Skip to main content

All Questions

Tagged with
-1 votes
1 answer
46 views

Resources to master summation symbol [closed]

I noticed that I have some difficulties to use the summation tools( change of index, double or multiples summation...). Do you have some resources or book to master this topic. I am using concrete ...
Moi Moi's user avatar
1 vote
0 answers
69 views

Evaluating an infinite series with a function

There is an infinite series, I want to transform it into a function, with digamma functions or something else. I hope someone can provide some guidance and suggestions. $$ E(x,y)=\sum_{n=-\infty}^{\...
yongyouhe's user avatar
6 votes
2 answers
256 views

Problematic limit $\epsilon \to 0 $ for combination of hypergeometric ${_2}F_2$ functions

In an earlier question, the integral $$I_n(c)=\int_0^\infty x^n (1+x)^n e^{-n c x^2} dx$$ was considered with particular focus on its behavior for positive integer $n$. In trying to analyze this, it ...
Semiclassical's user avatar
3 votes
0 answers
48 views

How to solve $\sum\limits_{n=1}^\infty \prod\limits_{k=0}^{n-1} \frac{\alpha+k}{\beta+k}$? [duplicate]

This problem: $S:=\sum\limits_{n=1}^\infty \prod\limits_{k=0}^{n-1} \frac{\alpha+k}{\beta+k}$ where $\beta > a+1, \ \ \alpha, \beta >0$ is in my problem book and I couldn't solve it I tried to ...
pie's user avatar
  • 6,563
0 votes
1 answer
60 views

Cool identities/properties involving the Alternating Harmonic Numbers

Using the following analytic continuation for the Alternating Harmonic Numbers ($\bar{H}_x=\sum_{i=1}^x\frac{(-1)^{i+1}}i$): $$\bar{H}_x=\ln2+\cos(\pi x)\left(\psi(x)-\psi\left(\frac x2\right)-\frac1x-...
Kamal Saleh's user avatar
  • 6,549
0 votes
2 answers
89 views

A threshold for an exponential sum

I came across a sum where I have to find the smallest $n$ so that $$\sum_{x = 0}^n \frac{250^x}{x!} \ge \frac{e^{250}}{2}$$ I wrote a Java code and the result was 55 but with Desmos it was over 129 (...
Issaouik Aziz's user avatar
1 vote
0 answers
41 views

A partial sum formula [duplicate]

I'm very familiar with partial sums and such little bit hard once, but I was wondering is there a partial sum formula for that $$\displaystyle\sum_{n=1}^k n^n$$ I have tried with Wolfram alpha but I ...
I'mmksk's user avatar
  • 21
1 vote
0 answers
81 views

Closed form for $ \sum_{a_1=0}^\infty~\sum_{a_2=0}^\infty~\cdots~\sum_{a_n=0}^\infty \dfrac1{(a_1!+a_2!+\ldots+a_n!)} $ [closed]

After reading this post and the general solution for that case, I wonder if there is a closed form for the general solution for this sum: $ \sum_{a_1=0}^\infty~\sum_{a_2=0}^\infty~\cdots~\sum_{a_n=0}^\...
user967210's user avatar
0 votes
1 answer
77 views

Please help me to find the sum of an infinite series. [duplicate]

Please help me to solve this problem. I need to find the sum of an infinite series: $$ S = 1 + 1 + \frac34 + \frac12 + \frac5{16} + \cdots $$ I tried to imagine this series as a derivative of a ...
Starnex's user avatar
  • 21
2 votes
2 answers
80 views

Evaluate $\sum_{k=1}^{\infty}\frac{9k-4}{3k(3k-1)(3k-2)}$

We want to evaluate the series: $$\sum_{k=1}^{\infty}\frac{9k-4}{3k(3k-1)(3k-2)}$$ My try : We have : $$\frac{9k-4}{3k(3k-1)(3k-2)}=\frac{1}{3k-1}+\frac{1}{3k-2}-\frac{2}{3k}$$ Therefore: $$\sum_{k=1}^...
Mostafa's user avatar
  • 2,348
1 vote
2 answers
57 views

