All Questions
6
questions
-2
votes
2
answers
109
views
I found an interesting question but I keep getting stuck in a loop. [closed]
Find all values of A, B, C and C such that:
$$
\frac{x-1}{(x-1)(x-2)(x-2)} = \frac{A}{x+1} + \frac{B}{x+2} + \frac{C}{(x-2)^2}
$$
I keep getting into a loop in which:
$$
x - 1 = Ax^2 - 4Ax + 4A + Bx^2 ...
- 15
0
votes
1
answer
82
views
About a statement of partial fraction in an answer
I'm reading this answer of The logic behind partial fraction decomposition, I think my question is too basic and not directly related to the answer so I don't comment there. I don't understand why:
...
- 229
0
votes
3
answers
212
views
Partial Fractions help!?
$A + C = 0$
$-4A + B - 8C + D = 1$
$3A + 16C - 8D = -29$
$-12A + 3B + 16D = 5$
How do I equate the coefficients? Please provide steps an an explanation.
- 33
1
vote
1
answer
559
views
Partial Fraction Expansion of $12\frac{x^3+4}{(x^2-1)(x^2+3x+2)}$
Find the vector $(A,B,C,D)$ if $A$, $B$, $C$, and $D$ are the coefficients of the partial fractions expansion of
$$12\frac{x^3+4}{(x^2-1)(x^2+3x+2)} = \frac{A}{x-1} + \frac{B}{x+2} + \frac{C}{x+1} + \...
- 1,283
3
votes
2
answers
20k
views
Separating addition terms in denominator
If I have a fraction such as:
$\frac{1+d(6-4a)}{1-a+d(7-4a)}$
then how can I separate it so I have it as $\frac{1}{1-a}+(some-term)$
Thanks.
- 63
2
votes
2
answers
228
views
problem with partial fraction decomposition
I want to do partial fraction decomposition on the following rational function:
$$\frac{1}{x^2(1+x^2)^3}$$
So I proceed as follows:
$$\begin{align}
\frac{1}{x^2(1+x^2)^3} &= \frac{A}{x} + \frac{...
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