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4 votes
0 answers
162 views

Determine sum of the series $\sum_{k=1}^\infty\frac{1}{n(n+1)(n+2)}$ [duplicate]

I have the following problem, $$\sum_{k=1}^\infty\frac{1}{n(n+1)(n+2)}$$ And I try to work as follows: Hint: Partial Fraction decomposition: $\begin{aligned} \frac{1}{n(n+1)(n+2)} &= \frac{...
Darío A. Gutiérrez's user avatar
3 votes
2 answers
90 views

Evaluating the limit of the sequence: $\frac{ 1^a + 2^a +..... n^a}{(n+1)^{a-1}[n^2a + n(n+1)/2]}$

My friend gave me this question to solve a few days ago and after I got no way to solve this, I thought I should seek some help. I had to evaluate the limit of the following when $n$ tends to ...
Amritansh Singhal's user avatar
1 vote
4 answers
95 views

How to solve $\lim_{x \to 0} \dfrac{\arctan(x)}{e^{2x}-1}$?

$$\lim_{x \to 0} \dfrac{\arctan(x)}{e^{2x}-1}$$ I have no idea how to do this, initially I thought that perhaps $\lim_{x \to 0} \dfrac{e^x-1}{x} = 1$ might be of use but I don't see how I can rewrite ...
FreddyBlueEyes's user avatar
4 votes
4 answers
334 views

Calculus - Finding limit (NOT L'Hopital's Rule): $\lim_{x \to 1^-}\frac{x^2+x+\sin({\pi\over 2}x)-3}{x-1}$

How do I find this limit? $$\displaystyle{\lim_{x \to 1^-}}\frac{x^2+x+\sin({\pi \over 2}x)-3}{x-1}$$ I am unable to factor the numerator to get rid of the denominator. Can someone please help? ...
user1234's user avatar
  • 293
3 votes
2 answers
60 views

Evaluation of $\lim_{n \to \infty} ((n+1)!\ln (a_n))$

Consider the sequence $(a_n)_{n \geq1}$ such that $a_0=2$ and $a_{n-1}-a_n=\frac{n}{(n+1)!}$. Evaluate $$\lim_{n \to \infty} ((n+1)!\ln (a_n))$$ Could someone hint me as how to achieve value of $a_n$ ...
MathGeek's user avatar
  • 1,367
1 vote
1 answer
59 views

Finding $\lim_{n\to \infty} \frac{1}{n} \sum_{k=1}^n \frac{a^{1+\frac{k}{n}}}{a^{1+\frac{k}{n}}+1} $

As the question says, $$\lim_{n\to \infty} \frac{1}{n} \sum_{k=1}^n \frac{a^{1+\frac{k}{n}}}{a^{1+\frac{k}{n}}+1} $$ where a is a constant, $a>0$.
Larrrrrrrrrry's user avatar
3 votes
1 answer
144 views

$\lim_{z\to -1} (z+1) \sin(\frac{1}{z+1})$, for complex variable $z$.

I want to find this limit for complex variable $z$ $$\lim_{z\to -1} (z+1) \sin(\frac{1}{z+1})$$ In the real case I know $\sin(z)$ is bounded by $-1, 1,$ and the limit is $0$. But in the complex case ...
user95747's user avatar
  • 261
3 votes
1 answer
204 views

A limit using the Euler number: $\lim_{n\rightarrow\infty}\frac{n!}{(n-i)!}\left(\frac{c}{n}\right)^{n-i}$

What is answer of this limit and how can I get it? $c$ and $i$ are constants. $$\lim_{n\rightarrow\infty}\frac{n!}{(n-i)!}\left(\frac{c}{n}\right)^{n-i}$$ I guess it will envolve some Neper/the Euler ...
H.W.'s user avatar
  • 579
1 vote
1 answer
59 views

Finding a limit of a two variable function: $f(x,y)=\frac {\sin(x^2-xy)}{\vert x\vert} $

I have this exercise but not sure if I'm doing it right $$\lim_{(x,y)\to (0,0)} \frac {\sin(x^2-xy)}{\vert x\vert} $$ I assume $\frac {\sin(x^2-xy)}{\vert x\vert}\le\frac {1}{\vert x \vert} $ then ...
Mauro's user avatar
  • 11
6 votes
1 answer
261 views

Find $\lim_{a\to \infty}\frac{1}{a}\int_0^{\infty}\frac{x^2+ax+1}{1+x^4}\cdot\arctan(\frac{1}{x})dx$

Find $$ \lim_{a\to \infty} \frac{1}{a} \int_0^{\infty}\frac{x^2+ax+1}{1+x^4} \arctan\left(\frac{1}{x}\right)dx $$ I tried to find $$ \int_0^{\infty} \frac{x^2+ax+1}{1+x^4}\arctan\left(\frac{...
Brahmagupta's user avatar
  • 4,274
1 vote
5 answers
99 views

Limit of a function of two variables: $\lim_{(x,y) \to 0}\dfrac{x^2y}{17x^2+y^2}$

$$\lim_{(x,y) \to 0} \dfrac{x^2y}{17x^2+y^2}$$ I want to obtain this limit but don't know how to. The most general advice I've found is to convert this function into polar coordinates, so when I do ...
Assam's user avatar
  • 23
1 vote
3 answers
116 views

Find the limit of the sequence $\left( \sqrt {2n^{2}+n}-\sqrt {2n^{2}+2n}\right) _{n\in N}$

My answer is as follows, but I'm not sure with this: $\lim _{n\rightarrow \infty }\dfrac {\sqrt {2n^{2}+n}}{\sqrt {2n^{2}+2n}}=\lim _{n\rightarrow \infty }\left( \dfrac {2n^{2}+n}{2n^{2}+2n}\right) ^{\...
Andi Zhang's user avatar
8 votes
4 answers
540 views

A limit related to super-root (tetration inverse).

Recall that tetration ${^n}x$ for $n\in\mathbb N$ is defined recursively: ${^1}x=x,\,{^{n+1}}x=x^{({^n}x)}$. Its inverse function with respect to $x$ is called super-root and denoted $\sqrt[n]y_s$ (...
Vladimir Reshetnikov's user avatar
9 votes
1 answer
416 views

Closed Form for $~\lim\limits_{n\to\infty}~\sqrt n\cdot(-e)^{-n}\cdot\sum\limits_{k=0}^n\frac{(-n)^k}{k!}$

$\qquad\qquad\qquad$ Does $~\displaystyle\lim_{n\to\infty}\frac{\sqrt n}{(-e)^n}\cdot\sum_{k=0}^n\frac{(-n)^k}{k!}~$ possess a closed form expression ? Inspired by this frequently asked question, I ...
Lucian's user avatar
  • 48.5k
10 votes
3 answers
484 views

Evaluating the limit of a certain definite integral

Let $\displaystyle f(x)= \lim_{\epsilon \to 0} \frac{1}{\sqrt{\epsilon}}\int_0^x ze^{-(\epsilon)^{-1}\tan^2z}dz$ for $x\in[0,\infty)$. Evaluate $f(x)$ in closed form for all $x\in[0,\infty)$ and ...
User001's user avatar

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