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2 votes
2 answers
797 views

Branch Points of the Polylog function

The polylogarithm $$ {\rm Li}_s(z) = \sum_{n=1}^\infty \frac{z^n}{n^s} $$ has obvious branch points at $z=1$. For integers $s\leq 0$ it is a rational function with a pole of order $1-s$ at $z=1$. If $...
Diger's user avatar
  • 6,277
3 votes
0 answers
75 views

Approaching a branch point along different paths

There's a very nice characterization of the three main types of isolated singularities of an analytic function $f(z)$ that takes oriented curves $\gamma$ that terminate at the singularity and ...
tparker's user avatar
  • 6,280
1 vote
1 answer
1k views

on the (double) discontinuity of dilogarithm along a branch cut

Define the function $$Li_s(z)=\sum_{k=1}^\infty \frac{z^k}{k^s}$$ for |z|<1. Let's focus on $s=2$. It can be extended to a holomorphic function on $\mathbb C \setminus [1,\infty)$ $$Li_2(z)= -\...
jj_p's user avatar
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