My professor graded my proof as a zero, and I'm having a hard time seeing why it would be graded as such. Either he made a mistake while grading or I'm lacking in my understanding. Hopefully someone can help sort it out. The proof is as follows:
Goal: If $n$ is a positive integer, then $\frac{n}{n+1} > \frac{n}{n+2}$.
Proof: Assume $n$ is a positive integer.
Observe, $\frac{n}{n+1} > \frac{n}{n+2}$
$\frac{n(n+1)}{n+1} > \frac{n(n+1)}{n+2}$
$n > \frac{n^2+n}{n+2}$
$n(n+2) > \frac{(n^2 + n)(n+2)}{n+2}$
$n^2 + 2n > n^2 + n$
$n^2 - n^2 + 2n > n^2 - n^2 + n$
$2n > n$
Since $2n > n$ for all positive integers, then $\frac{n}{n+1} > \frac{n}{n+2}$ for all positive integers.
Therefore, if $n$ is a positive integer, then $\frac{n}{n+1} > \frac{n}{n+2}$. Q.E.D.
Here are the notes on the problem by the professor:
"You assumed Q! You cannot assume your conclusion!"
Shows that $2n > n$ reduces down to $n > 0$ and points an arrow to 'Assume n is a positive integer' "Circular logic."
"By the way... reducing to falsehood is a valid truth technique(proof by contradiction) but reduction to truth tells you nothing."