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Can a finite Wasserstein metric on Euclidean support be embedded in a Euclidean space?

Thanks for everyone's help with understanding finite metric embeddings in Euclidean space. I have a follow-up question. Say we have the Wasserstein distance between $n$ distributions in Euclidean ...
user9998990's user avatar
0 votes
1 answer
55 views

Conditions on a finite metric that guarantees embedding in Euclidean space? [duplicate]

If we have $n$ points in some metric space, do there exist coordinates for the $n$ points in an $n-1$ dimensional Euclidean space with exactly the same pairwise distances as in the original space? ...
user9998990's user avatar
1 vote
0 answers
74 views

The isometry group of a metric space with the topology of pointwise convergence is a topological group

Let $(X,d)$ be a metric space and let $\mathrm{Iso}(X)$ denote the group of isometries of $(X,d)$, where the group operation is the composition. Equip $\mathrm{Iso}(X)$ with the topology of pointwise ...
jenda358's user avatar
  • 511
5 votes
1 answer
247 views

When is isometry space of compact metric space a manifold?

Supposse we have a compact metric space $(X, d)$. Let $(\text{Iso}(X, d), D)$ be a metric space of all isometries $f : X \rightarrow X$ with a metric $D$ defined with: $$D(f, g) = \text{sup}\{d(f(x), ...
Goki's user avatar
  • 271
2 votes
1 answer
98 views

If $A$ and $B$ are countable dense subsets of compact metric space $(X, d)$ with infinitely many isometries, is there isometry such that $f(a) \in B$.

Let $(X, d)$ be a separable and compact metric space with infinitely many isometires. Let $A, B$ be infinitely countable dense subsets of $X$. Is there an isometry $f : X \rightarrow X$ such that $f(a)...
Goki's user avatar
  • 271
-1 votes
1 answer
73 views

Is isometric to $\mathbb R^n$ implies vector space?

Suppose $(E,d_E)$ is a metric space that is isometric to $\mathbb R^3$ with Euclidean distance. I have some impedent : (1) I want to state that $E$ is a metric space of dimension $n$, but as far as I ...
PermQi's user avatar
  • 579
5 votes
2 answers
302 views

Orbits of points in compact metric space when there exists a point that is fixed by all isometries

Let $(X,d)$ be a compact metric space and Iso$(X,d)$ be a set of all isometries $f : X \rightarrow X$. For $x \in X$ orbit of $x$ is defined as: $$\operatorname{Orb}(x) := \{f(x) : f \in \operatorname{...
Goki's user avatar
  • 271
3 votes
1 answer
82 views

A sufficient condition for an isometry to exist between metric spaces

Reminder: An isometry of metric spaces $(X,d)$, $(Y,d')$ is a function $$f:X \to Y$$ Such that for any $s,t \in X$ we have $$d(s,t) = d(f(s),f(t))$$ i.e. It preserves all distances. A homeomorphism of ...
Carlyle's user avatar
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2 votes
0 answers
103 views

Metric Space with No Local Isometries?

We know there are metric spaces with no non-trivial (global) isometries. For example, consider the Euclidean plane $(\mathbb{R}^2, d)$. Let $X \subset \mathbb{R}^2$ be the set $\{(0,0), (1,0),(0,2)\}$....
backtothefuture's user avatar
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0 answers
63 views

prove that every isometry Is also continous [duplicate]

Let $ (X,d_x) $ and $(Y,d_y)$ be metric spaces, an isometry $f:(x,d_x)\rightarrow (y,d_y)$ Is Always continous Proof: A function Is an isometry if keeps distances unaltered therfore $ \forall x_1,x_2\...
MASSIMILIANO MESSINA's user avatar
0 votes
1 answer
213 views

Show that $T$ is a topological embedding of $X$ in itself.

Let $X$ be the set of odd positive fractions with denominator $3$ in lowest terms, except for $\frac13$. $X=\{x\in\Bbb Q^+:3x\in3\Bbb N\pm1\}\setminus\{\frac13\}$ If $a,b$ are 2-adic units, then any 2-...
it's a hire car baby's user avatar
2 votes
0 answers
53 views

What is the sum of the 2-adic values of the orbits of the affine group over 2-adic integers restricted to $ax+b$ where $2^{\nu_2(x)}=2^{\nu_2(b)}$?

Let $\textrm{aff}(\Bbb Z_2)$ be the affine group over 2-adic integers, defined as the linear polynomials $ax+b$ where $a\in\Bbb Z_2^\times$ and $b\in\Bbb Z_2$. A very interesting subset of this group ...
it's a hire car baby's user avatar
1 vote
0 answers
64 views

Isometry Between C[0,1] and C[1,2]

This is not homework, I am just trying to make something clear for myself. I am trying to show that $C([0,1])$ and $C([1,2])$ are isometric. Here both spaces are endowed with the standard sup metric. ...
Mud's user avatar
  • 81
0 votes
1 answer
123 views

Construct on $\mathbb{R}^2$ a norm $\lVert \cdot \rVert$ such that the metric space ($\mathbb{R}^2 , \lVert \cdot \rVert$) is neither isometric to the

Construct on $\mathbb{R}^2$ a norm $\lVert \cdot \rVert$ such that the metric space ($\mathbb{R}^2 , \lVert \cdot \rVert$) is neither isometric to the space ($\mathbb{R}^2 , \lVert \cdot \rVert_2$), ...
wengen's user avatar
  • 1,135
1 vote
1 answer
72 views

If $f_n$, f are isometries, then $\underset{n\to\infty}{\lim}\overset{\infty}{\underset{i=0}{\sum}}2^{-i-1}d(f_n(x_i), f(x_i))=0$.

The Problem: Suppose $(X, d)$ is a complete separable metric space, and $\{x_i\}\subseteq X$ is a countable dense subset. Suppose $(f_n)$ is a sequence of isometries of $X$ such that $\underset{n\to\...
Dick Grayson's user avatar
  • 1,467

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