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17 votes
2 answers
19k views

Proof there is a rational between any two reals

This is a problem from Rudin, but I wanted to add my own intuition to it. It uses Rudin's definition of Archimedean property. I'd just like to know if my version holds If $x \in \mathbb R$, $y\in \...
Good Morning Captain's user avatar
7 votes
5 answers
2k views

Is this direct proof of an inequality wrong?

My professor graded my proof as a zero, and I'm having a hard time seeing why it would be graded as such. Either he made a mistake while grading or I'm lacking in my understanding. Hopefully someone ...
Ravarion's user avatar
7 votes
2 answers
277 views

Baby Rudin Theorem 1.19 Step 5

I have no background in pure mathematics, and I'm trying to learn how to be more rigorous in general. To help with this, I am trying to make everything more explicit as I progress through Rudin's ...
AspiringScrub's user avatar
6 votes
4 answers
11k views

How to prove that every real number is the limit of a convergent sequence of rational numbers?

Here is my procedure: so we want to prove $\forall r\in \mathbb{R},$ there exists a sequence $q_n$ of rationals such that $\forall\epsilon\gt 0,$ there exists a $N$ such that $n\gt N\implies |q_n-r|\...
CoolKid's user avatar
  • 2,758
6 votes
1 answer
202 views

Different definitions of the archimedean property

In some textbooks I have seen the archimedean property defined as: for some positive real $x$, real number $y$, there exists a natural $n$ such that $nx>y$. In other textbooks the archimedean ...
Elimination_matrices's user avatar
6 votes
1 answer
3k views

Proving that the absolute value of x is greater then or equal to $0$

My Question reads: Prove for all $x\in\mathbb{R}$, $|x|\geq\ 0$. This is for a set theory class where we know that $\mathbb{R}$ is the set of Dedekind cuts. For each $x\in\mathbb{R}$, we define $|...
Sam's user avatar
  • 1,088
5 votes
1 answer
6k views

For every $\epsilon >0$ , if $a+\epsilon >b$ , can we conclude $a>b$?

If $a+\epsilon > b$ for each $\epsilon >0$, can we conclude that $a>b$? Please help me to clarify the above. Thanks in advance.
Peter's user avatar
  • 1,975
4 votes
2 answers
172 views

Proving the density of a function in an interval.

I am reading Steven G. Krantz's Real Analysis and Foundations and came across this problem. Problem: Let $\lambda$ be a positive irrational real number. If $n$ is a positive integer, choose by the ...
slhulk's user avatar
  • 290
4 votes
2 answers
12k views

Proof clarification - If $ab = 0$ then $a = 0$ or $b =0$

I came across a proof for the following theorem in Apostol Calculus 1. My question is regarding (1) in the proof, why is this part necessary? I don't see why you can't begin with (2) Theorem 1.11 If ...
YetiMountainButter's user avatar
3 votes
4 answers
941 views

Why does a/b have to be in simplest form in the proof of irrationality for sqrt2

The proof of the irrationality of $\sqrt{2}$ starts with the supposition that $\sqrt{2} = \frac ab$ where $a$ and $b$ are integers. I understand that, but why is it important that $\frac ab$ is ...
Zoe Nelson's user avatar
3 votes
2 answers
1k views

$x,y$ are real, $x<y+\varepsilon$ with $\varepsilon>0$. How to prove $x \le y$? [closed]

$x,y \in \mathbb R$ are such that $x \lt y + \epsilon$ for any $\epsilon \gt 0$ Then prove $x \le y$.
Highlights Factory's user avatar
3 votes
1 answer
663 views

Prove: If $x$ has the property that $0\leq x<h$ for every$ h>0$, then$ x=0$.

I'm going through Apostol's Calculus I introduction, and I'm trying to prove this, but I'm having a little trouble doing it. It's proposed as an exercise in section I 3.5: order axioms. So, what I ...
Daniel Bonilla Jaramillo's user avatar
3 votes
2 answers
3k views

How to prove the power set of the rationals is uncountable?

Recently a professor of mine remarked that the rational numbers make an "incomplete" field, because not every subsequence of rational numbers tends to another rational number - the easiest example ...
Rob's user avatar
  • 7,202
3 votes
3 answers
467 views

Formal proof of: $x>y$ and $b>0$ implies $bx>by$?

Property: If $x,y,b \in \mathbb{R}$ and $x>y$ and $b>0$, then $bx>by$. What is a formal (low-level) proof of this result? Or is this property taken as axiomatic? The motivation for this ...
Rebecca J. Stones's user avatar
3 votes
2 answers
69 views

Regarding $x < y \Rightarrow x^n < y^n$ proof rigor.

I came across the implication $$x < y \Rightarrow x^n < y^n$$ $$x,y>0, n\in Z^+$$ in a textbook and came up with the following proof. Proof Since $x<y$ the following chain of inequalities ...
John Dough's user avatar

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