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Questions tagged [prime-factorization]

For questions about factoring elements of rings into primes, or about the specific case of factoring natural numbers into primes.

2 votes
2 answers
262 views

Prime factors of $5^n+6^n+7^n+8^n+9^n+10^n$

I currently run an integer factoring project of the numbers of the form $$5^n+6^n+7^n+8^n+9^n+10^n$$ where $n$ is a non-negative integer. Do the prime factors have a particular form as it is the case ...
Peter's user avatar
  • 85.1k
0 votes
0 answers
52 views

Found a relation regarding the primes, is this interesting?

Define $S_{odd}$ as all $n\in N $ where $n$ is the product of an odd number of distinct primes. Define $S_{even}$ similarly. Thus: $$S_{odd} = \{2,3,5,...,30,42,....\}$$ $$S_{even} = \{6,10,14, ....,...
AndroidBeginner's user avatar
-1 votes
1 answer
84 views

Dottie number and prime factorization

It's related to Dottie number and prime factorization . Let : $D=\operatorname{Dottie-number}\simeq 0.7390851332$ Now define $n\geq 3$ an integer: $$\lfloor\left(D\right)^{-2n}\rfloor=P$$ Then it ...
Ranger-of-trente-deux-glands's user avatar
2 votes
1 answer
96 views

Is $\omega(n)=16$ the maximum?

What is the largest possible value of $\omega(n)$ (the number of distinct prime factors of $n$) , if $n$ is a $30$-digit number containing only zeros and ones in the decimal expansion. I checked ...
Peter's user avatar
  • 85.1k
0 votes
0 answers
55 views

Ramification of primes on $\overline{\mathbb Q}$

My concern arises about the existence of unramified primes in infinite extensions of $\mathbb Q$, particularly in $\overline{\mathbb Q}$. Now, in general there exist be a definition of ramification ...
Luis Antonio Sanchez's user avatar
3 votes
1 answer
308 views

Center Binomial can "Self-Factor" RSA semiprimes. [closed]

Given two odd primes $P$ and $Q$ s.t. $P < Q$, $PQ = N$, $P \neq 3$ and $Q \neq 5$ at same time... the center binomial $f(k)=\frac{(2k)!}{(k!)^{2}}$ can be used to factor $N$. This will not be ...
steveK's user avatar
  • 129
1 vote
2 answers
90 views

SemiPrime Test to determine distance between P and Q

I have two composite primes (semiprimes) where $17*641 = 10897$ and $101*107 = 10807$. Notice that $10897$ and $10807$ are almost equal. Their square roots are $104.38$ and $103.95$ respectively. But ...
steveK's user avatar
  • 129
0 votes
0 answers
59 views

Why trial division algorithm to find the prime factors of $N$ is $O(\sqrt{N})$, even though you need to check after $\sqrt{N}$?

I have understood that to check if $N$ is prime, it is enough to check up to $\sqrt{N}$ because if it has divisor up to that point then it's composite number. However, if you want to count all the ...
Inf's user avatar
  • 21
1 vote
0 answers
82 views

Is the quadratic sieve algorithm on Wikipedia wrong/inefficient?

I'm confused by a few aspects of the algorithm. https://en.wikipedia.org/wiki/Quadratic_sieve First, I'm confused by the choice of $a_i$'s. For each iteration: Choose $x \in \{ 0, \pm 1, \pm 2, \...
hidenori's user avatar
0 votes
3 answers
471 views

Is this algorithm efficient as a factorization algorithm?

Let $N=8*G+3$ $->$ $N=(4*x+2)^2-(2*y-1)^2=p*q$ with $q/p < 2$ Given this system if we choose $D^2$ odd close to $8*x+4$ $->$ $(8*x+4-D^2)=W*V$ with $V$ and $W$ odd very close to each other ...
Alberico Lepore's user avatar
0 votes
0 answers
31 views

Form of the divisors of a number (Prime Factorization). Is this algorithm-based proof correct? [duplicate]

I am trying to proof the following result: For a number $n$ whose prime number decomposition is $p_1^{\alpha _1} ... p_m^{\alpha _m}$. Every divisor of $n$ has the form $p_1^{\beta _1} ... p_m^{\beta ...
niobium's user avatar
  • 1,231
0 votes
1 answer
59 views

ways to write out a number in exponential form

Let's say that we have a number of the form $n^n$. How many integer pairs of the form $a^b$ are equivalent to this number? for example, let's say that $n=8$ We have $2^{24}$, $(-2)^{24}$, $4^{12}$, $(-...
Evan Semet's user avatar
-2 votes
1 answer
67 views

All possible factorisations of a number

Is there a method for finding all possible n-factor factorisations of a number? For example, if all possible 2-factor factorisations of 90 (up to order) are: 1 × 90 2 × 45 3 × 30 5 × 18 6 × 15 9 × 10 ...
FreeThought's user avatar
1 vote
1 answer
110 views

Open Question: For natural $n$ with prime decomposition $\prod p_i^{r_i}$, define $f(n)=\sum p_i r_i$. Find all $n$ such that $f(n)-f(n+1)=1$.

A question I created myself: For any $n\in \Bbb{N}$, we can get $n = p_1^{r_1}\cdots p_m^{r_m}$, where $p_i$ are primes. Take $$f(n)=p_1r_1+\cdots+p_mr_m$$ Find all $n$ such that $f(n)-f(n+1)=1$ It ...
Alwin Chen's user avatar
0 votes
0 answers
70 views

Show for some n Fermat’s method is faster than reverse trial division

One way to find a nontrivial divisor of n is Fermat’s factorization method: Suppose that we have an odd number n > 1 which we know is composite and not a perfect square. Calculate $\lfloor \sqrt{n}...
Mzq's user avatar
  • 254

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