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Questions tagged [ideals]

An ideal is a subset of ring such that it is possible to make a quotient ring with respect to this subset. This is the most frequent use of the name ideal, but it is used in other areas of mathematics too: ideals in set theory and order theory (which are closely related), ideals in semigroups, ideals in Lie algebras.

46 votes
8 answers
25k views

Why $\gcd(b,qb+r)=\gcd(b,r),\,$ so $\,\gcd(b,a) = \gcd(b,a\bmod b)$

Given: $a = qb + r$. Then it holds that $\gcd(a,b)=\gcd(b,r)$. That doesn't sound logical to me. Why is this so? Addendum by LePressentiment on 11/29/2013: (in the interest of http://meta.math....
www.data-blogger.com's user avatar
179 votes
11 answers
53k views

Prove that $\gcd(a^n - 1, a^m - 1) = a^{\gcd(n, m)} - 1$

For all $a, m, n \in \mathbb{Z}^+$, $$\gcd(a^n - 1, a^m - 1) = a^{\gcd(n, m)} - 1$$
user avatar
85 votes
7 answers
31k views

Quotient ring of Gaussian integers

A very basic ring theory question, which I am not able to solve. How does one show that $\mathbb{Z}[i]/(3-i) \cong \mathbb{Z}/10\mathbb{Z}$. Extending the result: $\mathbb{Z}[i]/(a-ib) \cong \mathbb{...
user avatar
160 votes
1 answer
37k views

Classification of prime ideals of $\mathbb{Z}[X]$

Let $\mathbb{Z}[X]$ be the ring of polynomials in one variable over $\Bbb Z$. My question: Is every prime ideal of $\mathbb{Z}[X]$ one of following types? If yes, how would you prove this? $(0)$. $(...
Makoto Kato's user avatar
  • 42.9k
56 votes
5 answers
30k views

Why are maximal ideals prime?

Could anyone explain to me why maximal ideals are prime? I'm approaching it like this, let $R$ be a commutative ring with $1$ and let $A$ be a maximal ideal. Let $a,b\in R:ab\in A$. I'm trying to ...
Freeman's user avatar
  • 5,459
2 votes
2 answers
2k views

Euclid's Lemma $\,(a,b)=1,\ a\mid bc\Rightarrow a\mid c\,$ in Bezout, gcd, ideal form

Let $A$ be a UFD, e.g. $A = \Bbb Z$ or $\,\Bbb Q[x,y]$. Assume $a,b \in A$ are relatively prime, $c \in A$ and $a | bc$. To prove that $a|c$, is the following approach correct (or do you have to use ...
afedder's user avatar
  • 2,102
22 votes
7 answers
12k views

$I+J=1 \Rightarrow I^n+J^n = 1$ for ideals (or elements in GCD domain) [Freshman's Dream Binomial Theorem]

Let $R$ be a commutative ring and $I_1, \dots, I_n$ pairwise comaximal ideals in $R$, i.e., $I_i + I_j = R$ for $i \neq j$. Why are the ideals $I_1^{n_1}, ... , I_r^{n_r}$ (for any $n_1,...,n_r \in\...
user avatar
56 votes
8 answers
42k views

$\langle 2,x \rangle$ is a non-principal ideal in $\mathbb Z [x];\, $ $D[x]$ PID $\iff D$ field, for a domain $D$

Hi I don't know how to show that $\langle 2,x \rangle$ is not principal and the definition of a principal ideal is unclear to me. I need help on this, please. The ring that I am talking about is $\...
Person's user avatar
  • 703
50 votes
2 answers
22k views

What are the left and right ideals of matrix ring? How about the two sided ideals?

What are the left and right ideals of matrix ring? How about the two sided ideals?
user avatar
1 vote
3 answers
1k views

Ideals $\neq0$ in $F[x]$ & Euclidean domains are generated by elements $\neq0$ of minimal degree (Euclidean size), so Euclidean $\Rightarrow$ PID

Consider the following Theorem Let $F$ be a field, $I$ a nonzero ideal in $F[x]$, and $g(x)$ an element of $F[x]$. Then, $I= \langle g(x)\rangle$ if and only if $g(x)$ is a nonzero polynomial of ...
user avatar
48 votes
5 answers
17k views

Structure of ideals in the product of two rings

$R$ and $S$ are two rings. Let $J$ be an ideal in $R\times S$. Then there are $I_{1}$, ideal of $R$, and $I_{2}$, ideal of $S$ such that $J=I_{1}\times I_{2}$. For me it's obvious why $\left\{ r\in R\...
IIJ's user avatar
  • 481
31 votes
2 answers
4k views

When does the distributive law apply to ideals in a commutative ring?

Let $R$ be a commutative ring with identity and $I,J,K$ be ideals of $R$. If $I\supseteq J$ or $I\supseteq K$, we have the following modular law $$ I\cap (J+K)=I\cap J + I\cap K$$ I was wondering if ...
Timothy Wagner's user avatar
74 votes
3 answers
37k views

What do prime ideals in $k[x,y]$ look like?

Suppose that $k$ is an algebraically closed field. Then what do the prime ideals in the polynomial ring $k[x,y]$ look like? As far as I know, the maximal ideals of $k[x,y]$ are of the form $(x-a,y-b)$...
user14242's user avatar
  • 2,900
21 votes
4 answers
29k views

In a PID every nonzero prime ideal is maximal

In a principal ideal domain, prove that every non trivial prime ideal is a maximal ideal Attempt: Let $R$ be the principal ideal domain. A principal ideal domain $R$ is an integral domain in which ...
MathMan's user avatar
  • 9,114
1 vote
1 answer
782 views

For ideals in a PID: sum = gcd, intersection = lcm

Suppose we have a Ring R which is a E.D, then it must be PID. Suppose $I = (a)$ and $J =(b)$ are two ideals. Is it true that $I+J =(a)+(b) = (\gcd(a,b))?$ If this is true then how can we prove it ...
user423255's user avatar

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