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0 votes
1 answer
70 views

If $0\leq A\leq B$ and $C\geq0$ then does $0\leq AC\leq BC$?

Let $H$ be a complex Hilbert space with inner product $\langle\cdot,\cdot\rangle$. We say $A\geq 0$ if $\langle Ax,x\rangle\geq0$ for all $x\in H$. If $0\leq A\leq B$ and $C\geq0$ then does $0\leq AC\...
schrodingerscat's user avatar
1 vote
0 answers
34 views

Meaning of "smooth finite-rank operators $Q$ in $L^2(\mathbb R^d)$"

What does it mean for a finite-rank operator to be "smooth"? How can one finite-rank operator be smoother than another? For me, a finite-rank operator on $L^2(\mathbb R^d)$ has an expression ...
schrodingerscat's user avatar
1 vote
1 answer
84 views

Operator theory: nonnegative operator $Q$ less than an orthogonal projection $P$ satisfies $PQ=QP$

Suppose that we have a Hilbert space $\mathcal{H}$, an orthogonal projection $P$ (i.e. $P=|\Psi\rangle\langle\Psi|$ for some $\Psi\in\mathcal{H}$ with $\|\Psi\|=1$) and another non-negative bounded ...
Ooooscar's user avatar
0 votes
1 answer
40 views

If $A$ is trace-class on $L^2(\mathbb R^2)$ then $\mathbb 1(-\Delta\leq 1)A\mathbb 1(-\Delta\leq 1)$ is finite-rank. [closed]

I am trying to prove that if $A$ is trace-class on $L^2(\mathbb R^2)$ then $\mathbb 1(-\Delta\leq 1)A\mathbb 1(-\Delta\leq 1)$ is a finite-rank operator, where $\mathbb 1(-\Delta\leq 1)$ is defined on ...
schrodingerscat's user avatar
1 vote
1 answer
65 views

An inequality for Schatten norms with a compact self-adjoint operator

Let $Q$ be a compact self-adjoint operator on $L^2(\mathbb R,\mathbb C)$. Notice that $(1-\Delta)^{s}$ is a positive (and hence self-adjoint) operator on $H$ for any $s>0$. We denote by $\mathfrak ...
schrodingerscat's user avatar
3 votes
1 answer
130 views

Commutator bertween shift operator and "position" operator

I was studying the shift operator in quantum mechanics from wikipedia and in the commutator section explains that for a shift operator $\hat T(x)$ and a position operator $\hat x$, the commutator $\...
Daniel Muñoz's user avatar
0 votes
1 answer
59 views

In what sense is $\breve{g}(x-y)/(2\pi)^n$ the integral kernel of $g(-i\nabla)$?

It is said in Trace Ideals and Their Applications by Barry Simon that the integral kernel of the operator $g(-i\nabla)$ on $L^2(\mathbb R^n)$ is given by $\breve{g}(x-y)/(2\pi)^n$. Indeed, for any $\...
schrodingerscat's user avatar
1 vote
1 answer
80 views

Hartree equation in density matrix formalism is equivalent to a system of Hartree equations

I want to prove that: If the density matrix $$\gamma(t):=\sum_{j=1}^N|u_j(t)\rangle\langle u_j(t)|=\sum_{j=1}^N\langle u_j(t),\cdot\rangle u_j$$ solves $$i\partial_t\gamma(t)=[-\Delta+w*\rho,\gamma],$...
schrodingerscat's user avatar
4 votes
1 answer
145 views

Definition of ground state?

In quantum mechanics, a ground state is an eigenstate of the hamiltonian with the minimal eigenvalue and its existence is guaranteed by appropriate theorems. At least that's how it's defined in ...
Kelly's user avatar
  • 305
1 vote
1 answer
42 views

Find self-adjoint of $P=|a \rangle \langle b |$

Let $P$ be an operator s.a. $P=|a \rangle \langle b |$ and $P|f \rangle = \langle b | f \rangle | a \rangle $. Find the self-adjoint and the $P^2$ operator. My attempt: We know to find the self ...
lebong66's user avatar
  • 463
4 votes
1 answer
175 views

Are quantum state (density) operators unique?

For context, the following question is related to my question on Physics SE. Now for the question. Consider the following requirements on an operator $\rho$ on a Hilbert space (or on a rigged Hilbert ...
EE18's user avatar
  • 1,143
1 vote
1 answer
69 views

For projection matrices, which vector of the outer product should be complex conjugated?

I have a conjugation wrong somewhere in my definitions, and I can't work out where it is. I want to define the standard matrix for a projection operator. If you can provide correct and standard ...
Mikkel Rev's user avatar
  • 1,849
2 votes
1 answer
321 views

On the usage of derivative in operator theory

In quantum mechanics, we work with linear operators on Hilbert spaces $\mathscr{H}$. Suppose I have two bounded ones, defined on the same space $A, B: \mathscr{H}\to\mathscr{H}$. It seems to me there ...
ric.san's user avatar
  • 141
0 votes
1 answer
437 views

Show that the adjoint of two operators is the sum of the adjoints

Problem Show that for any two operators $\hat{A}$ and $\hat{B}$, the adjoint $(\hat{A} + \hat{B})^\dagger = \hat{A}^\dagger + \hat{B}^\dagger$. Do so using the integral form of the definition of ...
10GeV's user avatar
  • 1,381
0 votes
1 answer
55 views

Positive linear operator inequality

I'm stuck proving the following inequality. Let $H$ autohermitian operator such that $$\langle u|H|u\rangle\geq0\qquad\forall |u\rangle$$ Proof that $$|\langle u|H|v\rangle|^2\leq\langle u|H|u\rangle\...
math3341's user avatar

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