All Questions
Tagged with polylogarithm complex-analysis
41
questions
4
votes
2
answers
260
views
Logarithmic integral $ \int_0^1 \frac{x}{x^2+1} \, \log(x)\log(x+1) \, {\rm d}x $
At various places e.g.
Calculate $\int_0^1\frac{\log^2(1+x)\log(x)\log(1-x)}{1-x}dx$
and
How to prove $\int_0^1x\ln^2(1+x)\ln(\frac{x^2}{1+x})\frac{dx}{1+x^2}$
logarithmic integrals are connected ...
2
votes
1
answer
311
views
Real Part of the Dilogarithm
It is well known that
$$\frac{x-\pi}{2}=-\sum_{k\geq 1}\frac{\sin{kx}}{k}\forall x\in(0,\tau),$$
which gives
$$\frac{x^2}{4}-\frac{\pi x}{2}+\frac{\pi^2}{6}=\sum_{k\geq 1}\frac{\cos(kx)}{k^2}.$$
...
2
votes
2
answers
797
views
Branch Points of the Polylog function
The polylogarithm
$$
{\rm Li}_s(z) = \sum_{n=1}^\infty \frac{z^n}{n^s}
$$
has obvious branch points at $z=1$.
For integers $s\leq 0$ it is a rational function with a pole of order $1-s$ at $z=1$. If $...
3
votes
0
answers
75
views
Approaching a branch point along different paths
There's a very nice characterization of the three main types of isolated singularities of an analytic function $f(z)$ that takes oriented curves $\gamma$ that terminate at the singularity and ...
3
votes
2
answers
304
views
Jump of dilogarithm
I am reading about the dilogarithm function
$$ \mathrm{Li}_2(z):= - \int_0^z \frac{\log(1-u)}{u}du, \quad z \in \mathbb{C} \backslash [1, \infty).$$
I found it stated that the "jump" of the ...
3
votes
1
answer
500
views
Bose-Einstein function as real part of polylogarithm: $\overline{G}_{s}(x)= \Re \mathrm{Li}_{s+1}(e^x)$
For real $x<0$ the Bose-Einstein integral of order $s$ is given at https://dlmf.nist.gov/25.12.E15 as
$$G_{s}(x)=\frac{1}{\Gamma\left(s+1\right)}\int_{0}^{\infty}\frac{t^{s}}{e^{t-x}
-1}\mathrm{d}...
2
votes
1
answer
686
views
Calculate a $\operatorname{Li}_{2}(-1)$ using Integral Representation
$\newcommand{LogI}{\operatorname{Li}}$
I know that $\LogI_{2}(-1)=-\frac{\pi^2}{12}$, but I have never seen a proof of this result without using a functional identity of the Dilogarithm or a series ...
0
votes
0
answers
135
views
Validity of argument in dilogarithm identities on Wolfram
I've come across a series of identities existing between dilogarithms and powers of logarithms but I am not sure about when such equations are valid in terms of the restriction of the domain of the ...
3
votes
3
answers
449
views
Indefinite integral $\int \arctan^2 x dx$ in terms of the dilogarithm function
I read about the integral
$$\int \arctan^2 x dx$$ in this old post: Evaluation of $\int (\arctan x)^2 dx$
By replacing
$$\arctan x = -\frac{i}{2}\left[\log(1+ix) - \log(i-ix)\right],$$
as suggested ...
1
vote
1
answer
1k
views
on the (double) discontinuity of dilogarithm along a branch cut
Define the function
$$Li_s(z)=\sum_{k=1}^\infty \frac{z^k}{k^s}$$
for |z|<1. Let's focus on $s=2$.
It can be extended to a holomorphic function on $\mathbb C \setminus [1,\infty)$
$$Li_2(z)= -\...
1
vote
2
answers
640
views
Sum of Dilogarithm and its Complex Conjugate
$$\newcommand{\dl}[1]{\operatorname{Li}_2\left( #1\right)}$$
I have the following expression involving Dilogarithims, where $z\in\mathbb{R}$ and $b\in\mathbb{C}\setminus\lbrace 0\rbrace$:
$$f(z,b) = ...
3
votes
1
answer
709
views
What's about $\int_0^\infty x^{-z}Li_{z+2}(e^{-xz})dx$ as $-\zeta(3)z^2\Gamma(-z)$?
Because $$-\int_0^\infty \frac{e^{-zt}}{t^z}dt=z^2\Gamma(-z),$$
holds for $0<\Re z<1$ then using the change of variable $t=nx$ one has that $$-\frac{1}{n^{z-1}}\int_0^\infty \frac{e^{-znx}dx}{x^...
1
vote
0
answers
98
views
What's the worst sequence that still leads to a converging series?
As a background, I'm initially interested in sequences $a_n$ giving rise to functions $\sum_{n=0}^\infty a_nx^n$ for $x\in(0,1)$ and their diverging behavior for $x$ to $1$. E.g. the geometric series $...
0
votes
1
answer
406
views
Evaluating Fermi Dirac integrals of order j<0
The complete Fermi Dirac integral (I'm purposely leaving off the gamma prefactor)...
$$F_j(x) =\int\limits_{0}^{\infty} \frac{t^j}{e^{t-x}+1} \: dt$$
is generally defined for j>-1. Is there a way to ...
5
votes
2
answers
438
views
Extract imaginary part of $\text{Li}_3\left(\frac{2}{3}-i \frac{2\sqrt{2}}{3}\right)$ in closed form
We know that polylogarithms of complex argument sometimes have simple real and imaginary parts, e.g.
$\mathrm{Re}[\text{Li}_2(i)]=-\frac{\pi^2}{48}$
Is there a closed form (free of polylogs and ...