Summation form of improper integrals

On page 9, Edwards has this expression $$ \int_0^{\infty} e^{-nx} x^{s-1} dx = \frac{\Pi(s-1)}{n^s}$$ obtained from Euler’s factorial formula by replacing $x$ with $nx$. Can you help with the next ...
zeynel's user avatar
  • 447
2 votes
2 answers
78 views

How to calculate thi sum $\sum_{n=2}^{\infty} \frac{\left( \zeta(n) - 1 \right) \cos \left( \frac{n \pi}{3} \right)}{n}$

My question $$ \displaystyle{\mathcal{S} = \sum_{n=2}^{\infty} \frac{\left( \zeta(n) - 1 \right) \cos \left( \frac{n \pi}{3} \right)}{n}}$$ My try to solve the integral $$\displaystyle \sum\limits_{n =...
Ahan 's user avatar
  • 121
0 votes
0 answers
14 views

Getting the formular of a summation [duplicate]

im kind of stuck at my math homework from my calculus class. To progress further i need to be able to write a Summation into a forumular(?), as seen in the picture. Is there any proven method to do ...
Sicone's user avatar
  • 1
0 votes
1 answer
95 views

Showing $\sum_{n=1}^{\infty }\left ( \sum_{j=1}^{\infty }\frac{x^{(n-j)^2}-x^{(n+j-1)^2}}{(2n-1)(2j-1)} \right ) = \frac{\pi^2}{8}$

Show that $$\sum_{n=1}^{\infty }\left ( \sum_{j=1}^{\infty }\frac{x^{(n-j)^2}-x^{(n+j-1)^2}}{(2n-1)(2j-1)} \right) = \frac{\pi^2}{8}$$ I liked this problem because the result is a final answer, and ...
Dmitry's user avatar
  • 1,429
1 vote
5 answers
113 views

Alternative ways to evaluate $\sum_{k=1}^{n}(2k+1)^2$

I'm looking for alternative ways to calculate $$\sum_{k=1}^{n}(2k+1)^2$$ The normal approach is to expand $(2k+1)^2$ and use the formulas $\sum_{k=1}^n k^2 = \dfrac{n(n+1)(2n+1)}6$ , $\sum_{k=1}^n k = ...
Soheil's user avatar
  • 6,794
0 votes
4 answers
196 views

How to evaluate $\sum\limits_{n=3}^ \infty \frac{1}{n \ln(n)(\ln(\ln(n)))^2}$

I saw this problem : Prove that $\sum\limits_{n=3}^ \infty \frac{1}{n \ln(n)(\ln(\ln(n)))^2}$ converges, this is an easy problem could be proved using Cauchy condensation test twice. $$\sum_{n=3}^ \...
pie's user avatar
  • 6,563
0 votes
1 answer
47 views

Sum sequence using Stolz–Cesàro

I have this sequence, and I need to find the convergence of the sum sequence. The answer is - sum equal π/4. But I tried to solve it by Stolz–Cesàro, as you can see in the picture, And what I got is ...
miiky123's user avatar
  • 215
1 vote
1 answer
46 views

Simplifying $\frac{1}{2}\sum_{n=0}^{\infty}{(n+1)(n+2)(z^n+z^{n+1})}$

This is part of a larger problem where I am trying to prove $\sum_{n=0}^{\infty}{(n+1)^2z^n}=(z+1)/(1-z)^3$. Thus far I have used the derivatives of the geometric series to obtain $\frac{1}{2}\sum_{n=...
EzTheBoss 2's user avatar
4 votes
1 answer
125 views

Find value of this sum

Let $$\lim_{x\rightarrow 0}\frac{f^{}(x)}{x}=1$$ and for every $x,y \in \mathbb{R} $ we have: $$f(x+y)=f(x)-f(y)+ xy(x+y)$$ Now Find : $$\sum_{i=11}^{17}f^{\prime} (i)$$ I think this question is ...
amir bahadory's user avatar
0 votes
2 answers
200 views

how to calculate $\sum\limits_{k=1}^{+\infty }{\arctan \frac{1}{1+k^{2}}}$

Question: how to calculate $$\sum\limits_{k=1}^{+\infty }{\arctan \frac{1}{1+k^{2}}}$$ My attempt Let $\arctan \theta =\frac{i}{2}\ln \left( \frac{i+\theta }{i-\theta } \right)$ $$S=\sum\limits_{k=1}^{...
Mods And Staff Are Not Fair's user avatar
2 votes
1 answer
177 views

