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3 votes
2 answers
77 views

How to evaluate an expression of higher powers and roots using logarithms?

I am struggling with the following question from a Dutch algebra exam from the 1950s. The instructions are as follows: Calculate with logarithms. $$ x = \frac{\sqrt[3]{(23.57^2 - 15.63^2)}}{{0....
Marinus Lilienthal's user avatar
2 votes
2 answers
648 views

What is wrong with my approach to solving $x^{\log25} + 25^{\log x} = 10\;$?

Found this equation on the web: $$x^{\log25} + 25^{\log x} = 10$$ The person solved by substitution and got $x = \sqrt{10}$ which satisfies the equation. I tried different ways after following the man'...
Frederick's user avatar
  • 119
0 votes
0 answers
30 views

What if a point in $[a,b]$ does not lie in the domain of $f(x)$ while applying IVT

I came across the function $f(x)=x^3\ln(\sin x)$. I tried applying IVT in the interval $\left[-\frac{5 \pi}{4},-\pi\right) \cup\left(0, \frac{3 \pi}{4}\right]$. Now we see that $$\begin{aligned} f\...
Umesh shankar's user avatar
1 vote
2 answers
82 views

Why does $e^{t+4}(t-1)=0$ only yield one solution?

I understand that $e^{t+4}(t-1)=0$ only yields one solution because $e^x >0$ what I am wondering is why you can't $\ln$ to cancel out the $e$ to give $(t+4)(t-1)=0$ This is clearly invalid from ...
AmmarQ's user avatar
  • 11
0 votes
1 answer
130 views

Restrictions on exponent laws

Alright, so i want to add restrictions to this list of exponent laws. The code i will post now is my attempt at writing their restrictions and the laws i want to write restrictions on. SO, please let ...
Al3dium GD's user avatar
-2 votes
1 answer
202 views

How to solve the equation $\log_5x+\log(x+1)=\frac{\log12}{1-\log2}$? [closed]

How can one solve the equation: $$\log_5x+\log(x+1)=\frac{\log12}{1-\log2}$$
somkiat_t's user avatar
  • 117
2 votes
6 answers
384 views

Show that $f(x)$ is an Odd Function

Show that $$f(x) = \ln \left(x+\sqrt{x^2+1}\right)$$ is an odd function. My attempt: $$f(-x)=\ln\left(-x+\sqrt{(-x)^2+1}\right)=\ln\left(-x+\sqrt{x^2+1}\right).$$ How should I proceed? I know that ...
Mathxx's user avatar
  • 7,788
1 vote
2 answers
130 views

logarithmic equation $\log_2(3^x-8)=2-x$

I've been unable to solve the following equation: $$\log_2(3^x-8)=2-x$$ I can arrive at $$3^x-8=2^{2-x}$$ but I'm clueless afterwards. I know that the answer is $x=2$ but cannot arrive to that ...
mathearts's user avatar
2 votes
1 answer
113 views

Solve an equation with the form $y=\left(1+\frac{a}{x}\right)^{bx}+c$

Knowing that $\lim_{x\to \infty}\left(1+\frac{1}{x}\right)^x=e$ and, $\lim_{x\to \infty}\left(1+\frac{a}{x}\right)^{bx}=e^{ab}$ and also, $\lim_{x\to \infty}\left[\left(1+\frac{a}{x}\right)^{bx}+c\...
MattMath's user avatar
1 vote
0 answers
281 views

Removing exponent from equation

I'm trying to solve the following equation numerically: This is problematic, because the term $ t^{\beta_i}_{j} $ becomes extremely large ($> 10000^{300}$), and unrepresentable with typical number ...
larspars's user avatar
  • 111
3 votes
2 answers
264 views

Solving for $x$ : $a^x+b^x=c$

Well the question is to solve for $x$ in $$a^x+b^x=c \tag{a,b,c are constants}$$ Well as of me, I tried to put $\ln{}$ on both sides which does not seem to help. Apart from this I don't seem to have ...
NeilRoy's user avatar
  • 2,221
6 votes
4 answers
996 views

What is the solution to the equation $9^x - 6^x - 2\cdot 4^x = 0 $?

I want to solve: $$9^x - 6^x - 2\cdot 4^x = 0 $$ I was able to get to the equation below by substituting $a$ for $3^x$ and $b$ for $2^x$: $$ a^2 - ab - 2b^2 = 0 $$ And then I tried \begin{align}x ...
Mertcan Ekiz's user avatar
0 votes
2 answers
46 views

Solving for $x$ using $\ln$ or any possible way.

$$ 12.46x=1-(1+x)^{-20} $$ I tried solving for $x$ using $\ln$ and other methods but the only answer i got was 0.8. The correct answer is approximately to $0.05$.
Sourabh Sen's user avatar
6 votes
1 answer
160 views

How to solve the equation $ (x-2)^{\log_{100}(x-2)}+\log_{10}(x-2)^5-12 = 10^{2\log_{10}(x-2)}$?

If $\displaystyle (x-2)^{\log_{10^2}(x-2)}+\log_{10}(x-2)^5-12 = 10^{2.\log_{10}(x-2)}$, then value of $x$ is ... My Try Let$$\log_{10}(x-2) = y \quad \Leftrightarrow \quad (x-2)=10^y .$$ Then$$(10)^{...
juantheron's user avatar
  • 53.7k
2 votes
2 answers
111 views

What is wrong with this solution?

$$ \ln(x) = 1 + \ln(5)$$ $$ x = e^{1+ \ln(5)} = e^{1+5} = e^6$$ What exactly am I doing wrong here?
JohnPhteven's user avatar
  • 2,047

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