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0 votes
1 answer
42 views

How is the time defined with paths consistent with the idea that we assign time to frames?

In 49:34 of this lecture by Frederic Schuller, it is explained that time is a derived quantity defined through this integral: $$\tau = \int_{\lambda_o}^{\lambda_1} \sqrt{ g(v_{\gamma}, v_{\gamma}) }$$...
Cathartic Encephalopathy's user avatar
0 votes
1 answer
59 views

Sorts of relativistic effect around black holes [closed]

There are many effects around black holes. In particular it is possible to study the motion of geodesics, calculate tidal tensors, lense-thirring effetcs and so on. So, beyond tidal effects, geodesic ...
BasicMathGuy's user avatar
3 votes
0 answers
95 views

What does the Einstein-Hilbert action look like in terms of Riemannian metric of positive signature?

For a 4-manifold to admit a Lorentzian metric is equivalent to that manifold having vanishing Euler characteristic. Any spacetime that admits a Lorentzian metric $g^{\mathcal{L}}$ can have that metric ...
R. Rankin's user avatar
  • 2,847
2 votes
1 answer
101 views

Ultrastatic spacetime and cosmological constant

A spacetime $(\mathcal{M},g)$ is called "ultrastatic", if it admits a set of coordinates such that $$g=-\mathrm{d}t^{2}+h$$ where $h$ is a Riemannian metric, which does not depend on time. ...
B.Hueber's user avatar
  • 854
0 votes
2 answers
121 views

What is the formal criteria that the spacetime is curved?

We suppose we have three scenarios. We are far away from mass and energy in a spot in the universe. We put in free movement a small object $m$, for example, an apple. At the same time, we send a ...
user249018's user avatar
2 votes
1 answer
141 views

Static Spacetime = no cosmological constant?

I stumbled over a strange result, which cannot be true: In the (3+1)-formulation of general relativity, one considers a metric of the type $$g_{\mu\nu}\mathrm{d}x^{\mu}\mathrm{d}x^{\nu}=(-\alpha^{2}+\...
B.Hueber's user avatar
  • 854
1 vote
1 answer
262 views

Gabriel's horn and General Relativity

Is there anything in GR that involves Gabriel's Horn? This idea came to me when I met Flamm's paraboloid. If we take Schwarzschild metric at constant time and $\theta=\pi/2$, we get $$ds^2=\left(1-\...
AFG's user avatar
  • 2,284
16 votes
5 answers
2k views

Is energy "equal" to the curvature of spacetime?

When you are solving the Einstein field equations (EFE), you basically have to input a stress–energy tensor and solve for the metric. $$ R_{\mu \nu} - \frac{1}{2}R g_{\mu \nu} = 8 \pi T_{\mu \nu} $$ ...
Álvaro Rodrigo's user avatar
2 votes
2 answers
260 views

Is a stationary spacetime automatically globally hyperbolic?

Is a stationary spacetime automatically globally hyperbolic? Can one construct a Cauchy-Surface by the existence of a global timelike Killing Vector field?
Mac Menders's user avatar
7 votes
3 answers
1k views

Is spacetime isomorphic to a metric space?

I know that spacetime, as described by General Relativity (GR), is a pseudo-Riemannian manifold. The label "pseudo" is due to the fact that the metric of spacetime entails not only positive ...
Maverick's user avatar
  • 431
2 votes
0 answers
572 views

How to derive the Kerr killing vector?

The Kerr metric have two killing vectors: $$t^{\mu} \equiv (k_{t})^{\mu} = (1,0,0,0)\hspace{5mm} \mathrm{and}\hspace{5mm} \phi^{\mu} \equiv (k_{\phi})^{\mu} = (0,0,0,1). \tag{1}$$ In general, it is ...
M.N.Raia's user avatar
  • 3,085
1 vote
0 answers
41 views

Does a cosmological scale parameter in FLRW split the frame bundle?

Suppose we're looking at an FLRW cosmological metric. Then a set of orthonormal frames on our spacetime in the comoving frame looke like the set: $$\theta=\left\{ a(x^{0})\theta^{i},\theta^{0}\right\} ...
R. Rankin's user avatar
  • 2,847
2 votes
0 answers
95 views

Can the Einstein tensor be written as an integral over real spacetime?

Background We know the Stress-energy tensor can be written as: $$ T^{\mu \nu} = \int \mathcal{N}(x,p,t) p^\mu \otimes p^\nu \frac{d V_p}{E}$$ where $\mathcal{N}(x,p,t)$ is the distribution function, $...
More Anonymous's user avatar
4 votes
2 answers
619 views

Can we just take the underlying set of the spacetime manifold as $\mathbb{R^4}$ for all practical purposes?

In mathematical GR and also in some informal GR presentations (eg: MTW), manifolds are always mentioned before talking about GR... but now I am starting to wonder.. if it even actually neccesary? In ...
Cathartic Encephalopathy's user avatar
4 votes
1 answer
435 views

Foundational considerations in definition of Newtonian Spacetime

My doubt comes from lecture 08 on Theoritische Mechanik by Frederic Schuller. He gives definition of Newtonian Space time as followg: A Newtonian Spacetime is a quintuple of structures $(M,\mathcal{O}...
Cathartic Encephalopathy's user avatar

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