Skip to main content

All Questions

1 vote
1 answer
145 views

Evaluate $\lim_{n\to\infty}\prod_{k=1}^n \frac{2n}{e}(\arcsin(\frac{k}{n})-\arcsin(\frac{k-1}{n}))$

I'm trying to evaluate $L=\lim\limits_{n\to\infty}f(n)$ where $$f(n)=\prod\limits_{k=1}^n \frac{2n}{e}\left(\arcsin\left(\frac{k}{n}\right)-\arcsin\left(\frac{k-1}{n}\right)\right)$$ We have: $f(1)\...
Dan's user avatar
  • 25.8k
7 votes
1 answer
209 views

What is the product of the areas of every regular polygon inscribed in a circle of area $1$?

What is a closed form of $P=\prod\limits_{k=3}^{\infty}\frac{k}{2\pi}\sin{\left(\frac{2\pi}{k}\right)}\approx 0.05934871...$ ? This is the product of the areas of every regular polygon inscribed in a ...
Dan's user avatar
  • 25.8k
5 votes
1 answer
115 views

Hidden property of the graph of $y=\tan{x}$: infinite product of lengths of zigzag line segments converges, but to what?

On the graph of $y=\tan{x}$, $0<x<\pi/2$, draw $2n$ zigzag line segments that, with the x-axis, form equal-width isosceles triangles whose top vertices lie on the curve. Here is an example with $...
Dan's user avatar
  • 25.8k
2 votes
4 answers
270 views

Show that $\lim_{n\to\infty}n\left(n\ln{n}+\ln{\sqrt{2}}-n-\sum_{k=1}^n \ln{\left(k-\frac{1}{2}\right)}\right)=\frac{1}{24}$.

I am trying to show that $$L=\lim\limits_{n\to\infty}n\left(n\ln{n}+\ln{\sqrt{2}}-n-\sum\limits_{k=1}^n \ln{\left(k-\frac{1}{2}\right)}\right)=\frac{1}{24}$$ Desmos strongly suggests that this is true,...
Dan's user avatar
  • 25.8k
5 votes
2 answers
134 views

Find $C$ such that $\frac{1}{n}\prod_{k=1}^{n}C\left(\cos{\frac{k\pi}{2(n+1)}}+\sin{\frac{k\pi}{2(n+1)}}-1\right)$ converges to a positive number.

I'm looking for the value of $C$ such that $L=\lim\limits_{n\to\infty}\frac{1}{n}\prod\limits_{k=1}^{n}C\left(\cos{\frac{k\pi}{2(n+1)}}+\sin{\frac{k\pi}{2(n+1)}}-1\right)$ equals a positive real ...
Dan's user avatar
  • 25.8k
5 votes
0 answers
131 views

Infinite product of areas in a square, inscribed quarter-circle and line segments.

The diagram shows a square of area $An$ and an enclosed quarter-circle. Line segments are drawn from the bottom-left vertex to points that are equally spaced along the quarter-circle. The regions ...
Dan's user avatar
  • 25.8k
3 votes
0 answers
121 views

Special property of circle with radius 0.975399...

$4n$ points are uniformly distributed on a circle. Parabolas are drawn in the manner shown below with example $n=4$. The parabolas' vertices are at the center of the circle. The parabolas have a ...
Dan's user avatar
  • 25.8k
6 votes
2 answers
270 views

What is a closed form of this limit? (product of areas in circle with parabolas)

I am looking for a closed form of $L=\lim\limits_{n\to\infty}\prod\limits_{k=1}^n \left(\left(6+\frac{4n}{\pi}\left(\sin{\frac{\pi}{2n}}\right)\left(\cos{\frac{(2k-1)\pi}{2n}}\right)\right)^2-\left(\...
Dan's user avatar
  • 25.8k
16 votes
1 answer
453 views

Closed form for $\lim\limits_{n\to\infty}\prod\limits_{k=1}^n{\left(2-\frac{2n^2-\pi^2+8}{n^2}\cos{\frac{(2k-1)\pi}{n}}\right)}$?

I am looking for a closed form for: $$\lim_{n\to\infty}\prod_{k=1}^n{\left(2-\frac{2n^2-\pi^2+8}{n^2}\cos{\frac{(2k-1)\pi}{n}}\right)}$$ (Wolfram suggests that it's approximately 6.17966.) Context: I ...
Dan's user avatar
  • 25.8k
7 votes
1 answer
342 views

An infinite product for $\frac{\pi}{2}$

Please help prove $$ \begin{align} \frac{\pi}{2}&=\left(\frac{1}{2}\right)^{2/1}\left(\frac{2^{2}}{1^{1}}\right)^{4/(1\cdot 3)}\left(\frac{1}{4}\right)^{2/3}\left(\frac{2^{2}\cdot4^{4}}{1^{1}\...
tyobrien's user avatar
  • 3,557
4 votes
0 answers
72 views

How do I find the finite limits of this infinite product?

What is... $$\lim_{\omega \to \infty} \left( {1 \over {a^{\omega}}} \cdot \prod_{N=1}^{\omega} (1+e^{b \cdot c^{-N}}) \right)$$ I'd like closed form solutions, and in this case that means any ...
Zach466920's user avatar
  • 8,361
8 votes
2 answers
1k views

Infinite Product $\prod_{n=1}^\infty\left(1+\frac1{\pi^2n^2}\right)$

How do I find: $$\prod_{n=1}^\infty\; \left(1+ \frac{1}{\pi ^2n^2}\right) \quad$$ I am pretty sure that the infinite product converges, but if it doesn't please let me know if I have made an error. ...
Kevin's user avatar
  • 81
24 votes
6 answers
6k views

Evaluating the infinite product $\prod\limits_{k=2}^\infty \left ( 1-\frac1{k^2}\right)$

Evaluate the infinite product $$\lim_{ n\rightarrow\infty }\prod_{k=2}^{n}\left ( 1-\frac{1}{k^2} \right ).$$ I can't see anything in this limit , so help me please.
Sherloek holmes's user avatar