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4 votes
1 answer
322 views

The axiom of regularity and the real numbers

I'm having trouble understanding how there can be sufficiently many distinct elements for $\mathbb{R}$ to exist with its properties and yet still be a set. (The ...
nobody's user avatar
  • 151
0 votes
3 answers
3k views

Using only the field axioms of real numbers prove that $(-1)(-1) = 1$

Using only the field axioms of real numbers prove that $(-1)(-1) = 1$ (1) I start with an obvious fact:$$0 = 0$$ (2) Add $(-1)$ to both sides of the equation: $$0 + (-1) = 0+ (-1)$$ (3) Zero is the ...
Aemilius's user avatar
  • 3,709
1 vote
3 answers
272 views

Prove, using only the field axioms of real numbers, that $0/0$ is undefined.

Prove, using only the field axioms of real numbers, that $0/0$ is undefined. I have thought about it for a while and come up with an idea how to solve this. First, I would like to prove (using field ...
Aemilius's user avatar
  • 3,709
-1 votes
1 answer
5k views

Using only the field axioms of real numbers, prove that $-x = (-1)x$ [duplicate]

Using only the field axioms of real numbers, prove that $-x = (-1)x$ Ths is how I attempted to solve this problem: $$1+(-1)=0 \iff x(1+(-1))=0\cdot x \iff x+(-1)x=0\iff(-1)x=-x$$ However, I am not ...
Aemilius's user avatar
  • 3,709
0 votes
3 answers
271 views

Using the axioms of real numbers prove that 0 < 1 [closed]

These are the axioms that I am allowed to use: (1) $x + 0 = 0 + x = x$ (2)$x \cdot 1 = 1 \cdot x = x$ (3) $xy = 1 \iff y = \frac{1}{x}$, $x \neq0$ (4) $x+y = 0 \iff y = -x$ (5) $ x(y+z) = xy + xz$ ...
Aemilius's user avatar
  • 3,709
9 votes
2 answers
838 views

axioms of real numbers without multiplication

Consider the axioms of real numbers https://en.wikipedia.org/wiki/Real_number#Axiomatic_approach and suppose we remove the multiplication operation and its properties. Do we loose something? I have ...
Emanuele Paolini's user avatar
0 votes
1 answer
73 views

How to prove this theorem using field axioms of real numbers?

I need to prove that $0*a=a*0=0$ I'm guessing I have to use the existence of inverse axiom. But I'm not sure how the proof goes. Thanks a lot in advance!
Andres Romero's user avatar
0 votes
2 answers
2k views

How to prove the theorems of algebra using axioms?

Like the vast majority of math students I'm having trouble with proofs. I would like to get some advice on how to approach proofs. What are the steps that need to be done?, how do I know that the ...
Andres Romero's user avatar
0 votes
1 answer
176 views

Axiomatics of Real Numbers - should $0\neq 1$ be considered as axiom?

I am analysing axiomatic approach to defining real numbers. There are two axioms that postulate existence of $0$ and $1$, namely (according to my notes): There exists an element $0\in\mathbb{R}$ such ...
mz71's user avatar
  • 908
2 votes
4 answers
532 views

Isn't it obvious that $0$ and $1$ are distinct?

The field axioms for the real number system contain the following statements concerning the existence of neutral or identity elements for addition and multiplication: (1) There exists a real number,...
user avatar
1 vote
1 answer
105 views

Proof of |x · y| = |x| · |y| using axioms of real numbers

I'm trying to prove |x · y| = |x| · |y| using only the axioms of real numbers. I'm using the definition of the modulus function to be below. I thought I should start by distinguishing four cases like (...
user avatar
0 votes
1 answer
109 views

Proving some basic algebraic statements using the axioms of the real numbers

I am trying to rigorously understand how algebra works by deriving everything from the axioms of the real numbers. I thought this wouldn't be too difficult but it seems I don't have any idea where to ...
esotechnica's user avatar
7 votes
0 answers
701 views

Geometric basis for the real numbers

I am aware of the standard method of summoning the real numbers into existence -- by considering limits of convergent sequences of quotients. But I never actually think of real numbers in this way. I ...
P i's user avatar
  • 2,146
1 vote
1 answer
24 views

If $x+y=(x_1y_1, ..., x_ny_n)$ and $c\cdot '\ x=x^c_1, ..., x^c_n$, how to show that with these two operation $V$ is a subspace?

Let $V=(R^+)^n=\{(x_1, ..., x_n)| x_i\in R^+$for each $i\}$. In $V$ define a vector sum operation $+'$ by $x+y=(x_1y_1, ..., x_ny_n)$ and scalar multiplication $\cdot '$ by $c\cdot '\ x=x^c_1, ..., x^...
1412's user avatar
  • 871
4 votes
2 answers
1k views

Axiomatic definition of the real numbers and uncountability

There are several approaches in defining the real numbers axiomatically and suppose that we have some set of axioms $A$ which completely characterize rational numbers and which does not mention ...
Farewell's user avatar
  • 5,016

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