Show that $ \int_0^{\pi\over 2}\frac{\sin(2nx)}{\sin^{2n+2}(x)}\frac{1}{e^{2\pi \cot x}-1}dx =(-1)^{n-1}\frac{2n-1}{4(2n+1)} $

Show that $$ \int_0^{\pi\over 2}\frac{\sin(2nx)}{\sin^{2n+2}(x)}\frac{1}{e^{2\pi \cot x}-1}dx =(-1)^{n-1}\frac{2n-1}{4(2n+1)} $$ My attempt Lemma-1 \begin{align*} \frac{\sin(2nx)}{\sin^{2n}(x)}&=\...
Mods And Staff Are Not Fair's user avatar
0 votes
0 answers
132 views

Calculation of $\sum_{n=1}^{\infty}\frac{\psi_1(n)}{2^nn^2}$

Calculation of $$\sum_{n=1}^{\infty}\frac{\psi_1(n)}{2^nn^2}$$ My attempt \begin{align*} \sum_{n=1}^\infty\frac{\psi_1(n)}{2^n n^2} &= -\sum_{n=1}^\infty\psi_1(n)\left(\frac{\log(2)}{2^n n}+\int_0^...
Mods And Staff Are Not Fair's user avatar
4 votes
2 answers
203 views

How to evaluate this sum $\sum_{n=1}^{\infty} \frac{(-1)^n}{(n^2 + 3n + 1)(n^2 - 3n + 1)}$

How to evaluate this sum $$\sum_{n=1}^{\infty} \frac{(-1)^n}{(n^2 + 3n + 1)(n^2 - 3n + 1)}$$ My attempt $$\sum_{n=1}^{\infty} \frac{(-1)^n}{(n^2 + 3n + 1)(n^2 - 3n + 1)}$$ $$= \sum_{n=1}^{\infty} \...
Mods And Staff Are Not Fair's user avatar
8 votes
2 answers
244 views

How to calculate $\int _0^1 \int _0^1\left(\frac{1}{1-xy} \ln (1-x)\ln (1-y)\right) \,dxdy$

Let us calculate the sum $$ \displaystyle{\sum_{n=1}^{+\infty}\left(\frac{H_{n}}{n}\right)^2}, $$ where $\displaystyle{H_{n}=1+\frac{1}{2}+\cdots+\frac{1}{n}}$ the $n$-th harmonic number. My try The ...
Mods And Staff Are Not Fair's user avatar
1 vote
1 answer
123 views

Convergence of summation of complex exponentials with alternating exponent

Related to my previous question, consider $$f(s)=\sum_{k=1}^{\infty} \exp(-s(-2)^k)$$where $s\in\mathbb{C}$ is a complex number. According to the Willie Wong's comment, $f(s)$ diverges when $\Re\{s\} \...
S.H.W's user avatar
  • 4,359
2 votes
2 answers
228 views

Evaluate the infinite product $ \prod_{n=1}^{\infty} \left ( 1 + \frac{x^2}{n^2+n-1} \right )$

Question statement Evaluate the infinite product $$\displaystyle{\prod_{n=1}^{\infty} \left ( 1 + \frac{x^2}{n^2+n-1} \right ) }$$ My try Because of the square of $\displaystyle{x}$ , we can consider $...
Mods And Staff Are Not Fair's user avatar
1 vote
1 answer
130 views

Borel Regularization of $\sum_{n=1}^\infty \ln(n)$ [closed]

I'm trying to solve the following taylor series $$\sum_{n=0}^\infty \frac{x^n}{n!} \ln(n+1)$$ so I can regularize the following sum $$\sum_{n=1}^\infty \ln(n)$$ Using Borel Regularizaiton I can use ...
TheScripterGeek's user avatar
0 votes
1 answer
41 views

How to express $\sum_{i=0}^{m} \exp [(\frac{a}{b+c+i})^2] $ in terms of an integral?

