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0 votes
3 answers
79 views

Completeness meaning (complete basis vs complete metric space)

Today my professor started talking about the formalism of QM. We talked about the eigenvectors of a Hermitian operator (over Hilbert space) as a "complete set". He also mentioned briefly ...
R24698's user avatar
  • 389
2 votes
1 answer
55 views

Infinite-dimensional cube $[0,1]^\mathbb N$ compact/complete under certain metrics?

Consider the infinite-dimensional cube $[0,1]^\mathbb N := \{ (x_i)_{i=1}^\infty \ | \ 0 \le x_i \le 1 \ \forall i \}.$ This space can be equipped with certain metrics. Below are two of them. $d_\...
Euclid's user avatar
  • 1,450
2 votes
0 answers
44 views

Always Closed Metric Space is Complete

I am trying to prove that Given a metric space $Y$, if for every metric space $X \supseteq Y$, $Y$ is $X$-closed, then $Y$ is complete. by contradiction or contraposition, such that I don't use the ...
n1lp0tence's user avatar
6 votes
2 answers
287 views

A complete metric space contains a convergent sequence or an infinite discrete subset

Theorem. Let $X$ be an infinite complete metric space. Then there is an injective convergent sequence in $X$ or there exists $\varepsilon>0$ and an infinite $\varepsilon$-discrete subset $A\...
Martin Sleziak's user avatar
1 vote
1 answer
44 views

What happen if we eliminate only one point from a Cauchy complete metric space?

Consider $\mathbb{R}$ with the usual metric. We know that $\mathbb{Z}$ is complete as a subspace of $\mathbb{R}$ (because is closed), and $\mathbb{Z} \setminus \{0\}$ is still complete. But if we take ...
Hilbert's Minion's user avatar
3 votes
1 answer
90 views

Does complete and separable Wasserstein space imply the completeness of the base space?

Also asked on MathOverflow. Let $(Z,d)$ be a metric space, and for $p\geq 1$, consider a metric space $(W_p,d_{W^p})$ defined by The Wasserstein Space $\begin{align}W_p = \{\mu|\mu\textrm{ is a Borel ...
Kaira's user avatar
  • 1,565
0 votes
0 answers
14 views

Why metric equivalence does not preserve completeness but norm equivalence does? [duplicate]

I was studying Functional analysis when I came across the normed space equivalence i.e. equivalent norms. I already proved that equivalent norms on a vector space $X$ over field $\mathbb{R}$ or $\...
Rudra's user avatar
  • 23
0 votes
1 answer
34 views

Completeness preserved under specific homeomorphism

Problem: Let $(X,d)$ be a complete metric space, $(Y,d')$ a metric space, and $f\colon X\to Y$ a homeomorphism, such that there exists a $c>0$, for which $$c\cdot d(x,y)\leq d'(f(x), f(y)).$$ Show ...
categoricallystupid's user avatar
-1 votes
1 answer
45 views

Find an example to show Cantor intersection theorem does not hold if we eliminate one condition

Cantor's intersection theorem states that: Let $(X,d)$ be a complete metric space, and let $A_1\supset A_2\supset...$ be an infinite chain of nonempty, closed, bounded subsets of $X$. Suppose further ...
user avatar
0 votes
1 answer
50 views

Subspace of real valued functions on [0,1] is complete

I’m currently working on the following problem: Let $X$ denote the set of nondecreasing functions $f:[0,1]\to\mathbb{R}$. We endow $X$ with the sup metric. Prove that $X$ is complete. I notice that if ...
Michael Wang-Wakamatsu's user avatar
2 votes
2 answers
154 views

Can we include a metric space into its completion?

Let $(X,d)$ be a metric space and let $(X^*,d^*)$ denote its completion (via equivalence classes of Cauchy sequences in $X$). Let $f:X \to X^*$ be an isometry such that $f(X)$ is dense in $X^*$. Now ...
Alphie's user avatar
  • 4,827
0 votes
1 answer
46 views

Compact-open topology not always complete with Arens' metric

For an infinite-type surface $S$ with complete metric $d$ and compact exhaustion $\{K_n\}_{n=1}^\infty$, Vlamis, in "Notes on the Topology of Mapping Class Groups" Appendix A, defines a ...
riv's user avatar
  • 1
4 votes
1 answer
85 views

Using only the universal property, prove that $X$ is dense in its Cauchy completion

Long ago, I learned about the Cauchy completion of metric spaces via the usual explicit construction of quotienting the set of Cauchy sequences. For a metric space $X$, let $\hat X$ denote this Cauchy ...
Atom's user avatar
  • 4,119
2 votes
2 answers
92 views

On the completeness of a metric space.

Theorem: Consider the metric space $(X, d)$, where $X \subseteq \mathbb{R}$ and $d(x, y) = |f(x) - f(y)|$, with $f$ being a one-to-one (injective) function on its domain $X$. If the range of $f$ is a ...
neelkanth's user avatar
  • 6,100
1 vote
1 answer
122 views

Completeness of $(C^{\infty}(\mathbb{R}),d)$

Let $C^{\infty}(\mathbb{R})$ be the space of all infinitely differentiable complex-valued functions on $\mathbb{R}$. Define the metric \begin{align} d(f,g) = \sum_{n,m=0}^{\infty} 2^{-n-m}\frac{\sup_{...
BasicUser's user avatar
  • 919

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