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1 vote
0 answers
30 views

Partial fractions with a repeated factor [duplicate]

I am looking to find a derivation, or a intuitive explanation as for why a partial fraction with a repeated factor needs to include a factor in the expansion for each power possible. How does one ...
James Chadwick's user avatar
2 votes
2 answers
245 views

How can i do the following partial decomposition?

I need to prove that: $$ \frac{1}{(x-a)(x-b)} = \frac{1}{(b-a)(x-b)}- \frac{1}{(b-a)(x-a)}, $$ and I must note that I need to go from the left expression to the right (because of the exercise). So, I ...
Miguel Simões's user avatar
-2 votes
2 answers
109 views

I found an interesting question but I keep getting stuck in a loop. [closed]

Find all values of A, B, C and C such that: $$ \frac{x-1}{(x-1)(x-2)(x-2)} = \frac{A}{x+1} + \frac{B}{x+2} + \frac{C}{(x-2)^2} $$ I keep getting into a loop in which: $$ x - 1 = Ax^2 - 4Ax + 4A + Bx^2 ...
Durian's user avatar
  • 15
2 votes
3 answers
83 views

Converting a proper fraction into partial fraction

For solving integration-related questions, a rational proper fraction of the form $\frac{px^{2}+qx+r}{(x-a)(x^{2}+bx+c)}$ is decomposed into the sum of the expressions, $$\frac{A}{x-a} + \frac{Bx+C}{x^...
Sasikuttan's user avatar
1 vote
2 answers
62 views

Contour integral over function $P(x)/Q(x)$: $P(x) = 1$ and $Q(x)$ can be broken into linear factors

a. Let $z_1,z_2,...,z_n$ be distinct complex numbers $(n \geq 2)$. Show that in the partial fractions decomposition \begin{equation} \frac{1}{(z-z_1)(z-z_2)\cdots(z-z_n)} = \frac{A_1}{z-z_1}+\frac{A_2}...
Alex's user avatar
  • 142
0 votes
3 answers
190 views

Partial Fractions Decomposition-Unsure Which Method To Use When

So I was working on this problem and could not use the cover up method to solve it. I was getting the wrong answer. Find B. $$\frac{1}{s^2(s^2+4)}=\frac{A}{s}+\frac{B}{s^2}+\frac{Cs+D}{s^2+4}$$ $$s=0: ...
Throw Away's user avatar
3 votes
2 answers
224 views

Usual method of partial fractions decomposition over the reals seems to fail.

I assumed that it would be straightforward to find the partial fraction decomposition over the reals of the rational function $$f(x) = \frac{1}{(x^2 +1)^2}.$$ However, when I try what I thought would ...
splitcomplexes's user avatar
0 votes
0 answers
180 views

Question on partial fractions; why numerator has to be one lower degree than denominator?

When decomposing into a partial fraction, why does the highest degree of the numerator have to be one lower than the numerator? For example: $\frac{x}{x^3-1} = \frac{a}{x-1} + \frac{bx+c}{x^2+x+1}$ ...
Shooting Stars's user avatar
0 votes
1 answer
230 views

Express in partial fractions and expand the terms using binomial expansion up to $x^3$ [closed]

$$ \frac{2}{(1-x)\left(1+x^{2}\right)} $$ This is then split into partial fractions $$ \frac{A}{1-x}+\frac{B x+C}{1+x^{2}} $$ Computing this i had gotten \begin{equation} 2=A\left(1+x^{2}\right)+(B x+...
AMN's user avatar
  • 161
1 vote
1 answer
124 views

Which integrating technique should I use?

Just some context: In the mathematical course, I have undertaken this year, I've just learnt how to integrate using partial fractions, substitution(not trig though, just a variable) and integrating ...
Shooting Stars's user avatar
0 votes
2 answers
106 views

Solution to $\int\frac{\ln(1+x^2)}{x^2}dx$

Q: $\int\frac{\ln(1+x^2)}{x^2}dx$ Here is my entire working: So, overall, I started with the reverse product rule, then onto reverse chain rule and then tried to partial fraction, however, I still ...
Shooting Stars's user avatar
2 votes
4 answers
85 views

Finding the partial fractions decomposition of $\frac{9}{(1+2x)(2-x)^2} $

So this is basically my textbook work for my class, where we are practicing algebra with partial fractions. I understand the basics of decomposition, but I do not understand how to do it when then the ...
verygood101's user avatar
2 votes
5 answers
97 views

How to decompose $\frac{1}{(1 + x)(1 - x)^2}$ into partial fractions

Good Day. I was trying to decompose $$\frac{1}{(1 + x)(1 - x)^2}$$ into partial fractions. $$\frac{1}{(1 + x)(1 - x)^2} = \frac{A}{1 + x} + \frac{B}{(1 - x)^2}$$ $$1 = A(1 - x)^ 2 + B(1 + x)$$ ...
MangoPizza's user avatar
  • 1,858
2 votes
0 answers
299 views

Are there applications of partial fraction decomposition ( of a rational function) outside integration problems?

