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-1 votes
0 answers
54 views

Summation involving the closest integer to $\sqrt n$ [closed]

Let $f(n)$ be the integer closest to $\sqrt n$. Evaluate $$\sum_{n=1}^\infty\frac{\left(\frac32\right)^{f(n)}+\left(\frac32\right)^{-f(n)}}{\left(\frac32\right)^n}$$ In this question, I was able to ...
2 votes
0 answers
102 views

$x_{1}=\frac{1}{x_{1}}+x_{2}=\frac{1}{x_{2}}+x_{3}=\ldots=\frac{1}{x_{n-1}}+x_{n}=\frac{1}{x_{n}}$; prove that $x_{1}=2\cos\frac{\pi}{n+2}$ [closed]

If $x_{1}, x_{2}, x_{3}, \ldots, x_{n}$ are $n\geq 2$ positive real numbers such that $ x_{1}=\frac{1}{x_{1}}+x_{2}=\frac{1}{x_{2}}+x_{3}=\ldots=\frac{1}{x_{n-1}}+x_{n}=\frac{1}{x_{n}}$, prove that $...
2 votes
1 answer
82 views

If $M:=\sum\limits_{k=1}^{\frac{n(n+1)}{2}}\lfloor\sqrt{2k}\rfloor$ How to Find $\frac{n^3+2n}{M}$?

$$M:=\sum\limits_{k=1}^{\frac{n(n+1)}{2}}\lfloor\sqrt{2k}\rfloor$$ Find $\frac{n^3+2n}{M}$ This problem was on a problem book. It is easy to find $M$ If $n$ is odd, $\ m=\frac{n+1}{2} $ and $$M= \...
18 votes
12 answers
17k views

How to prove this binomial identity $\sum_{r=0}^n {r {n \choose r}} = n2^{n-1}$?

I am trying to prove this binomial identity $\displaystyle\sum_{r=0}^n {r {n \choose r}} = n2^{n-1}$ but am not able to think something except induction,which is of-course not necessary (I think) here,...
1 vote
0 answers
48 views

Is there a rule for using parentheses or brackets after the summation symbol to indicate what is included in the sum? [duplicate]

Using parentheses or brackets removes ambiguity but is it necessary?
1 vote
3 answers
93 views

Evaluating $\sum_{\substack{i+j+k=n \\ 0\leq i,j,k\leq n}} 1$

I need to find the sum $$\sum_{\substack{i+j+k=n \\ 0\leq i,j,k\leq n}} 1$$ For $n=1$ we have the admissible values of $(i,j,k)$ as: $(1,0,0),(0,1,0), (0,0,1)$ $$\sum_{\substack{i+j+k=1 \\ 0\leq i,j,...
2 votes
1 answer
104 views

Enquiry on a claim in Titchmarsh. [closed]

There is a claim on p.107 of Titchmarsh's ''The theory of the Riemann zeta function'', that if $0<a<b \leq 2a$ and $t>0$, then the bound $$\sum_{a <n <b} n^{-\frac{1}{2}-it} \ll (a/t)^{...
1 vote
2 answers
187 views

summing binomial coefficiens related

$$ \mbox{If}\quad s_{n} = \sum_{k = 0}^{n}\left(-4\right)^{k} \binom{n + k}{2k},\quad\mbox{how to prove}\quad s_{n + 1} + 2s_{n} + s_{n - 1} = 0\ ?. $$ One of my student had this question in his exam....
2 votes
2 answers
398 views

Find the value of $S_1+S_2$

Knowing that $$\sum_{k=1}^{\infty}\frac{1}{k^2}=\frac{\pi^2}{6}$$ and $$S_i=\sum_{k=1}^{\infty}\frac{i}{(36k^2-1)^i}$$ Find value of $S_1+S_2$ i tried splitting: $$\frac{1}{36k^2-1}=\frac{1}{2}\...
-1 votes
1 answer
55 views

Expressing $\sum_{b=0}^a\sum_{c=0}^b c$ in terms of $a$ [closed]

Summation with the form: $$\sum_{b=0}^a\sum_{c=0}^b c$$ I am not aware of any rule about chaining sums and getting a value in terms of the variable $a$.
0 votes
1 answer
15 views

Solve for variable f when f is in a denominator function of a sum

I have the following equation which I need to solve for f: $\frac{X}{fY} = \sum_t^{T-1}\frac{A(t)}{f\cdot B(t)+1}$ While this seems very solvable, it has stumped an entire group of physics students. ...
8 votes
3 answers
565 views

Finding sum : ${\mathop{\sum\sum\sum\sum}_{0\le i\lt j\lt k\lt l\le n }} \,1$

Finding the value of: $${\mathop{\sum\sum\sum\sum}_{0\le i\lt j\lt k\lt l\le n }} 1$$ I know a similar question was asked on this site earlier, but I couldn't understand the method used there. Link ...
3 votes
2 answers
117 views

$1\binom{20}1+2\binom{20}2+3\binom{20}3+\dots+19\binom{20}{19}+20\binom{20}{20}$

$$1\binom{20}1+2\binom{20}2+3\binom{20}3+\dots+19\binom{20}{19}+20\binom{20}{20}$$ I solved it by letting the sum be $S$, then adding the sum to itself but taking the terms from last to first and then ...
0 votes
1 answer
54 views

Why is $\sum_{m=0}^{\lfloor xs\rfloor} 2 \binom{s}{m} p^m (1-p)^{s-m} \leq 2\exp{\left(-\frac{2(\lfloor xs\rfloor - sp)^2}{s}\right)}$

I am trying to understand few of the mathematical steps I have encountered in a paper, there are two of them (a) $\sum_{m=0}^{\lfloor xs\rfloor} 2 \binom{s}{m} p^m (1-p)^{s-m} \leq 2\exp{\left(-\frac{...
1 vote
1 answer
80 views

Sum related to Binomial Coefficients [duplicate]

Calculate:- $$\sum_{r=1}^{2023} \frac{(-1)^{r-1}r}{2024 \choose r}$$ And generalise the result if possible. I've tried to reduce this to a telescopic sum but could not do it. I've also made a ...

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