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2 votes
1 answer
47 views

Double Sum to Product Derivation

The function after the double-sigma sign can be separated into the product of two terms, the first of which does not depend on $s$ and the second of which does not depend on $r$. Source Is the ...
Starlight's user avatar
  • 1,818
0 votes
0 answers
43 views

Compute a tight upper bound of $\sum_{i=1}^{n-1}\frac{1}{3^i\log{n}- 3i}$?

I am trying to compute a tight upper bound of the sum below. $\sum_{i=1}^{n-1}n\frac{\frac{1}{3^i}}{\log_3{(n/3^i)}}$ I was able to 'simplify' it up to the expression below. $n\sum_{i=1}^{n-1}\frac{1}{...
ultrajohn's user avatar
  • 185
0 votes
1 answer
86 views

Can we derive the formula for summation of the series $1^{m}+2^{m}+3^{m}+...+n^{m}$ for every $m\geq2$? [duplicate]

Can we derive the formula for summation of the series $1^{m}+2^{m}+3^{m}+...+n^{m}$ for every $m\geq1$ ? For e.g. $1+2+3+...+n=\frac{n(n+1)}{2}$ . Here $m=1$ . Now I also know that $1^{2}+2^{2}+3^{2}+....
Syamaprasad Chakrabarti's user avatar
3 votes
1 answer
205 views

Is there a sequence where the average of the squares is proportional to the square of the average?

Usually in math, the order of operations matters when you do anything more complicated than addition or multiplication. If you have a list of numbers, whether you apply the average or the squaring ...
MumboJumbo's user avatar
0 votes
1 answer
81 views

How to find the sum of a finite number of increasing fractional powers

It is easy to show $\quad\sum_{i=1}^{\infty} \dfrac{1}{n^i}=\dfrac{1}{n-1}\quad$ e.g. $$\quad\sum_{i=1}^{\infty} \dfrac{1}{2^i}=\dfrac{1}{1}\quad$ $\quad\sum_{i=1}^{\infty} \dfrac{1}{3^i}=\dfrac{1}{2}...
poetasis's user avatar
  • 6,381
-1 votes
2 answers
241 views

How to derive $1^3 + 2^3 + \cdots + n^3 = \left(\frac12n(n +1)\right)^2$? [duplicate]

So I know of the basic summation: $$1 + 2 + \dots + n = \frac{n(n +1)}{2}$$ You derive this by noting that if you pair every element with the one on the other end (example: $1$ with $n$, $2$ with $n - ...
user129393192's user avatar
0 votes
0 answers
52 views

How can I prove that $ \sum_{k=1}^{n}\frac{k\cdot P(n,k)}{n^{k+1}} = 1$? [duplicate]

The answer is difficult to me, I cannot figure out how to compute it. $\sum_{k=1}^{n}\frac{k\cdot P(n,k)}{n^{k+1}}=1$ If someone can explain some technique to do it, I'd appreciate it. I tried to ...
MAB's user avatar
  • 1
0 votes
0 answers
104 views

series based on $(1+x+x^2)^n$

Question : Let $a_r$ denote the following $$(1+x+x^2)^n=\sum_{r=0}^{2n}a_rx^r$$ then prove the following $$\sum_{r=0}^{n}(-1)^r\binom n r a_r = \begin{cases} 0 & n \ne 3k \text{ for all ...
sparrow_2764's user avatar
8 votes
1 answer
250 views

Compute $\sum^{2024}_{k=1} \frac{2023-2022 \cos \left(\frac{\pi(2k-1)}{2024} \right)}{2021-2020 \cos \left(\frac{\pi(2k-1)}{2024} \right)}$

Question: Compute $$\sum^{2024}_{k=1} \frac{2023-2022 \cos \left(\frac{\pi(2k-1)}{2024} \right)}{2021-2020 \cos \left(\frac{\pi(2k-1)}{2024} \right)}$$ I began by rearranging the sum as follows: $$\...
Indecisive's user avatar
2 votes
0 answers
84 views

Evaluating $\sum_{k=0}^{\infty} \frac {2^k}{5^{2^k}+1}$ [duplicate]

So my teacher shared this problem with us and said everyone needs to try this, he teaches us Olympiad Math so I am assuming this wouldn't require analysis or calculus. This is the question, I have ...
Nishkarsh's user avatar
2 votes
1 answer
72 views

Proving $\sum_{k=0}^{(m-1)/2}(-1)^k{{m+1}\choose{k}}\left(\frac{m+1}{2}-k\right)^p=0$, for odd $m\geq3$ and even $2\leqslant p\leq m-1$

I am trying to prove the following identity for odd $m\geqslant 3$ and even $2\leqslant p\leqslant m-1$: $$\sum_{k=0}^{(m-1)/2}(-1)^k{{m+1}\choose{k}}\left(\frac{m+1}{2}-k\right)^p=0$$ When I split ...
sofic's user avatar
  • 23
1 vote
2 answers
170 views

Proof of weird formula for method of differences

Suppose we have to find sum of a sequence $t_1,t_2,t_3...t_n$. For $1\le i\le n$, let $\triangle t_i=t_{i+1} -t_i$, $\triangle ^2t_i=\triangle t_{i+1}-\triangle t_i$ and so on ($\triangle ^{j}t_i=\...
Eisenstein's user avatar
0 votes
1 answer
56 views

Prove the sum of n integers starting from n.

Prove that the sum of $n$ integers starting from $n$ has the recurrence $a_{n-1}+3n-2;\quad a_0=0$ $$\sum_{i=n}^{2n-1}i=a_{n-1}+3n-2\quad n\in\mathbb{N} \tag{EQ 1}$$ Examples:$$n=1 \qquad \sum_{i=1}^{...
Narlin's user avatar
  • 1,211
1 vote
0 answers
92 views

Example of a specific polynomial

I need four non-trivial polynomials $P(x)$, $Q(y)$, $R(z)$ and $S(w)$ such that $$P(x)Q(y)R(z)S(w)=\sum_{i}a_i b_i c_i d_i x^i y^i z^i w^i+ \sum_{j\neq k\neq l\neq m}e_j f_k g_l h_m x^j y^k z^l w^m $$ ...
Max's user avatar
  • 862
1 vote
0 answers
47 views

Multiple Sigma Notation and Expected Value

I've been struggling with expected value calculations that involve multiple or nested sigma notations. For instance, the solution to a problem I was working on is: $X=\Sigma_{i=1}^{10}X_i\implies E[X]...
user601846's user avatar

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