I've been recently acquainted with a well known technique called " partial fraction decomposition" which allows, for example to express $\frac {x} {x^2-1}$ as $\frac {1}{2(x+1)} + \frac {1} ...
Vince Vickler's user avatar
1 vote
1 answer
393 views

Skepticism concerning Heaviside's "Cover-up Method" for partial fraction decomposition

I was reading this paper from MIT and it introduces Heaviside’s Cover-up Method for partial fraction decomposition. In that paper in Example $1$ it solves a problem using that method and just when ...
user avatar
1 vote
1 answer
95 views

Find the partial fraction for: $\frac{1}{(x^2+1)^2(x-1)}$

I want to find the partial fraction of: $$\frac{1}{(x^2+1)^2(x-1)}$$ Although I want this expressed through the format of finding the complex number that goes into $x$ so that I can get this equation ...
Stackcans's user avatar
  • 361
1 vote
2 answers
87 views

Find the partial fraction: $\frac{x^2}{(x-1)^2(x-2)^2(x-3)}$

I'm trying to find the partial fraction for the following $\frac{x^2}{(x-1)^2(x-2)^2(x-3)}$ by the process of long-division, here's what I have tried: Leaving $(x-3)$ as it is in the denominator and ...
Stackcans's user avatar
  • 361
1 vote
2 answers
90 views

Partial Fraction Decomposition of $\frac{z+4}{(z+1+2i)(z+1-2i)}$

I have the fraction $\frac{z+4}{(z+1+2i)(z+1-2i)}$. I want to partial decompose this fraction, but I am not seeing how to do it. I know that the answer is a=$\frac{1}{2}$+$\frac{3i}{4}$ and b=$\frac{1}...
Learn_Math's user avatar
2 votes
3 answers
52 views

Clarification on partial fraction expansion

I would like to use the cover up method for the following equation. $$\frac{1}{x^2(x+1.79)}$$ and it breaks down into $$\frac{A}{x}\quad\frac{B}{x^2}\quad\frac{C}{(x + 1.79)}$$ I realize that you ...
Livingstone's user avatar
1 vote
3 answers
284 views

Why does this partial fraction decomposition work, even with division by $0$? [duplicate]

Here is how partial fraction decomposition works. First, take a fraction like $\frac{1}{n(n+1)}$. You can express this fraction as the sum $\frac{A}n + \frac{B}{n+1}$ for some constants $A$ and $B$. ...
Some Guy's user avatar
  • 2,685
2 votes
3 answers
82 views

Compute $\sum_{n=1}^\infty (\frac34)^n \frac{7n+32}{n(n+2)}$

Question: Compute $$\sum_{n=1}^\infty \left(\frac34\right)^n \frac{7n+32}{n(n+2)}$$ I first did the partial fraction decomposition into: $$\sum_{n=1}^\infty \left(\frac34\right)^n \frac{16}n - \sum_{...
Edmund Chang's user avatar
1 vote
5 answers
75 views

how to solve this into partial fractions

I'm having a bit of a hard time putting this into partial fractions: $$\frac{10}{x^2+2x+1+\pi^2}.$$ I know that the roots of the denominator are $-1 \pm i\pi$, but I dont know how to proceed on puting ...
Lusvi's user avatar
  • 17
0 votes
2 answers
179 views

Finding nth derivative of $\frac{1}{x^4+4}$

I am supposed to find the nth order derivative of: $$\frac{1}{x^4+4}$$ I tried to resolve into partial fractions. But it didn't work out for me. Edit- where I am stuck $$\frac{1}{x^4+4}=\frac{1}{(x-1+...
S.S's user avatar
  • 1,239
1 vote
1 answer
64 views

Evaluation of a telescoping sum

I have come to a problem in a book on elementary mathematics that I don't understand the solution to. The problem has two parts : a.) Factorize the expression $x^{4} + x^{2} + 1$ b.) Compute the ...
scipio's user avatar
  • 595
1 vote
1 answer
53 views

Decomposing fractions

I am not sure how these two terms are equal from this wiki: $$ I(X,Y) = KL(p(x,y) || p(x)p(y)) = \sum_{x,y}p(x,y) \log[\frac{p(x,y)}{p(x)q(y)}] \\ I(X,Y) = \sum_{x,y}p(x,y) \log[\frac{p(x,y)}{p(y)}...
Jonathan's user avatar
  • 736
0 votes
1 answer
131 views

