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1892 United States presidential election in Delaware

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1892 United States presidential election in Delaware

← 1888 November 8, 1892 1896 →
 
Nominee Grover Cleveland Benjamin Harrison
Party Democratic Republican
Home state New York Indiana
Running mate Adlai Stevenson I Whitelaw Reid
Electoral vote 3 0
Popular vote 18,581 18,077
Percentage 49.90% 48.55%

County Results
Cleveland
  40-50%
  50-60%


President before election

Benjamin Harrison
Republican

Elected President

Grover Cleveland
Democratic

The 1892 United States presidential election in Delaware took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.

Delaware was won by the Democratic nominees, former President Grover Cleveland of New York and his running mate Adlai Stevenson I of Illinois.

Despite reclaiming the presidency, Cleveland performed much worse in Delaware than he did in his 1888 re-election bid. The State shifted 10 points for Harrison, voting for Cleveland by only 1.4 percentage points. This would be one of four states where Harrison outperformed his initial run for the presidency in 1888, these other states were New Hampshire, Georgia and, South Carolina.

Results

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1892 United States presidential election in Delaware[1]
Party Candidate Votes Percentage Electoral votes
Democratic Grover Cleveland 18,581 49.90% 3
Republican Benjamin Harrison (incumbent) 18,077 48.55% 0
Prohibition John Bidwell 564 1.51% 0
Write-ins Scattered 13 0.03% 0
Totals 37,235 100.00% 3
Voter turnout

See also

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References

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  1. ^ Dave Leip's U.S. Election Atlas; Presidential General Election Results – Delaware

Notes

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