of, $$ (x-1)(x-2)\cdots(x-k) = x^k + P_1(k) x^{k-1} + P_2(k)x^{k-2} + \cdots + P_k(k),$$ Where $k$ is an integer. In particular I am ...
Spencer's user avatar
  • 12.4k
4 votes
2 answers
3k views

Simplifying a Product of Summations

I have, for a fixed and positive even integer $n$, the following product of summations: $\left ( \sum_{i = n-1}^{n-1}i \right )\cdot \left ( \sum_{i = n-3}^{n-1} i \right )\cdot \left ( \sum_{i = n-...
FlamingWilderbeest's user avatar
4 votes
4 answers
305 views

Summation of reciprocal products

When studying summation of reciprocal products I found some interesting patterns. $$\sum_{k=1}^{N} \frac{1}{k\cdot(k+1)}=\frac{1}{1\cdot1!}-\frac{1}{1\cdot(N+1)}$$ $$\sum_{k=1}^{N} \frac{1}{k\cdot(k+1)...
Paul vdVeen's user avatar
4 votes
3 answers
104 views

$Q\le \prod \frac{5+2x}{1+x}\le P$ find $P,Q$

if $x,y,z,$ are positives and $x+y+z=1$ and $$Q\le \prod_{cyc} \frac{5+2x}{1+x}\le P$$ find maximum value of $Q$ and minimum value of $P$ This is actually a question made up myself ,so i don,t know ...
Albus Dumbledore's user avatar
4 votes
1 answer
304 views

Proving $\sum_{k=0}^n\dfrac{x_k^{n+1}}{\prod_{j\neq k}(x_k-x_j)}=\sum_{k=0}^nx_k$

In Problems from the book by Andreescu, there's the following problem : Let $x_0,\ldots,x_n$ be distinct complex numbers. Prove $\displaystyle \sum_{k=0}^n\dfrac{x_k^{n+1}}{\prod_{j\neq k}(...
Gabriel Romon's user avatar
4 votes
3 answers
159 views

Product of sums which equal to sum of product

We can be sure that $$\left(\sum\limits_{k=0}^{n}\frac{1}{k+1}\right)\left(\sum\limits_{k=0}^{n}\binom{n}{k}\frac{(-1)^k}{k+1}\right)= \sum\limits_{k=0}^{n}\binom{n}{k}\frac{(-1)^k}{(k+1)^2}$$ Is ...
user514787's user avatar
  • 1,475
4 votes
2 answers
637 views

Prove $\prod_{k=1}^n(1+a_k)\leq1+2\sum_{k=1}^n a_k$

I want to prove $$\prod_{k=1}^n(1+a_k)\leq1+2\sum_{k=1}^n a_k$$ if $\sum_{k=1}^n a_k\leq1$ and $a_k\in[0,+\infty)$ I have no idea where to start, any advice would be greatly appreciated!
ntm's user avatar
  • 143
4 votes
2 answers
136 views

Show that $k^a=\sum_{m=1}^b\left ( c_m^a\prod_{n\neq m} \frac{k-c_n}{c_m-c_n} \right ).$

I used the following result in another post without providing proof (because I couldn't prove it): $$k^a=\sum_{m=1}^b\left ( c_m^a\prod_{n\neq m} \frac{k-c_n}{c_m-c_n} \right ),$$ where $a$ and $b$ ...
SDiv's user avatar
  • 2,550
4 votes
1 answer
7k views

Can Pi prod be expressed using Sigma Notation?

Can $\prod(x)$ be expressed in terms of $\sum (x)$?
Nick's user avatar
  • 6,834
4 votes
2 answers
82 views

How to define this pattern as $f(n)$

Given a binary table with n bits as follows: $$\begin{array}{cccc|l} 2^{n-1}...&2^2&2^1&2^0&row\\ \hline \\ &0&0&0&1 \\ &0&0&1&2 \\ &0&1&0&...
Manatok's user avatar
  • 265
4 votes
1 answer
88 views

Formulating an alternating sum of product combinations

Consider some list $A=(a_1,a_2,\cdots,a_n)$. I'd like to find a closed form for the following operation. $$f(A)=\sum_{k=1}^n(-1)^{k-1}s_k= s_1-s_2+\cdots(-1)^{n-1}s_n.$$ Where $s_k$ is the sum of all ...
Graviton's user avatar
  • 4,472
4 votes
1 answer
115 views

How can I evaluate the below mentioned series without using a computation software?

I have been trying to evaluate $\displaystyle\sum_{m=0}^{2^{2^5}-1}\frac{2}{\prod_{n=1}^5\bigl((m+2)^{\frac{2}{n}}+(m)^{\frac{2}{n}}\bigr)}$ for quite a long time. I tried various approaches but ...
Arsh's user avatar
  • 121
4 votes
1 answer
1k views

Sum and Product Puzzle and Prime Factors

Suppose we have two number $X$ and $Y,$ such that $1 < X < Y < 100,$ and $X + Y ≤ 100.$ Sue is given $S = X + Y$ and Pete is given $P = XY.$ They then have the following conversation: Pete: '...
MPKenning's user avatar
  • 143

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