Partial Fractions With Repeated Quadratics

I'm told that given a function $f(x)=\frac{P(x)}{Q(x)}$, if $\deg(P)>\deg(Q)$ then $f$ is improper, which makes sense when I think of real numbers like $5/2$. And in this case we would have to do ...
Lex_i's user avatar
  • 2,072
4 votes
1 answer
651 views

Partial fractions zero coefficients

In partial fractions, there can be terms in the coefficients in the partial form that turn out to be zero. One case of this is when the variable is "linear" in a power of $x$, for example, ...
jamie's user avatar
  • 701
3 votes
2 answers
93 views

Binomial Expansion Of $\frac{24}{(x-4)(x+3)}$

Can somebody help me expand $\frac{24}{(x-4)(x+3)}$ by splitting it in partial fractions first and then using the general binomial theorem? This is what I've done so far: $$\frac{24}{(x-4)(x+3)}$$ $$=\...
mikejacob's user avatar
  • 327
2 votes
1 answer
597 views

Why do some partial fractions have x or a variable in the numerator and others don't?

Why do rational expressions like $\left(\frac{1}{(x-2)^3}\right)$ do not have x in the numerator of the partial fraction but a rational expression like $\left(\frac{1}{(x^2+2x+3)^2}\right)$ does have ...
IlIllIlllllllIllIlIllIIlIII 's user avatar
0 votes
0 answers
52 views

Partial Fractions $\frac{2}{s^2+4} = \frac{As+B}{s^2+4}$

I have this relatively simple partial fraction $$\frac{2}{s^2+4} = \frac{As+B}{s^2+4}$$ I multiply each side by $(s^2+4)$ and all that remains is $2 = As + B$. Then can I match the coefficients up ...
Evan Kim's user avatar
  • 2,409
1 vote
1 answer
81 views

Arbitrarily long decomposition into partial fractions.

$$\int \frac{dx}{x(x+p)(x+2p)(x+3p)...(x+(n-1)p)}= ?$$ I'm trying to solve this integral, and as I usually do in these cases, I break the expression into partial fractions, but I find this case ...
Woody Woodstock's user avatar
1 vote
1 answer
209 views

Reasoning behind the resolution of partial fractions when denominator is the product of linear factors where some of them are repeating

The following text is from Mathematics for Class XII by Dr. R.D.Sharma, chapter "Indefinite Integrals", topic "Integration of Rational Algebraic Functions by using Partial Fractions&...
Vishnu's user avatar
  • 1,826
1 vote
2 answers
67 views

Partial fraction decomposition of $\frac{1}{x^a(x+c)^b}$

We have the partial fraction decomposition $$\frac{1}{x^a(x+c)^b}=\frac{d_a}{x^a}+\frac{d_{a-1}}{x^{a-1}}+...+\frac{d_{1}}{x}+\frac{e_b}{(x+c)^b}+\frac{e_{b-1}}{(x+c)^{b-1}}+...+\frac{e_{1}}{x+c},$$ ...
TheGrandDuke's user avatar
0 votes
2 answers
61 views

Integration of rational of polynomials

I want to evaluate the indefinite integral for: $$ \int\frac{x^3+3x−2}{x^2-3x+2}dx,\quad \text{for } x>2 $$ I did long division and factoring, simplifying it to $$ \int x+3\,dx + \int\frac{10x-8}{(...
Hash88's user avatar
  • 115
0 votes
1 answer
53 views

How does this imply $x = z^2$?

I read that given the equation: $$ x + \frac{1}{x} = z^2 + \frac{1}{z^2} $$ , we can imply that $x=z^2$. But that $x=z^2$ is not obvious to me... I know we can match the variables on the left hand ...
Link L's user avatar
  • 735
0 votes
1 answer
94 views

Partial fractions Integration - Distributing Coefficients

Given the following Integral $\int \frac{2x^3+ 2x^2+ 2x+ 1}{x^2 (x^2+1)}$ I would expand my fractions like the following $\frac{A}{x} + \frac{B}{x^2}+\frac{Cx+D}{x^2+1}$ When I look at the ...
maxcraft's user avatar
2 votes
4 answers
90 views

How to get the value of $A + B ?$

I have this statement: If $\frac{x+6}{x^2-x-6} = \frac{A}{x-3} + \frac{B}{x+2}$, what is the value of $A+B$ ? My attempt was: $\frac{x+6}{(x-3)(x+2)} = \frac{A(x+2) + B(x-3)}{(x-3)(x+2)}$ $x+6=(...
ESCM's user avatar
  • 3,173
0 votes
1 answer
200 views

Resolve into partial fractions $(x^2 + 3x - 5)/[(2x - 7)(x^2 + 3)^2]$

Resolve into partial fractions $\frac{x^2 + 3x - 5}{(2x - 7)(x^2 + 3)^3}$ The question has to do with the denominator being one linear and a repeated quadratic factor. Although, I am familiar with ...
Nzewi Ernest Kenechukwu's user avatar
1 vote
3 answers
253 views

