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1804 United States presidential election in Delaware

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1804 United States presidential election in Delaware

← 1800 2 November – 5 December 1804 1808 →
 
Nominee Charles C. Pinckney Thomas Jefferson
Party Federalist Democratic-Republican
Home state South Carolina Virginia
Running mate Rufus King George Clinton
Electoral vote 3 0

The 1804 United States presidential election in Delaware took place between 2 November and 5 December 1804, as part of the 1804 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

Delaware cast three electoral votes for the Federalist candidate Charles C. Pinckney over the Democratic-Republican candidate and incumbent President Thomas Jefferson. These electors were elected by the Delaware General Assembly, the state legislature, rather than by popular vote. The three electoral votes for Vice president were cast for Pinckney's running mate Rufus King from New York.[1]

Results

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1804 United States presidential election in Delaware[2]
Party Candidate Votes Percentage Electoral votes
Federalist Charles C. Pinckney 3
Democratic-Republican Thomas Jefferson (incumbent) 0
Totals 3

See also

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References

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  1. ^ "1804 Presidential General Election Results". U.S. Election Atlas. Retrieved July 9, 2023.
  2. ^ "1804 Presidential Election". 270towin.com. Retrieved July 9, 2023.