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0 votes
0 answers
63 views

What is the most general Self-Adjoint operator acting on $L^{2}(\mathbb{R})$?

What is the most general Self-Adjoint operator acting on $L^{2}\mathbb{R}$? My hypothesis is that the aswer to my question will be that the most general Self-Adjoint operator $A$ acting on $L^{2}(\...
Hldngpk's user avatar
  • 71
1 vote
0 answers
105 views

On the structure of the set of Self-Adjoint operators acting on $L^{2}(\mathbb{R})$.

Let us consider the $Hilbert$ Space $L^{2}(\mathbb{R})$ and let $SA(L^{2}(\mathbb{R})$ be the space of all self adjoint operators acting on $L^{2}$. I have worked with operators such as $X$, $P$, $X^{...
Hldngpk's user avatar
  • 71
2 votes
1 answer
370 views

If $\hat{A}$ commutes with $\hat{r}^2$, does $\hat{A}$ commute with $\hat{r}$?

Let $\hat{x}, \hat{y}, \hat{z}$ be the position operators in 3D space and $\hat{r}^2=\hat{x}^2+\hat{y}^2+\hat{z}^2$ as usual. If one operator $\hat{A}$, commutes with $\hat{r}^2$, i.e. $$\Big[\hat{A}, ...
Gaussian97's user avatar
0 votes
0 answers
27 views

Question regarding conjugate operators and the harmonic operator.

Let us consider the operator $\hat{n}=\hat{a}^\dagger\hat{a}$ as the number operator of the harmonic oscillator. Let $|n\rangle$ be the eigenstates. Then we can say : $$\hat{n}|n\rangle=n|n\rangle$$ I'...
Nakshatra Gangopadhay's user avatar
1 vote
1 answer
145 views

Given $[A,B]=0$ then $[A,f(B)]=0$

Given $A$ and $B$ two operators that commute ($[A,B]=0$) then $A$ commutes with an arbitrary function of $B$ I recently saw this property of the commutators on a quantum mechanics course. We didn't ...
Mikel Solaguren's user avatar
1 vote
1 answer
67 views

Equivalence between two definitions of hermitian adjoint

Given the two definitions of hermitian adjoint: $(1): <\Psi|A|\Phi>=(<\Psi|A^+|\Phi>)^*$ $(2): <\Psi|A\Phi>=<A^+\Psi|\Phi>$ I want to show that they are equivalent However I ...
Mikel Solaguren's user avatar
1 vote
0 answers
62 views

Integral over operators equal -When are operators equal?

This is a physics motivated question from quantum mechanics. When I have two operators $\hat{A}$ and $\hat{B}$ acting on the Hilbertspace $\mathbb{C}-L^2(\mathbb{R})$ with $$\int\psi^*(x)\hat{A}\psi(x)...
Silas's user avatar
  • 320
1 vote
1 answer
42 views

What can I infer from this scalar product identity?

Suppose I have shown for a single vector $\lvert 0 \rangle$ that $$\langle 0 \rvert U^\dagger \phi U \lvert 0 \rangle=\langle 0 \rvert \phi \lvert 0 \rangle$$ where $\phi$ is a certain operator and $U$...
Ghorbalchov's user avatar
5 votes
1 answer
191 views

Problem on a rank 1 perturbation of an self-adjoint operator

With my teacher we have been trying to solve for a while a problem that consists of two parts, and each one in three sections. The first part, which has to do with the problems that I was able to ...
Litafie's user avatar
  • 160
1 vote
1 answer
74 views

Action of an operator-valued function of the momentum operator $\hat{p}$ and its unboundedness

I am currently dealing with an operator-valued function $f(\hat{T})$ of the following kind: $$f(\hat{T}) =\sqrt{1 + b\hat{T}^2} $$ where $b$ $\in \mathbb{R}$ and $\hat{T}$ is a linear operator acting ...
RH_ss's user avatar
  • 31
1 vote
1 answer
94 views

What is the meaning of the operator projection in quantum mechanic

Let's have a vector $B_1$ which lies in the $xz$ plane forming an angle $\theta$ with $z$ axis. Let $S_\theta$ be the projection of the operator S along $B_1$. Question 1: How can i write $S_\theta$ ...
Salmon's user avatar
  • 315
0 votes
1 answer
33 views

On derivatives of tensor products in QM

Does the derivation follow a sort of Leibniz's Rule for a tensor product? $ \displaystyle \frac {\partial} {\partial t} \left ( A_t \otimes B_t \right) \overset ? = \frac {\partial A_t} {\...
ric.san's user avatar
  • 141
4 votes
2 answers
99 views

Can I conclude these weak derivatives are strong?

I'm trying to show the momentum operator $P : \mathcal D(P)\ \dot{=}\ C^\infty_0(\Bbb R)\to L^2(\Bbb R)$ with $P=-i\hbar\partial_x$ is essentially self-adjoint, which is equivalent to saying that it ...
giobrach's user avatar
  • 7,532
0 votes
1 answer
192 views

proof of the product: x times m derivative of delta function.

The question is in one dimension and is : Prove that $$x\delta^{(m)}=-m\delta^{(m-1)},\ m \in \mathbb{N},$$ where $\delta^{(m)}$ is the $m$-derivative of $\delta.$ As I know, I got through this way: $...
João Pedro's user avatar
2 votes
1 answer
82 views

Scaled Dirac Delta function: $ \delta (xe^r - y) $

I was reading on squeezed Gaussian states and stumbled upon this paper: Equivalence Classes of Minimum-Uncertainty Packets. II. It is mentioned after Eq. $\left(2\right)$ that $$ \left\langle x\left\...
Lefteris's user avatar

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