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Questions tagged [quantum-electrodynamics]

Quantum electrodynamics (QED) is the quantum field theory believed to describe electromagnetic interaction. It is the simplest example of a quantum gauge theory, where the gauge group is abelian, U(1).

-1 votes
2 answers
206 views

How exactly does a proton form from quarks? What is the exact sequence and mechanism?

What are the steps that lead to the bonding of two up quarks and one down quark into a proton? For instance, does an up quark "bind" with a down quark in quark-gluon plasma, which then binds ...
xxl's user avatar
  • 29
0 votes
0 answers
33 views

Probability amplitudes in Richard Feynman’s QED [duplicate]

So i’ve been reading Richard Feyman’s book, QED, and in it, he simplifies the idea of how physicists calculate the probability of a photon hitting a certain detector. He lets the magnitude of a vector ...
Rockkinkajou's user avatar
5 votes
3 answers
1k views

Why does light interact with normal matter but not with other light?

Why does light interact with normal matter but not with other light? Assumptions: Light does not interact with other light at all. Light does interact with other matter, i.e reflection/refraction.
Muhammad Javed's user avatar
1 vote
1 answer
124 views

Why did Schwinger [Phys. Rev. 74 (1948) 1439] choose a non-standard form of the Lagrangian density associated with the free electromagnetic field?

This sounds like a science history question, but is not. It is about acceptable forms for the Lagrangian density of electromagnetism. There is also a second question on the distinction between total ...
Trond Saue's user avatar
5 votes
0 answers
223 views

Why poles of two-point function corresponds to bound states?

In this article Two-time Green function method in quantum electrodynamics of high-Z few-electron atoms the author has: Let $\mathcal{G}$ be fourier transform of the green function $$ \begin{array}{r} \...
amilton moreira's user avatar
0 votes
0 answers
18 views

Are static electric and magnetic fields flows of virtual photons? [duplicate]

Many electromagnetic interactions are modeled as exchanges of a real photons: e.g. an excited electron can relax and emit a photon. Somewhere else, a photon and an electron can interact, "...
chbaker0's user avatar
  • 305
2 votes
1 answer
44 views

Spin magnetic dipole moment of electron not an invariant with acceleration?

Since the energy of the electron at rest can be calculated by: $$ E_e=\frac{h c}{ \lambda_e} $$ where $\lambda_e$ is the Compton wavelength value of the electron at rest, $h$ the Planck constant and $...
Markoul11's user avatar
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0 votes
0 answers
116 views

Unitarity of time-evolution operator of Dirac's equation

Let $\Psi(t)$ be state of Dirac's electron in context of Dirac's equation and consider time-evolution operator $$\Psi(t) = U(t)\Psi(0)$$ is or is not $U$ an unitary (preserving length) operator? (note ...
moshtaba's user avatar
  • 1,409
2 votes
0 answers
76 views

Lorentz invariance

In QED loop renormalization, Lorentz invariance is often used to express the possible momentum-dependence of the propagators. For example, the propagator corresponding to the fermion loop is $$ie_0^2 \...
nomeruk's user avatar
  • 138
5 votes
1 answer
247 views

Radiative correction of the electron self-energy

In Mandl & Shaw's Quantum Field Theory (2nd edition p217), the radiative correction for the electron self-energy is: $$ e_0^2 \Sigma(p) = \frac{\tilde{e_0}^2}{16\pi^2} (p\!\!/ -4m) \left(\frac{2}{\...
nomeruk's user avatar
  • 138
1 vote
1 answer
107 views

Why would energy conservation be violated during interference if a wave function represented multiple photons?

the below paragraph is from Paul Dirac's 'The principles of quantum mechanics'. He argues that representing multiple photons' probability distribution via a single wavefunction leads to energy ...
Meet Chaudhari's user avatar
4 votes
2 answers
209 views

Propagator and Ward identity in the $R_\xi$ gauge

The full gauge propagator in the $R_\xi$ gauge is $$D_{\mu\nu} = \frac{i}{k^2+i\epsilon}\left(-g_{\mu\nu}+\frac{1-\xi}{k^2}k_\mu k_\nu\right).\tag{1}$$ Now if we take $\xi=0$, we get the Lorenz gauge, ...
Mohamed Ahmed's user avatar

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