I have this sum $$\sum_{i=0}^{m} \exp [(\frac{a}{b+c+i})^2] $$ where the upper limit $m$ is a finite non-negative integer, and $a,b,c\in\mathbb{R}$. I want to transform summation to an integral ...
MsMath's user avatar
  • 51
0 votes
0 answers
33 views

Question on transforming a sum to an integral using the Euler–Maclaurin formula.

I have a question regarding transforming a summation to an integral using the Euler–Maclaurin formula. Imagine I have this sum $$\sum_{i=0}^{m} f(i) \qquad \text{with} \qquad f(i)= \exp [(\frac{a}{b+...
MsMath's user avatar
  • 51
1 vote
0 answers
69 views

Leibniz integral rule for summation

Context Fundamental points of Feymann trick: You have an integral $I_0=\int_a^b f(t)\mathrm{d}t$ Now consider a general integral $I(\alpha)=\int_a^b g(\alpha,t)\mathrm{d}t$ so that $I'(\alpha)=I_0$ ...
Math Attack's user avatar
2 votes
0 answers
67 views

Closed form for $\psi^{1/k}(1)$, where $k$ is an integer

I have proven the identity $$ \sum_{k=1}^{\infty} \dfrac{\operatorname{_2F_1}(1, 2, 2-1/t,-1/k)}{{k}^{2}} = Γ(2-\dfrac{1}t){\psi^{1/t}(1)}+\psi(-\dfrac{1}t)(\dfrac{1}t(1-\dfrac{1}t))+\gamma(1-\dfrac{1}...
Aiden McDonald's user avatar
0 votes
0 answers
104 views

Is this divergent series, convergent?

Examining the series $\sum_{n=1}^{\infty} \frac{1}{nx}$ alongside its integral counterpart reveals insights into its convergence. Notably, the integral over intervals from $10^n$ to $10^{n+1}$ yields ...
Diogo Sousa's user avatar
1 vote
2 answers
82 views

Upper rectangle area sum to approximate 1/x between $1\leq x\leq 3$

I am trying to figure out how to use rectangles to approximate the area under the curve $1/x$ on the interval $[1,3]$ using $n$ rectangle that covers the region under the curve as such. Here is what I ...
Remu X's user avatar
  • 1,071
2 votes
2 answers
99 views

Prove $\frac12\left(\psi\left(\frac{x+1}2\right)-\psi\left(\frac x2\right)\right)=\psi(x)-\psi\left(\frac x2\right)-\ln2$

Desmos suggests that$$\frac12\left(\psi\left(\frac{x+1}2\right)-\psi\left(\frac x2\right)\right)=\psi(x)-\psi\left(\frac x2\right)-\ln2$$Where $\psi$ is the digamma function. I can write the LHS as $$\...
Kamal Saleh's user avatar
  • 6,549
0 votes
0 answers
31 views

Can we compare the arithmetic mean of the ratios given the comparison between individual arithmetic means?

I have positive real random numbers $u_1,\ldots,u_n$ and $v_1,\ldots,v_n$ and $x_1,\ldots,x_n$ and $y_1,\ldots,y_n$. I know that the arithmetic mean of $u_i$'s is greater than the arithmetic mean of $...
zdm's user avatar
  • 452
1 vote
1 answer
95 views

Evaluation of $\int_{0}^{\frac{\pi}{4}} \frac{\log(\log(\tan(\frac{\pi}{4} + x))) \cdot \log(\tan(\frac{\pi}{4} + x)))}{\tan(2x)} \,dx$ [closed]

$$\int_{0}^{\frac{\pi}{4}} \frac{\log(\log(\tan(\frac{\pi}{4} + x))) \cdot \log(\tan(\frac{\pi}{4} + x)))}{\tan(2x)} \,dx$$ $$\int_{0}^{\frac{\pi}{4}} \frac{\log(\log(\tan(\frac{\pi}{4} + x))) \cdot \...
Mods And Staff Are Not Fair's user avatar
2 votes
0 answers
365 views

