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1798 Delaware gubernatorial election

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1798 Delaware gubernatorial election

← 1795 October 2, 1798 1801 →
 
Nominee Richard Bassett David Hall
Party Federalist Democratic-Republican
Popular vote 2,490 2,068
Percentage 52.50% 43.60%

Bassett:      50–60%

Governor before election

Daniel Rogers (acting)
Federalist

Elected Governor

Richard Bassett
Federalist

The 1798 Delaware gubernatorial election was held on October 2, 1798.

Acting Governor Daniel Rogers was not eligible for re-election under the Delaware Constitution of 1792.

Federalist nominee Richard Bassett defeated Democratic-Republican nominee David Hall and Federalist nominee Barclay Townsend with 52.50% of the vote.

General election

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Results

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1798 Delaware gubernatorial election[1][2][3][4]
Party Candidate Votes % ±%
Federalist Richard Bassett 2,490 52.5%
Democratic-Republican David Hall 2,068 43.6%
Federalist Barclay Townsend 185 3.90%
Majority 422 8.90%
Turnout 4,743 100.00%
Federalist hold Swing

References

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  1. ^ "DE Governor, 1798". Our Campaigns. Retrieved December 8, 2020.
  2. ^ Congressional Quarterly 1998, p. 46.
  3. ^ Glashan 1979, pp. 50–51.
  4. ^ Dubin 2003, p. 26.

Bibliography

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  • Gubernatorial Elections, 1787-1997. Washington, D.C.: Congressional Quarterly Inc. 1998. ISBN 1-56802-396-0.
  • Glashan, Roy R. (1979). American Governors and Gubernatorial Elections, 1775-1978. Meckler Books. ISBN 0-930466-17-9.
  • Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson, North Carolina: McFarland. ISBN 978-0-7864-1439-0.