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0 votes
1 answer
47 views

Sum sequence using Stolz–Cesàro

I have this sequence, and I need to find the convergence of the sum sequence. The answer is - sum equal π/4. But I tried to solve it by Stolz–Cesàro, as you can see in the picture, And what I got is ...
6 votes
4 answers
241 views

Evaluate $\int_{0}^{1}\{1/x\}^2\,dx$

Evaluate $$\displaystyle{\int_{0}^{1}\{1/x\}^2\,dx}$$ Where {•} is fractional part My work $$\displaystyle{\int\limits_0^1 {{{\left\{ {\frac{1}{x}} \right\}}^2}dx} = \sum\limits_{n = 1}^\infty {\...
1 vote
1 answer
46 views

Simplifying $\frac{1}{2}\sum_{n=0}^{\infty}{(n+1)(n+2)(z^n+z^{n+1})}$

This is part of a larger problem where I am trying to prove $\sum_{n=0}^{\infty}{(n+1)^2z^n}=(z+1)/(1-z)^3$. Thus far I have used the derivatives of the geometric series to obtain $\frac{1}{2}\sum_{n=...
4 votes
2 answers
488 views

Sum $\sum\limits_{n=1}^{\infty}\frac{(-1)^n}{\sqrt{n}}$

I have the following infinite sum: $$ \sum\limits_{n=1}^{\infty}\frac{(-1)^n}{\sqrt{n}} $$ Because there is a $(-1)^n$ I deduce that it is a alternating series. Therefore I use the alternating series ...
8 votes
2 answers
244 views

How to calculate $\int _0^1 \int _0^1\left(\frac{1}{1-xy} \ln (1-x)\ln (1-y)\right) \,dxdy$

Let us calculate the sum $$ \displaystyle{\sum_{n=1}^{+\infty}\left(\frac{H_{n}}{n}\right)^2}, $$ where $\displaystyle{H_{n}=1+\frac{1}{2}+\cdots+\frac{1}{n}}$ the $n$-th harmonic number. My try The ...
2 votes
2 answers
172 views

how to turn the sum $\lim\limits_{n\to\infty}\left(\prod\limits_{k=0}^n \frac{2n+2k}{2n+2k+1}\right)$ into integral with Riemann sum

I want to solve $\lim_{n\to\infty}\left(\prod_{k=0}^n \frac{2n+2k}{2n+2k+1}\right)$ with integration I know that $\lim_{n \to \infty}\frac{b-a}{n} \sum_{k=0}^nf(a+\frac{b-a}{n})=\int_a^b f(x)dx$ so ...
4 votes
1 answer
125 views

Find value of this sum

Let $$\lim_{x\rightarrow 0}\frac{f^{}(x)}{x}=1$$ and for every $x,y \in \mathbb{R} $ we have: $$f(x+y)=f(x)-f(y)+ xy(x+y)$$ Now Find : $$\sum_{i=11}^{17}f^{\prime} (i)$$ I think this question is ...
2 votes
1 answer
177 views

Show that $ \int_0^{\pi\over 2}\frac{\sin(2nx)}{\sin^{2n+2}(x)}\frac{1}{e^{2\pi \cot x}-1}dx =(-1)^{n-1}\frac{2n-1}{4(2n+1)} $

Show that $$ \int_0^{\pi\over 2}\frac{\sin(2nx)}{\sin^{2n+2}(x)}\frac{1}{e^{2\pi \cot x}-1}dx =(-1)^{n-1}\frac{2n-1}{4(2n+1)} $$ My attempt Lemma-1 \begin{align*} \frac{\sin(2nx)}{\sin^{2n}(x)}&=\...
1 vote
2 answers
205 views

Which closed form expression for this series involving Catalan numbers : $\sum_{n=1}^{\infty}\frac{(-1)^{n-1}}{4^nn^2}\binom{2n}{n}$

Obtain a closed-form for the series: $$\mathcal{S}=\sum_{n=1}^{\infty}\frac{(-1)^{n-1}}{4^nn^2}\binom{2n}{n}$$ From here https://en.wikipedia.org/wiki/List_of_m ... cal_series we know that for $\...
0 votes
2 answers
200 views

how to calculate $\sum\limits_{k=1}^{+\infty }{\arctan \frac{1}{1+k^{2}}}$

Question: how to calculate $$\sum\limits_{k=1}^{+\infty }{\arctan \frac{1}{1+k^{2}}}$$ My attempt Let $\arctan \theta =\frac{i}{2}\ln \left( \frac{i+\theta }{i-\theta } \right)$ $$S=\sum\limits_{k=1}^{...
0 votes
0 answers
132 views

Calculation of $\sum_{n=1}^{\infty}\frac{\psi_1(n)}{2^nn^2}$

Calculation of $$\sum_{n=1}^{\infty}\frac{\psi_1(n)}{2^nn^2}$$ My attempt \begin{align*} \sum_{n=1}^\infty\frac{\psi_1(n)}{2^n n^2} &= -\sum_{n=1}^\infty\psi_1(n)\left(\frac{\log(2)}{2^n n}+\int_0^...
4 votes
2 answers
200 views

How to evaluate this sum $\sum_{n=1}^{\infty} \frac{(-1)^n}{(n^2 + 3n + 1)(n^2 - 3n + 1)}$

How to evaluate this sum $$\sum_{n=1}^{\infty} \frac{(-1)^n}{(n^2 + 3n + 1)(n^2 - 3n + 1)}$$ My attempt $$\sum_{n=1}^{\infty} \frac{(-1)^n}{(n^2 + 3n + 1)(n^2 - 3n + 1)}$$ $$= \sum_{n=1}^{\infty} \...
1 vote
1 answer
123 views

Convergence of summation of complex exponentials with alternating exponent

Related to my previous question, consider $$f(s)=\sum_{k=1}^{\infty} \exp(-s(-2)^k)$$where $s\in\mathbb{C}$ is a complex number. According to the Willie Wong's comment, $f(s)$ diverges when $\Re\{s\} \...
32 votes
1 answer
818 views

On the relationship between $\Re\operatorname{Li}_n(1+i)$ and $\operatorname{Li}_n(1/2)$ when $n\ge5$

Motivation $\newcommand{Li}{\operatorname{Li}}$ It is already known that: $$\Re\Li_2(1+i)=\frac{\pi^2}{16}$$ $$\Re\Li_3(1+i)=\frac{\pi^2\ln2}{32}+\frac{35}{64}\zeta(3)$$ And by this question, ...
2 votes
2 answers
227 views

Evaluate the infinite product $ \prod_{n=1}^{\infty} \left ( 1 + \frac{x^2}{n^2+n-1} \right )$

Question statement Evaluate the infinite product $$\displaystyle{\prod_{n=1}^{\infty} \left ( 1 + \frac{x^2}{n^2+n-1} \right ) }$$ My try Because of the square of $\displaystyle{x}$ , we can consider $...

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