Integrating quadratics in denominator

I'm following a book on Calculus that introduces partial fraction expansion. They discuss common outcomes of the partial fraction expansion, for example that we are left with an integral of the form: ...
BMBM's user avatar
  • 2,493
0 votes
3 answers
51 views

Partial fraction expansion inquiry

How can I expand $\frac{a + 5}{(a^2-1)(a+2)}$ so that the sum of partial fractions is equal to $\frac{1}{a-1} - \frac{2}{a+1} + \frac{1}{a+2}$ ? Thanks in advance!
Rolando González's user avatar
-1 votes
2 answers
60 views

Equations with 3 unknowns [closed]

I have this equation/problem: Find the value of A and B if 2/(x−5)(x+3) = A /(x−5) + B/(x+3) How can I solve/approach this? Thank you for your advice. Regards Lisa
Lisa Levi's user avatar
2 votes
6 answers
222 views

Why partial fraction decomposition of $\frac{1}{s^2(s+2)}$ is $\frac{A}{s}+\frac{B}{s^2}+\frac{C}{(s+2)}$?

Can someone please explain why: $$\frac{1}{s^2(s+2)}=\frac{A}{s}+\frac{B}{s^2}+\frac{C}{(s+2)}$$ And not:$$\frac{1}{s^2(s+2)}=\frac{A}{s^2}+\frac{B}{(s+2)}$$ I'm a bit confused where the extra s ...
stuart's user avatar
  • 533
0 votes
1 answer
41 views

How would I apply partial fraction expansion to this expression?

$$\displaystyle\frac{1}{X\bigg(1-\dfrac{X}{Y}\bigg)\bigg(\dfrac{X}{Z}-1\bigg)}$$ I want it in the form $$\frac{A}{X} + \frac{B}{(1-\dfrac{X}{Y})}+\frac{C}{(\dfrac{X}{Z}-1)}$$where I am required to ...
glaceauoxford's user avatar
0 votes
1 answer
912 views

Confusion about "picking values of $x$", partial fraction decomposition

One of the methods of decomposing a fraction and finding the constants, $A, B, C,$ etc., is to "pick values of $x$". For example, to find $A$ and $B$ of $${{3x}\over(x-1)(x+2)} = {A\over(x-1)} + {B\...
dlp's user avatar
  • 945
0 votes
0 answers
70 views

Mistake in the computation via partial fractions

This is a computation made in Titchmash's Introduction to Zeta functions. I was trying to reverse the computation. However, I kept missing factors. Consider $\frac{1- xyz^2}{(1-z)(1-xz)(1-yz)(1-xyz)}...
user45765's user avatar
  • 8,550
0 votes
1 answer
82 views

About a statement of partial fraction in an answer

I'm reading this answer of The logic behind partial fraction decomposition, I think my question is too basic and not directly related to the answer so I don't comment there. I don't understand why: ...
Kindred's user avatar
  • 229
2 votes
4 answers
79 views

Show $\frac{1}{1-\frac{x}{3-x}+\frac{x}{4-x}}$ is equivalent to $1+\frac{1}{2}\left(\frac{1}{2-x}-\frac{3}{6-x}\right)$ for $\lvert x\rvert < 1$

I have been asked to show that $$\frac{1}{1-\frac{x}{3-x}+\frac{x}{4-x}}$$ is equivalent to writing $$1+\frac{1}{2}\left(\frac{1}{2-x}-\frac{3}{6-x}\right)$$ From here I just tried to work out the ...
ElMathMan's user avatar
0 votes
3 answers
48 views

How do we make $A(x+1)(x^2+4x+5)+B(x^2...$ to be equal to $2x^2$??

$$\frac{2x^2}{(x+1)^2(x^2+4x+5)}$$ $$2x^2=A(x+1)(x^2+4x+5)+B(x^2+4x+5)+(Cx+D)(x+1)^2$$ We can get $B=1$ if we put $-1$ for $x$. But I don't know how can we solve for $A$, $C$ and $D$ since we can't ...
Viktor Dimitrioski's user avatar
1 vote
3 answers
121 views

Partial Fraction problem solution deviates from the Rule

Question: Compute $\displaystyle \int\frac{x^2+1}{(x^2+2)(x+1)} \, dx$ My Approach: As per my knowledge this integral can be divided in partial Fraction of form $\dfrac{Ax+B}{x^2+px+q}$ and then do ...
user avatar
0 votes
1 answer
48 views

Find the Partial Fraction Decomposition

$\frac{2x^5+3x^4-3x^3-2x^2+x}{2x^2+5x+2}$, I am not sure as to where to start with this one; I have already done the factoring process of the denominator but not sure how to continue the algebraic ...
Tylor Gonzalez's user avatar

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