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4 votes
1 answer
254 views

Goldstone theorem in Schwartz

On page 566, Schwartz’s QFT book, to see the $\pi$ is the Goldstone boson, it reads: $$J^\mu=\frac{\partial L}{\partial(\partial_\mu \pi)} \frac{\delta \pi}{\delta \theta}=F_\pi \partial_\mu \pi \tag{...
RicknJerry's user avatar
0 votes
0 answers
158 views

When the EM vector field is given a mass by Higgs mechanism, why isn't this equivalent to a massive photon?

In chapter 6 of Classical Theory of Gauge Fields (Rubakov), we are presented with a scalar field $\phi$ coupled to the electromagnetic vector potential $A_\mu$. In this Lagrangian there is a quartic ...
Oscar S's user avatar
1 vote
1 answer
969 views

Two questions about Goldstone bosons

Let's say we are considering the case of Abelian symmetry, with the Lagrange density given by: $$\mathcal{L}=\frac{1}{2}(\partial_\lambda \sigma)^2 + \frac{1}{2} (\partial_\lambda \pi)^2-V(\sigma^2 +\...
Luka8281's user avatar
  • 789
1 vote
0 answers
258 views

Anderson-Higgs Mechanism

Consider an abelian gauge field coupled with a complex field: $$\mathcal{L}=-\frac{1}{4}F_{\mu\nu}F^{\mu\nu}+(D\varphi)^\dagger D\varphi+\mu^2 \varphi^\dagger\varphi-\lambda(\varphi^\dagger\varphi)^2.$...
Ji Zou's user avatar
  • 131
0 votes
0 answers
269 views

Unitary gauge for spontaneous symmetry breaking

I'm given a lagrangian $$ \mathcal{L} = \partial_{\mu} \Phi^{\dagger} \partial^{\mu} \Phi + m^2 \Phi^{\dagger} \Phi - \lambda (\Phi^{\dagger} \Phi)^2 $$ where $m^2 > 0, \lambda > 0$. This ...
Kamil's user avatar
  • 701
5 votes
2 answers
663 views

What is spontaneous in spontaneous symmetry breaking

When we say spontaneous symmetry breaking what do we mean by "spontaneous"? The dictionary, for a non native speaker, relates it to the absence of an external stimulus. In QFT and SM it simply says ...
user avatar
1 vote
1 answer
84 views

Can we modify the Standard Model to fully break $SU(2)_L \times U(1)_Y$ symmetry?

I'm trying to understand how to see if a gauge symmetry would be fully or partially broken on Higgsing. Specifically I am looking at Lagrangians of the form $$ \mathcal L = - \frac{1}{4} {F_a}_{\mu \...
Borun Chowdhury's user avatar
2 votes
0 answers
153 views

Breaking of supersymmetric QED in the O'Raifeartaigh model

The action for supersymmetric QED is \begin{align} S_{\text{SQED}} = \int d^4x\left\{8d(x)^2- F_{\mu\nu}(x)F^{\mu\nu}(x) - 4i\lambda(x)\sigma^{\mu}\partial_{\mu}\bar{\lambda}(x)+ |F_L(x)|^2 + |F_{\...
QuantumMechanic's user avatar
14 votes
1 answer
714 views

What is "broken symmetry"?

For reference, I come from a mathematics background (mostly differential geometry). I have a very limited understanding of upper-level physics (I'm currently trying to fix this). This is my current ...
Robin Goodfellow's user avatar
1 vote
1 answer
417 views

Spontaneous symmetry breaking - potential minima

In spontaneous symmetry breaking, you expand the Lagrangian around one of the potential minima and write down the Feynman rules using this new Lagrangian. Will it make any difference to your Feynman ...
nightmarish's user avatar
  • 3,203
0 votes
1 answer
97 views

Elecric field equations of motion

I'm reading this paper Quantum Time Crystals, Frank Wilczek, Center for Theoretical Physics, about time crystals, and in the situation described there is a particle of unit mass and charge $q$, ...
proton's user avatar
  • 1,407
1 vote
4 answers
450 views

Lagrangian and finding equations of motion

I am given the following lagrangian: $L=-\frac{1}{2}\phi\Box\phi\color{red}{ +} \frac{1}{2}m^2\phi^2-\frac{\lambda}{4!}\phi^4$ and the questions asks: How many constants c can you find for which $\...
MSB's user avatar
  • 385
4 votes
3 answers
1k views

Why do we need $SU(2)\times U(1)$ invariant mass terms if the symmetry will be broken anyway?

In the SM we can not add fermionic mass terms like $m \overline{e}_R e_L$ to the Lagrangian since these terms are not invariant under $SU(2)\times U(1)_Y$. After introducing the Higgs in the unitary ...
Statics's user avatar
  • 1,230
-1 votes
1 answer
281 views

Understanding standard model and symmetry

I just want to know whether my understanding regarding standard model and symmetry is correct or utter nonsense. The standard model is the (yet incomplete) Lagrangian of the universe. The Lagrangian ...
Alex Janzik's user avatar
5 votes
2 answers
1k views

What is classical Lagrangian? The Bare one or renormalized one? Are counterterms quantum corrections to renormalized Larangian?

EDIT When one talks about the “classical Lagrangian” of a field, does one mean the renormalized Lagrangian with physical/renormalized masses and physical/renormalized couplings and without ...
SRS's user avatar
  • 26.8k
9 votes
2 answers
488 views

Quantum Anomalies and Quantum Symmetries

In Quantum Field Theories (QFT) there is a well known phenomenon of anomalies, where a classical symmetry is broken in the quantum theory due to a so called anomaly. This symmetry breaking can be ...
itamarhason's user avatar
3 votes
2 answers
439 views

Determination of the ground state of a field theory

Consider the Spontaneous symmetry breaking in the theory $$\mathcal{L}=\frac{1}{2}\partial_\mu\phi\partial^\mu\phi-\frac{\mu^2}{2}\phi^2+\frac{\lambda}{4!}\phi^4.$$ By the ground state of a classical ...
SRS's user avatar
  • 26.8k
2 votes
1 answer
213 views

Poincare non-invariance in real world and field theory

This may be a very blunt question but I wonder why we always use Poincare invariant Lagrangians in field theory. After all, the entire world around us is by no means homogeneous, isotropic and so on. ...
SRS's user avatar
  • 26.8k
5 votes
1 answer
805 views

Why do we need spontaneous symmetry breaking in Lagrangian formalism?

I have always struggled with the concept of spontaneous symmetry breaking. It seems to me that many others don't find it very intuitive as well, but that could be just me having difficulties with the ...
Dee's user avatar
  • 844
5 votes
1 answer
282 views

How does one prove that the current of a spontaneously broken symmetry generates a particle?

I am having a hard time arguing that, after spontaneous breaking of a continuous symmetry of a field Lagrangian, local fluctuations around the vacuum can be interpreted as particles (without referring ...
user46837's user avatar
  • 211
3 votes
1 answer
1k views

What to do with a $\phi$ term in a Lagrangian?

I am considering a Lagrangian that is of the following form: $$\mathcal{L}=-{1\over 2}\partial_\mu\phi\partial^\mu\phi+2\mu^2\phi^2+2\sqrt{6}{\mu^3\over \lambda}\phi + {9\mu^4\over 2\lambda} + \text{...
Danu's user avatar
  • 16.4k
5 votes
1 answer
927 views

Spontaneous symmetry breaking and 't Hooft and Polyakov monopoles

What is spontaneous symmetry breaking from a classical point of view. Could you give some examples, using classical systems.I am studying about the 't Hooft and Polyakov magnetic monopoles solutions, ...
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