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0 votes
1 answer
59 views

$\sum_{n=0}^{\infty} {n \choose y} p^{y+1}(1-p)^{2n-y}$

I am stuck in finding the sum of $\sum_{n=0}^{\infty} {n \choose y} p^{y+1}(1-p)^{2n-y}$. The sum looks quite similar to a negative binomial sum but I can't really find the exact form. Can anyone help?...
Iron Maiden 42's user avatar
0 votes
2 answers
69 views

Infinite sum power series

I would like to show $$ \sum_{r=0}^{\infty}\frac{1}{6^r} \binom{2r}{r}= \sqrt{3} $$ I have tried proving this using telescoping sum, limit of a sum, and some combinatorial properties but I couldn't ...
user735447's user avatar
1 vote
1 answer
89 views

Evaluating $\sum^n_{x=1}{2x-1\choose x}t^x$

Is there any technique that I can use to evaluate $$\sum^n_{k=1}{2k-1\choose k}t^k, \quad \forall t\in\left(0,\frac{1}{4}\right)$$ It can be shown that the series converges even if $n\to \infty$ ...
Andeanlll's user avatar
10 votes
2 answers
2k views

Find the value $\binom {n}{0} + \binom{n}{4} + \binom{n}{8} + \cdots $, where $n$ is a positive integer.

Given $$(1+x)^n= \binom {n}{0} + \binom{n}{1} x+ \binom{n}{2} x^2+ \cdots + \binom {n}{n} x^n.$$ Find the value $\binom {n}{0} + \binom{n}{4} + \binom{n}{8} + \cdots $, where $n$ is a positive ...
Samar Imam Zaidi's user avatar
4 votes
3 answers
466 views

Series with Binomial Coefficients

I need to get a closed form for this series $$\sum_{x=0}^{\infty} x {z \choose x} \lambda ^ x \mu^{z-x}$$ I know that that $\sum_{x=0}^{\infty} {z \choose x} \lambda ^ x \mu^{z-x} = (\lambda + \mu)^z$...
Agnishom Chattopadhyay's user avatar
3 votes
1 answer
224 views

Closed form of the sum of the product of three binomial coefficients

I encountered with this kind of series from the calculation in quantum optics: $$\sum_{n,m=0}^\infty \sum_{k,l=0}^{\min(n,m)}\binom{n}{k}\binom{m}{l}\binom{n+m-k-l}{m-k}A^{n+m}B^kC^l$$ Provided that ...
generic properties's user avatar
4 votes
3 answers
159 views

Find the sum of the $\sum_{m=k}^{+\infty}\binom{m}{k}(1-p)^k\cdot p^{m-k}$

Let $0<p<1$,Find the sum $$\sum_{m=k}^{+\infty}\binom{m}{k}(1-p)^k\cdot p^{m-k}$$
math110's user avatar
  • 93.6k
1 vote
3 answers
197 views

Find the radius of convergence of the series $y=\sum_{n=0}^{\infty}\binom{p}{n} x^{n}$

Let $p\in R$ Find the radius of convergence of the series: $$y=\sum_{n=0}^{\infty}\binom{p}{n} x^{n}$$ Show that y satisfies the differential equation $(1+x)y'=py$ and initial condition $y(0)=1$...
Kristin's user avatar
  • 359
3 votes
0 answers
120 views

Finding a closed form for this summation

I have been trying to derive a few identities using some bell polynomials and a technique i have come up with and i came across this summation: $$ \rho(n,k) = \sum_{j=0}^k {k \choose j} {\frac{-j}{2} ...
Eric L's user avatar
  • 1,957
7 votes
2 answers
731 views

Prove $(1-x)^{2k+1} \sum\limits_{n\ge 0}\binom{n+k-1}{k}\binom{n+k}{k} x^n = {\sum\limits_{j\ge 0} \binom{k-1}{j-1}\binom{k+1}{j} x^j} $

I stumbled upon the identity $$(1-x)^{2k+1} \sum\limits_{n\ge 0}\binom{n+k-1}{k}\binom{n+k}{k} x^n = {\sum\limits_{j\ge 0} \binom{k-1}{j-1}\binom{k+1}{j} x^j}. $$ The right-hand side is a polynomial. ...
Johann Cigler's user avatar