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1826 Delaware gubernatorial election

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1826 Delaware gubernatorial election

← 1823 (special) October 3, 1826 1829 →
 
Nominee Charles Polk Jr. David Hazzard
Party Federalist Democratic-Republican
Popular vote 4,333 4,051
Percentage 50.55% 48.23%

Polk:      60–70%
Hazzard:      50–60%      60–70%

Governor before election

Samuel Paynter
Federalist

Elected Governor

Charles Polk Jr.
Federalist

The 1826 Delaware gubernatorial election was held on October 3, 1826. Incumbent Federalist Governor Samuel Paynter was barred from seeking re-election to a second consecutive term. State Senator Charles Polk Jr. ran as the Federalist nominee to succeed Paynter, while 1823 Democratic-Republican nominee David Hazzard once again ran as his party's nominee. Polk ended up defeating Hazzard by a narrow margin, barely holding onto the governorship for the Federalists.[1]

General election

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Results

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1826 Delaware gubernatorial election[2]
Party Candidate Votes % ±%
Federalist Charles Polk Jr. 4,333 50.55% −1.21%
Democratic-Republican David Hazzard 4,238 49.45% +1.21%
Majority 95 1.11% −2.43%
Turnout 8,571 100.00%
Federalist hold

References

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  1. ^ Conrad, Henry C. (1908). History of the State of Delaware: From the Earliest Settlements to the Year 1907. Vol. 1. Lancaster, Pa.: Wickersham Company, Printers and Binders. p. 180.
  2. ^ Dubin 2003, p. 27.

Bibliography

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  • Gubernatorial Elections, 1787-1997. Washington, D.C.: Congressional Quarterly Inc. 1998. ISBN 1-56802-396-0.
  • Glashan, Roy R. (1979). American Governors and Gubernatorial Elections, 1775-1978. Meckler Books. ISBN 0-930466-17-9.
  • Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson, North Carolina: McFarland. ISBN 978-0-7864-1439-0.