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Questions tagged [metric-spaces]

Metric spaces are sets on which a metric is defined. A metric is a generalization of the concept of "distance" in the Euclidean sense. Metric spaces arise as a special case of the more general notion of a topological space. For questions about Riemannian metrics use the tag (riemannian-geometry) instead.

2 votes
0 answers
33 views

Linear Analysis – Examples 1-Q5 General $l^p$ spaces vs $l^1, l^\infty$

Let $1<p<\infty$, and let $x$ and $y$ be vectors in $l_p$ with $\left \|x \right \|=\left \|y \right \|=1$ and $\left \|x +y \right \|=2$, how to prove $x=y$? I know how to prove for $p=2$ ...
HIH's user avatar
  • 477
1 vote
3 answers
90 views

Proving that the closure of a set is closed directly

Currently working through Rudin's principle's of mathematical analysis. I am trying to prove directly that the closure of a set is closed but am hitting a wall on one part of the proof. Namely, if we ...
user8083's user avatar
  • 199
2 votes
1 answer
55 views

Infinite-dimensional cube $[0,1]^\mathbb N$ compact/complete under certain metrics?

Consider the infinite-dimensional cube $[0,1]^\mathbb N := \{ (x_i)_{i=1}^\infty \ | \ 0 \le x_i \le 1 \ \forall i \}.$ This space can be equipped with certain metrics. Below are two of them. $d_\...
Euclid's user avatar
  • 1,450
1 vote
1 answer
108 views

Determine the convexity of a ball in a metric space.

Let $V$ be the set of all Lebesgue integrable functions. $V$ forms a vector space with respect to general function addition and scalar multiplication. Let $X \subset V$ is the set of positive and ...
Mixi Andrew's user avatar
-2 votes
2 answers
21 views

Proving that boundedness of a metric space defined in terms of radius and diameters are same without usage of triangle inequality

Diameter boundedness:A metric space $M$ is bounded if for all points $p,q \in M$, we have $d(p,q) <= R$ Radius Boundedness: A metric space is bounded if and only if for every point $p \in M$, there ...
Cathartic Encephalopathy's user avatar
1 vote
1 answer
50 views

Two sets having strongly seperated points are strongly seperated themselves

Definition :- Two sets $A$ and $B$ are strongly seperated if there exist open neighbourhoods $U$ and $V$ such that $A \subseteq U , B \subseteq V , U\cap V=\phi$ Question :$A$ and $B$ are two compact ...
user-492177's user avatar
  • 2,589
1 vote
1 answer
48 views

What are the Chebyshev sets for the taxicab metric?

A set of points $S \subseteq \mathbb{R}^n$ is called a Chebyshev set if the metric projection w.r.t $S$ is single-valued. That is, for every point $x\in \mathbb{R}^n$, there is a unique point $y\in S$ ...
Erel Segal-Halevi's user avatar
0 votes
0 answers
22 views

Computing Component of Vector Outside Convex Hull of Set of Vectors

I have a set of points $\{x_n\}_{n=1}^N$ where $x_n \in \mathbb{R}^D$. I have another vector $y \in \mathbb{R}^D$. I'd like to efficiently compute the component of $y$ that lives outside the convex ...
Rylan Schaeffer's user avatar
2 votes
0 answers
44 views

Always Closed Metric Space is Complete

I am trying to prove that Given a metric space $Y$, if for every metric space $X \supseteq Y$, $Y$ is $X$-closed, then $Y$ is complete. by contradiction or contraposition, such that I don't use the ...
n1lp0tence's user avatar
-2 votes
1 answer
69 views

Rudin Ch 4 exercise 3: the zero set of a continuous function is closed

Let $f$ be a continuous real function on a metric space $X$. Let $Z(f)$ (the zero set of $f$) be the set of all $p \in X$ at which $f(p) = 0$. Prove that $Z(f)$ is closed. My attempt Let $p$ be a ...
Vivek's user avatar
  • 1
2 votes
1 answer
55 views

Manhattan metric proof

I would like to check my proof of the triangle inequality of the manhattan metric in $\mathbb{R}^2$ i.e: that if $d(x,y) = |x_1 - y_1| + |x_2 - y_2|$ then $d(x,y) \leq d(x,z) + d(z,y)$. My proof is as ...
STRICKLAND_7's user avatar
3 votes
3 answers
79 views

Understanding the Proof of Relative Openness Theorem in Rudin's Principles of Mathematical Analysis

I'm having trouble understanding Rudin's proof for the theorem stating: "Suppose $Y \subseteq X$. A subset $E$ of $Y$ is open relative to $Y$ if and only if $E = Y \cap G$ for some open subset $G$...
user8083's user avatar
  • 199
1 vote
1 answer
49 views

Are there compact metric spaces with Hausdorff measure equal to 0 or infinty

I am looking for examples of non-empty metric spaces which are compact with Hausdorff dimension $\alpha$, and have either its $\alpha$-dimensional Hausdorff measure equal to $0$ or its $\alpha$-...
Cosine's user avatar
  • 412
6 votes
2 answers
287 views

A complete metric space contains a convergent sequence or an infinite discrete subset

Theorem. Let $X$ be an infinite complete metric space. Then there is an injective convergent sequence in $X$ or there exists $\varepsilon>0$ and an infinite $\varepsilon$-discrete subset $A\...
Martin Sleziak's user avatar
1 vote
1 answer
105 views

Parametric Equation of a unit circle when the angle between $x$-axis and $y$-axis is not $90$ degrees

I know in regular Cartesian coordinates the parametric equation for a unit circle is $x=\cos(\theta)$, $y=\sin(\theta)$, and if the $x$ coordinates are stretched by an amount $a$, and the $y$ ...
Anders Gustafson's user avatar

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