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0 answers
59 views

Interchange of differentiation and summation in infinite sums

Is it possible to interchange differentiation and summation for infinite but also uniformly convergent sums, like: $\dfrac{d}{dx} \sin{x} = \dfrac{d}{dx}\sum_{n=0}^\infty (-1)^{n} \, \dfrac{x^{2n + 1}}...
0 votes
0 answers
67 views

Is it possible to rewrite this sum in terms of some power series?

Is it possible to rewrite this sum in terms of some power series, maybe some cosine power series? $$\sum_{n=0}^{\infty} \dfrac{x^{2n}}{2^{2n}(n!)^2}$$
-1 votes
1 answer
64 views

Finding the nth sum of a series [closed]

I am to find the sum of a series that takes this format $ \sum_{i=1}^{n}\frac{1}{i^\beta} $ $ \beta $ is a positive real number How to approach the partial sum of the above series and can obtain its ...
0 votes
1 answer
59 views

Suppose $\sum_{i = 1} a_i \sum_{i = 1} b_i < \infty$. If $\sum_{i = 1} a_i = \infty$, what does it say about $(b_i)$?

Let $(a_i), (b_i)$ be two non-negative sequence. Suppose $\sum_{i = 1} a_i \sum_{i = 1} b_i < \infty$. If $\sum_{i = 1} a_i = \infty$, what does it say about $(b_i)$? Does it necessarily mean that ...
1 vote
4 answers
190 views

How do I express the sum $(1+k)+(1+k)^2+\ldots+(1+k)^N$ for $|k|\ll1$ as a series?

Wolfram Alpha provides the following exact solution $$ \sum_{i=1}^N (1+k)^i = \frac{(1+k)\,((1+k)^N-1)}{k}.$$ I wish to solve for $N$ of the order of several thousand and $|k|$ very small (c. $10^{-12}...
9 votes
3 answers
13k views

Formula for finite power series

Are there any formula for result of following power series? $$0\leq q\leq 1$$ $$ \sum_{n=a}^b q^n $$
0 votes
1 answer
59 views

$\sum_{n=0}^{\infty} {n \choose y} p^{y+1}(1-p)^{2n-y}$

I am stuck in finding the sum of $\sum_{n=0}^{\infty} {n \choose y} p^{y+1}(1-p)^{2n-y}$. The sum looks quite similar to a negative binomial sum but I can't really find the exact form. Can anyone help?...
6 votes
3 answers
325 views

Integral Representation of a Double Sum

Let us assume we know the value of $x$ and $y$. I'm trying to write the following double sum as an integral. I went through many pages and saw various methods but I'm completely lost with my problem. $...
0 votes
1 answer
54 views

Question about this power series

I know that $\displaystyle\sum_{n=0}^{+\infty} \dfrac{(-1)^nx^{2n+1}}{2n+1}$ is the power series expansion for $f(x) = \tan^{-1}x$. The interval of convergence for this series is $(-1,1]$. If I ...
0 votes
0 answers
32 views

I don't know how to solve this summation of series

Here is the question $\sum_{x=1}^{\infty} 2^{x(t-1)}$, where $t$ is a constant Compare this summation with $Z^c$, where $Z \geq 0$, and specify for what values of $Z$ and $c$, such that $\sum_{x=1}^{\...
0 votes
1 answer
58 views

Can we reduce the 3-nested summation into 2-nest summation?

My problem started with the first case that I have : $$ I_{2}=a^{k_1} (a+b)^{k_2} $$ Where $k_1,k_2$ are real positive integers. Using the series expansion : $$ (a+b)^n=\sum_{i_1=0}^{n} \binom{n}{i_1} ...
0 votes
0 answers
65 views

How to find the sum of a power series without knowing the actual power series

How do I find the sum of this series? $$ \sum_{n=1}^{\infty}\frac{(-1)^{n-1}n}{(n+1)2^{n-1}} $$ The approach I wanted to use is to find a power series that can become this number series for a certain ...
0 votes
1 answer
71 views

Evaluate $\sum_{i=2}^{\infty}{\frac{n}{n^2-1}}x^n$

Evaluate $$\sum_{i=2}^{\infty}{\frac{n}{n^2-1}}x^n$$ using the fact that $${\frac{n}{n^2-1}} = {\frac{1}{2(n-1)}} + {\frac{1}{2(n+1)}}$$ So far I have proven that the Radius of Convergence is 1 and ...
2 votes
1 answer
151 views

How to expand the product of Laguerre polynomials into a sum of series?

In the course of my research, I needed a formula and found it, but I can not understand the derivation process of the formula. How to extract the $t^n$ and get the $\theta(m-p)$ in the last step? Can ...
1 vote
2 answers
121 views

Upper bound for infinite sum

Let $x \in (0,1)$, I need to find an upper bound (as good as possible) for the series $$\sum_{n=1}^{\infty}x^n n^k,$$ where $k$ is a natural number larger or equal than $2$, i.e., $k=2,3,4,\dots$. My ...

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