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8 votes
1 answer
467 views

Identity in Number Theory Paper

In this paper by Jerry Hu, he defines the function $$f_{s,k,i}\left(u\right)=\prod_{p\mid u} \left(1-\frac{\sum_{m=i}^{k-1}{s \choose m}\left(p-1\right)^{k-1-m}}{\sum_{m=0}^{k-1}{s \choose m}\left(p-...
Brian's user avatar
  • 2,155
8 votes
0 answers
258 views

Help me to get deeper understanding of Euler's proof of his Arithmetical Theorem

With distinct numbers $a_1, a_2, \ldots, a_n$, let's denote the products of the differences of each of these numbers with the each of the rest of them by the following principle: \begin{align} (...
Rusurano's user avatar
  • 848
7 votes
1 answer
365 views

How to prove the following discovery of Euler?

There exists a series of formulas. \begin{align*} \ & \dfrac{1}{(a-b)(a-c)}+\dfrac{1}{(b-a)(b-c)}+\dfrac{1}{(c-a)(c-b)} = 0, \\ \ & \dfrac{a}{(a-b)(a-c)}+\dfrac{b}{(b-a)(b-c)}+\dfrac{c}...
Rusurano's user avatar
  • 848
7 votes
3 answers
1k views

Summation series ($\Sigma$) is to Integral ($\int$)... as Product series ($\Pi$) is to ??

If a Summation series ($\Sigma$) is to an Integral ($\int$)... is there a corresponding concept for a Product series ($\Pi$)? Summation series ($\Sigma$) is to Integral ($\int$)... as Product series (...
Charles Richards's user avatar
7 votes
2 answers
200 views

Elementary proof of "generalized reverse Bernoulli inequality"

I've stumbled upon the following exercise in an early chapter of an analysis textbook: Let $a_n$ be a finite, nonnegative sequence such that $\sum_{i=0}^n a_i\le 1$. Prove $$ \prod_{i=1}^n (1 + a_i) \...
univalence's user avatar
6 votes
2 answers
359 views

Simplify $\prod_{k=1}^5\tan\frac{k\pi}{11}$ and $\sum_{k=1}^5\tan^2\frac{k\pi}{11}$

My question is: If $\tan\frac{\pi}{11}\cdot \tan\frac{2\pi}{11}\cdot \tan\frac{3\pi}{11}\cdot \tan\frac{4\pi}{11}\cdot \tan\frac{5\pi}{11} = X$ and $\tan^2\frac{\pi}{11}+\tan^2\frac{2\pi}{11}+\tan^2\...
Pratyush's user avatar
  • 2,586
6 votes
2 answers
144 views

Combinatorics Problem on proving that a particular sum is 0

I'm having some issues with proving that the following sum is $0$ for any value of $n \geq 2$: $$ \sum_{j=1}^{n} \frac{1}{\prod_{i=1,i\neq j}^{n}(a_{j}-a_{i})} $$ where the $a_i$ are non-zero and ...
Joshua's user avatar
  • 63
6 votes
2 answers
199 views

Calculate $\sum_{i = 0}^{n}\ln\binom{n}{i}\Big/n^2$

Calculate $$\sum_{i = 0}^{n}\ln\binom{n}{i}\Big/n^2$$ I can only bound it as follows: $$\binom{n}{i}<\left(\dfrac{n\cdot e}{k}\right)^k$$ $$\sum_{i = 0}^{n}\ln\binom{n}{i}\Big/n^2<\dfrac{1}{n}\...
Colliot's user avatar
  • 884
6 votes
0 answers
97 views

Prove that if $x_{1}x_{2}...x_{n}=1$ then $\frac{1}{1+x_{1}+x_{1}x_{2}}+...+\frac{1}{1+x_{n-1}+x_{n-1}x_{n}}+\frac{1}{1 +x_{n}+x_{n}x_{1}}\ge 1$ [duplicate]

Prove that if $x_{1}x_{2}...x_{n}=1$ then $\frac{1}{1+x_{1}+x_{1}x_{2}}+...+\frac{1}{1+x_{n-1}+x_{n-1}x_{n}}+\frac{1}{1 +x_{n}+x_{n}x_{1}}\ge 1$. $x_{1},x_{2},...,x_{n}$ are positive real numbers, and ...
nowepas's user avatar
  • 288
5 votes
4 answers
485 views

Big Greeks and commutation

Does a sum or product symbol, $\Sigma$ or $\Pi$, imply an ordering? Clearly if $\mathbf{x}_i$ is a matrix then: $$\prod_{i=0}^{n} \mathbf{x}_i$$ depends on the order of the multiplication. But, ...
Lucas's user avatar
  • 1,489
5 votes
3 answers
3k views

swap summation and multiple

In which case can we swap summation and multiple? ie. $$\sum_{i=1}^n\prod_{j=1}^na_{ij}=\prod_{j=1}^n\sum_{i=1}^na_{ij}$$ if we can't swap like this, please tell me how can we swap them?
maple's user avatar
  • 2,883
5 votes
2 answers
151 views

An equality between a product and a combinatorial sum

I'm trying to prove the following identity (of which I numerically verified the truth) : $$\text{For every $n\in\mathbb{N}^*$ and $\alpha \in \mathbb{R}\setminus\lbrace-2k\text{ }|\text{ }k\in\mathbb{...
Harmonic Sun's user avatar
  • 1,984
5 votes
3 answers
195 views

Prove that $\frac{\sqrt[n]{\prod_{k = 1}^nx_n}}{m} \ge n - 1$ where $\sum_{k = 1}^n\frac{1}{x_k + m} = \frac{1}{m}$.

Given positives $x_1, x_2, \cdots, x_{n - 1}, x_n$ such that $$\large \sum_{k = 1}^n\frac{1}{x_k + m} = \frac{1}{m}$$. Prove that $$\large \frac{\displaystyle \sqrt[n]{\prod_{k = 1}^nx_n}}{m} \ge n - ...
Lê Thành Đạt's user avatar
5 votes
1 answer
1k views

Sum operator precedence

I'm trying to read some simple equations and in order to interpret them in the right way I need to know $\sum$ and $\prod $ operator range/precedence. $$ \sum p(s, a) +\gamma $$ is equal to $\sum(p(...
Most Wanted's user avatar
5 votes
1 answer
225 views

Proving $(1+\frac 1n)^{n} = 1 + \sum_{k=1}^n({\frac 1{k!}\prod_{r=0}^{k-1}(1-\frac rn))}$ using the binomial theorem

$$\left(1+\frac 1n\right)^{n} = 1 + \sum\limits_{k=1}^n \left\{\frac 1{k!}\prod_{r=0}^{k-1}\left(1-\frac rn\right)\right\}$$ this exercise is taken from Apostol's Calculus I (page 45) and it's ...
Bog's user avatar
  • 135

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