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22 votes
1 answer
1k views

Prove all 4 axioms of "less than" are necessary (for real numbers)

One way to define an ordered field is as a field $F$ with a relation $<$ that satisfies: For all $x,y \in F$, exactly one of $x<y$, $x=y$, $y<x$ holds. For all $x,y,z \in F$, if $x<y$ and ...
Misha Lavrov's user avatar
1 vote
1 answer
271 views

How can we show that if $|x| \le 1/n$ for all natural numbers, n, then $x = 0$?

I was thinking about how to define the real number system axiomatically, and can't find anywhere a proof that $$\left[\forall n \in \mathbb{N}\left(|x| \le \frac{1}{n}\right)\right] \Rightarrow [x = 0]...
Micob's user avatar
  • 13
0 votes
2 answers
123 views

How can I prove this statement without using reduction to absurdity?

$\forall a,b\in\mathbb R[\forall c\in \mathbb R(c>a\implies c>b)\implies a\ge b]$
Peter Whang's user avatar
0 votes
2 answers
60 views

Transform a totally ordered set to a structure that is isomorphic to (R,+,.,≤)

So let $(M,\le_M)$ be a totally ordered set. Can we define $+$ and $.$ to make $M$ isomorphic to $(\mathbb{R},+,.,\le)$? I mean the well known axioms. To let this possible: $M$ is not bounded above ...
rl1's user avatar
  • 123
3 votes
1 answer
206 views

Abstracting Magnitude Measurement Systems (i.e. subsets of ${\mathbb R}^{\ge 0}$) via Archimedean Semirings.

I did some googling but could not find any easily accessible theory so I am going to lay out my ideas and ask if they hold water. Definition: A PM-Semiring $M$ satisfies the following six axioms: (1)...
CopyPasteIt's user avatar
  • 11.5k