Skip to main content

Questions tagged [partons]

A parton is a gluon, quark or antiquark in the eponymous model of scattering involving hadrons. In the hadron's infinite-momentum frame, incoming particles will be scattered instantaneously and incoherently, reducing the problem to a simple kernel convolved with parton distributions, at a particular physical scale (as probed by the inverse of the momentum transfer).

6 votes
2 answers
2k views

Why is it that the Callan-Gross relation predicts that quark has spin 1/2?

I'm studying deep inelastic scattering, and currently at the part where they say the Callan-Gross relation: $$F_1 (x) = \frac{1}{2x} F_x (x)$$ where $F_1$ and $F_2$ are the dimensionless structure ...
Kim Dong's user avatar
  • 700
5 votes
2 answers
1k views

Do electrons interact with gluons?

I know the straightforward answer to this question is no: electrons are leptons which by definition don't interact via the strong force, gluons are the mediators of the strong force and hence ...
Quantum spaghettification's user avatar
4 votes
1 answer
429 views

Parton model in experimental particle physics

In experimental particle physics, what does "parton-level" , "particle-level" and "detector-level" exactly mean ? PS : detailed explanations, links, etc .. would be deeply appreciated
M.A.B's user avatar
  • 243
3 votes
2 answers
350 views

How to derive operator form of the parton distribution function

A similar question is found here in Stackexchange a year ago without any response. I am following the formulation of the parton densities from the handbag diagram in Collins Handbook of Perturbative ...
firest's user avatar
  • 115
3 votes
2 answers
368 views

Sea quark parton annihilation?

Consider the figure below1: This can be read as follows (please correct me if I am wrong): two particles come in and 'fragment', a parton from each particle $C$ and $D$ annihilate to form the ...
Quantum spaghettification's user avatar
2 votes
0 answers
47 views

How to define the parton distribution function of the antiquark?

So I can define the quark distribution function within a hadron as $$ f_{\psi/h}(x)=\frac{1}{2}\int\frac{dz^-}{2\pi}e^{ixP^+z^-} \langle h(p)|\bar{\psi}(0)\gamma^+\psi(z^-)|h(p)\rangle|_{z^2=0} $$ ...
firest's user avatar
  • 115