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127 questions with no upvoted or accepted answers
4 votes
1 answer
119 views

Solving equations with logarithmic exponent

I need to solve the equation : $\ln(x+2)+\ln(5)=\lg(2x+8)$ With the change of base formula we can turn this into: $\ln(x+2)+\ln(5)=\frac{\ln(2x+8)}{\ln(10)}$ We can also simplify the LHS with the ...
Robin's user avatar
  • 41
4 votes
1 answer
642 views

Find integer $n$ that satisfies $(\lg n)^{2^{100}} <\sqrt{n}$ with $n > 2$

If $(\lg n)^{2^{100}} < {n^{1/2}}$, where $\lg$ is the binary logarithm, then $$(\lg n)^{2^{101}} < n$$ $$2^{101}\lg \lg n < \lg n$$ $$101 < \lg \lg n - \lg \lg \lg n$$ I don't know that ...
shatba's user avatar
  • 79
3 votes
0 answers
78 views

What functions satisfy $f(ax) - f(a(x-1)) > f(b(x+1)) - f(bx)$ for all $a, b \in \mathbb{R}^+$ and $x \in \mathbb{Z}^+$.?

I am looking at a family of functions $f : [0, \infty) \rightarrow [-\infty, \infty)$ satisfying the following property: $$f(bx) - f(b(x-1)) > f(a(x+1)) - f(ax) \quad \text{for all $a, b \in \...
K.C.'s user avatar
  • 31
3 votes
0 answers
66 views

Checking solution of equation with exponentials

I have solved the following equation: $2^x (2+\sqrt{3})^x - 2(1+\sqrt{3})^x = 2$ My approach: since $2+\sqrt{3}=\frac{1}{2}(1+\sqrt{3})^2$ it follows that $(2+\sqrt{3})^x=\frac{1}{2^x}(1+\sqrt{3})^{2x}...
lorenzo's user avatar
  • 4,098
3 votes
0 answers
83 views

How can I solve a system of 3 equations that use logs?

I'm having a bit of trouble solving this system of equations. What would be a good way of solving for the three variables in a question like this? I've tried many different ways of substituting or ...
helloitsme's user avatar
3 votes
0 answers
86 views

Find value of $k$ such that domain of $f(x)$ is $(-\infty \: 2] \cup [6 \:\infty)$

Find value of $k$ such that domain of $$f(x)=\log_{0.5}\left(\log_{4}\left(\log_3[(x-k)^2]\right)\right)$$ is $(-\infty \: 2] \cup [6 \:\infty)$ where $[.]$ is Greatest integer function. For outside $...
Ekaveera Gouribhatla's user avatar
3 votes
0 answers
175 views

solve $y = \frac{A }{\frac{B}{\ln(y/y_0)} - 1} \frac{1}{x^2}$

I'm trying to express y as a function of x, using the following equation : $$ y = \frac{A }{\frac{B}{\ln(y/y_0)} - 1} \frac{1}{x^2} $$ Can anyone help me ? Thanks ! [Edit] - I originally attempted ...
scalpas's user avatar
  • 31
3 votes
0 answers
147 views

Tweaking Reddit's Ranking Algorithm

This image explains how Reddit's Ranking algorithm works. As you know, Reddit is a very high traffic site. Therefore, the post rank decreases quite fast. This algorithm puts emphasis on bringing ...
pewpewlasers's user avatar
2 votes
0 answers
68 views

How to solve the equation $x^{\log_3{(x-1)}} = 3^{(3+\log_3{x})}$ [SOLVED]

I made a mistake copying the question ! it should be $x^{\log_3{(x)}-1} = 3^{(3+\log_3{x})}$. I'm trying to solve the equation: $x^{\log_3{(x-1)}} = 3^{(3+\log_3{x})}$ What I tried: I took the ...
Saiko's user avatar
  • 23
2 votes
0 answers
39 views

Simplifying $\sum_{k=1}^{\log_{2}{n}}\log_{3}{\frac{n}{2^k}}$ in two ways gives different results

I want to calculate the result of $$\sum\limits_{k=1}^{\log_{2}{n}}\log_{3}{\frac{n}{2^k}}$$ I used two below approaches. Both approaches are based on $\log A + \log B = \log (A \times B)$ and $\sum\...
hasanghaforian's user avatar
2 votes
0 answers
39 views

Does every basic exponent property have a corresponding logarithm property and vice versa?

Here is what I'm referring to: For $0 < a \neq 1$, $\,0 < b \neq 1$, and $m,n \in \mathbb{R^+}$, $p = a^m$, $q = a^n,$ $$\begin{align*} a^0 &= 1 \qquad &\qquad \log_a(1) &= 0 \tag{a}\...
Farrel Ahmed's user avatar
2 votes
0 answers
92 views

Subtract two long functions, possible shortcut using derivative?

If $f(x)$ is as follows: $$f(x)=\frac{2-\ln(x+1)}{x^4 +2}$$ what is $f(a+h)-f(a)$? I started this problem but quickly realized that the calculations were going to get difficult and long. But I noticed ...
Andrea Zamora's user avatar
2 votes
0 answers
51 views

Finding the domain of $[\log_{10}(\frac{5x - x^2}{4})]^{1/2}$

The solution given by the book is: I think this is wrong. My solution is: $\frac{5x - x^2}{4}$ $\ge$ $1$ $5x - x^2$ $\ge$ $4$ $5x - x^2 - 4$ $\ge$ $0$ $(-1)(x-1)(x-4)$ $\ge$ $0$ or $(x-1)(x-4)$ $\le$ ...
Nameless's user avatar
  • 425
2 votes
0 answers
27 views

Solving an equation with different bases, each to an unknown power, but with a third value

This is a relatively straightforward question, but neither myself nor my colleagues are able to come up with a tidy solution without brute force: Represent $x$ algebraically, given the equation $$4^{...
Daniel H.'s user avatar
  • 178
2 votes
0 answers
54 views

Is there an easy way to find parameter by three information?

$f(x)=a+b.c^x$ and we know $$f(0)=15\\ f(2)=30\\f(4)=90$$ so put down point in function and have: $$a+b.1=15\\a+b.c^2=30\\a+b.c^4=90$$so $$(2)-(1) \to bc^2-b=30-15\\(3)-(2) \to bc^4-bc^2=90-30\\b(c^2-...
Khosrotash's user avatar
  • 25.2k

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