A sum of two curious alternating binoharmonic series

Happy New Year 2024 Romania! Here is a question proposed by Cornel Ioan Valean, $$\sum_{n=1}^{\infty}(-1)^{n-1} \frac{1}{2^{2n}}\binom{2n}{n}\sum_{k=1}^n (-1)^{k-1}\frac{H_k}{k}-\sum_{n=1}^{\infty}(-1)...
user97357329's user avatar
  • 5,495
5 votes
2 answers
157 views

Show that $\sum_{n=1}^{\infty} \frac{\binom{2n}{n} (H_{2n} - H_n)}{4^n (2n - 1)^2} = 2 + \frac{3\pi}{2} \log(2) - 2G - \pi$

Show that $$\sum_{n=1}^{\infty} \frac{\binom{2n}{n} (H_{2n} - H_n)}{4^n (2n - 1)^2} = 2 + \frac{3\pi}{2} \log(2) - 2G - \pi$$ My try : We know that $$\sum_{n=1}^{\infty} \binom{2n}{n} (H_{2n} - H_{n}) ...
Mods And Staff Are Not Fair's user avatar
1 vote
1 answer
131 views

for any positive numbers $p_k$ how to find the minimum of $\sum_{k=1}^n a_k^2 +(\sum_{k=1}^n a_k)^2$ when $\sum_{k=1}^n p_ka_k=1$? [duplicate]

For any positive numbers $p_k$ how to find the minimum of $\sum\limits_{k=1}^n a_k^2 +(\sum\limits_{k=1}^n a_k)^2$ when $\sum\limits_{k=1}^n p_ka_k=1$? I saw this problem on my problem book and I ...
pie's user avatar
  • 6,563
1 vote
1 answer
129 views

Prove $\sum_{k=j}^{\lfloor n/2\rfloor}\frac1{4^k}\binom{n}{2k}\binom{k}{j}\binom{2k}{k}=\frac1{2^n}\binom{2n-2j}{n-j}\binom{n-j}j$

let $x>1$, $n\in \mathbb N$ and $$P_{n}(x)=\dfrac{1}{\pi}\int_{0}^{\pi}(x+\sqrt{x^2-1}\cos{t})^ndt.$$ Prove that $$P_{n}(x)=\dfrac{1}{\pi}\int_{0}^{\pi}\dfrac{1}{\left(x-\sqrt{x^2-1}\cos{t}\right)^{...
Fergns Qian's user avatar
0 votes
2 answers
80 views

On the convergence of $\sum_{n=0}^\infty(f(x)-T_n\{f\}(x))$

To test the efficiency of the Taylor Series at approximating functions, I was wondering whether$$\sum_{n=0}^\infty(f(x)-T_n\{f\}(x))\tag{$\star$}$$converges, where $T_n\{f\}(x)$ is the degree $n$ ...
Kamal Saleh's user avatar
  • 6,549
0 votes
1 answer
142 views

How to rigorously prove that $e^x = \sum\limits_{n=0}^ \infty \frac{x^n}{n!}$ without defining derivatives? [duplicate]

In my problem book, there was a question: By defining $e= \lim\limits_{n \to \infty}\left( 1+\frac{1}{n} \right) ^n$ prove that $e^x = \sum\limits_{n=0}^ \infty \frac{x^n}{n!}$. this is a strange ...
pie's user avatar
  • 6,563
22 votes
3 answers
1k views

Conjecture: $\sum\limits_{k=1}^nk^m=S_3(n)\times\frac{P_{m-3}(n)}{N_m}$ for odd $m>1 \ ;\ =S_2(n)\times\frac{P_{m-2}'(n)}{N_m}$ for even $m$.

When I was in high school, I was fascinated by $\displaystyle\sum\limits_{k=1}^n k= \frac{n(n+1)}{2}$ so I tried to find the general solution for $\displaystyle\sum\limits_{k=1}^n k^m$ s.t $m \in \...
pie's user avatar
  • 6,563
-1 votes
1 answer
81 views

$\sum _{k=1}^{\infty }{\frac {\coth(k\pi )}{(k\pi )^{4n-1}}}$ [duplicate]

Show that $${\displaystyle \sum _{k=1}^{\infty }{\frac {\coth(k\pi )}{(k\pi )^{4n-1}}}=\sum _{k=0}^{2n}(-1)^{k-1}\,{\frac {\zeta (2k)}{\pi ^{2k}}}\,{\frac {\zeta (4n-2k)}{\pi ^{4n-2k}}}\qquad n\in \...
user avatar
1 vote
2 answers
205 views

Which closed form expression for this series involving Catalan numbers : $\sum_{n=1}^{\infty}\frac{(-1)^{n-1}}{4^nn^2}\binom{2n}{n}$

Obtain a closed-form for the series: $$\mathcal{S}=\sum_{n=1}^{\infty}\frac{(-1)^{n-1}}{4^nn^2}\binom{2n}{n}$$ From here https://en.wikipedia.org/wiki/List_of_m ... cal_series we know that for $\...
Mods And Staff Are Not Fair's user avatar
6 votes
4 answers
241 views

Evaluate $\int_{0}^{1}\{1/x\}^2\,dx$

Evaluate $$\displaystyle{\int_{0}^{1}\{1/x\}^2\,dx}$$ Where {•} is fractional part My work $$\displaystyle{\int\limits_0^1 {{{\left\{ {\frac{1}{x}} \right\}}^2}dx} = \sum\limits_{n = 1}^\infty {\...
user avatar
2 votes
1 answer
78 views

$\frac{(1+x)^n}{(1-x)^3}=a_{0}+a_{1}x+a_{2}x^2+\cdots$ show that ${a_{0}+\cdots+a_{n-1}=\frac{n(n+2)(n+7)2^{n-4}}{3}}$

$$\displaystyle{\frac{(1+x)^n}{(1-x)^3}=a_{0}+a_{1}x+a_{2}x^2+\cdots}$$, show that $$\displaystyle{a_{0}+\cdots+a_{n-1}=\frac{n(n+2)(n+7)2^{n-4}}{3}}$$ When i gave this problem to my friends they said ...
user avatar
2 votes
1 answer
212 views

Calculate the value $\lim_{n\to \infty}\frac{\sum_{j=1}^n \sum_{k=1}^n k^{1/k^j}}{\sqrt[n]{(\sum_{j=1}^n j!)\sum_{j=1}^n j^n}}$

As in title, I want to calculate the following value $$\lim_{n\to \infty}\frac{\sum_{j=1}^n \sum_{k=1}^n k^{1/k^j}}{\sqrt[n]{(\sum_{j=1}^n j!)\sum_{j=1}^n j^n}}.$$ Here is my attempt: Since $\sum_{j=...
SuperSupao's user avatar
-1 votes
2 answers
96 views

Evaluate $\sum_{m=1}^{\infty} \frac{(-1)^m \mathcal{H}_{2m} }{2m+1} - \frac{1}{2} \sum_ {m=1}^{\infty} \frac{(-1)^m \mathcal{H}_m}{2m+1}$ [duplicate]

Let's declare $\mathcal{G}$ is constant of Catalanand the $\mathcal{H}_m-st$ mharmonic term. Let it be shown that: $$\displaystyle{\sum_{m=1}^{\infty} \frac{(-1)^m \mathcal{H}_{2m} }{2m+1} -\frac{1}{2}...
Mods And Staff Are Not Fair's user avatar
1 vote
2 answers
105 views

Evaluate $\sum_{n=1}^{\infty} (-1)^{n+1} H_n \left( \frac{1}{n+1} - \frac{1}{n+3} + \frac{1}{n+5} - \ldots \right)$

$$\sum_{n=1}^{\infty} (-1)^{n+1} H_n \left( \frac{1}{n+1} - \frac{1}{n+3} + \frac{1}{n+5} - \ldots \right) = \frac{\pi}{16} \cdot \log(2) + \frac{3}{16} \cdot \log(2) - \frac{\pi^2}{192}$$ $$\sum_{k=...
Mods And Staff Are Not Fair's user avatar

15 30 50 per page
1
2 3 4 5
37