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1 vote
1 answer
341 views

Minimal coupling Hamiltonian

A charged particle in an em field can be described by the following Hamiltonian (in CGS units): $$H = \frac {(\vec{p} \ + \frac {q}{c}\vec{A})^2}{2m} + U(r)$$ But... what does it mean to square the ...
ric.san's user avatar
  • 1,644
2 votes
1 answer
170 views

How to prove that the normal mode eigenvalue problem constitutes that of a Hermitian operator?

I am physics PhD student working on quantisation of electromagnetic fields in a non-homogeneous media. I am working through a paper at the moment and I am struggling with one of the statements. In the ...
Kristian Stokkereit's user avatar
3 votes
2 answers
483 views

Is electric field operator in Schrödinger picture time-dependent?

We know that in the Schrödinger picture, operators are time-independent if they do not have explicit time-dependence. So do electric field and vector potential field operators have time dependence in ...
physshyp's user avatar
  • 1,369
1 vote
0 answers
56 views

Why is there an inconsistency between the gauge transformation of the classical canonical momentum and the momentum operator in quantum mechanics? [duplicate]

I feel that there is a little inconsistency between the canonical momentum of a classical charged particle in an electromagnetic field and the momentum operator associated to the equivalent quantum ...
squinterodlr's user avatar
1 vote
1 answer
149 views

Schrödinger equation for charged particle in potential

This might be a silly question, but I don't think it is trivial. I am trying to solve an example for my class. In it the Schrödinger equation for a charged particle in a vector potential is given: $$i\...
eeqesri's user avatar
  • 1,488
3 votes
2 answers
593 views

The strange character of operator $\nabla$

I was first introduced to the mathematical operation gradient, divergence and curl not in Mathematics but during my studies of Electromagnetism. As you all know learning Maths from a Physics teacher ...
user avatar
0 votes
1 answer
98 views

Evaluation of Hamiltonian of a charged particle under EM field

The Hamiltonian of a charged partical in EM field is given by $$H = \frac{\pi^2}{2m} -e \phi$$ where $$\boldsymbol{\pi}=-\mathrm{i} \hbar \boldsymbol{\nabla}+e \mathbf{A}.$$ To evaluate $\pi^2$, we ...
user292458's user avatar
0 votes
1 answer
120 views

Justification of dropping term in Hamiltonian and expectation Values

While reading Sakurai's Modern QM, I was stuck at the point where he explains the absorption and emission of light quanta in atoms. He proceeds with Hamiltonian: $$H= p^2/2m + e\phi(x) -e/mc A\cdot p$...
Abhi7731756's user avatar
1 vote
1 answer
69 views

An electrodinamic identity: starting point [closed]

With this request, I would like to ask you kindly how you can prove this identity. I thank you for those who can help me. \begin{equation} \overline{\nabla} \times (\overline{\nabla} \times \...
Sebastiano's user avatar
  • 2,547
7 votes
1 answer
580 views

Why is the generalized momentum replaced by the momentum operator but not the ordinary momentum?

I was trying to understand the derivation of the Hamiltonian for a charged particle in an electromagnetic field. https://en.wikipedia.org/wiki/Hamiltonian_mechanics#...
stonar96's user avatar
  • 135
1 vote
1 answer
69 views

What is the physical interpretation of the derivative of a particle field?

I am learning quantum field theory, specifically the quantization of the electromagnetic field. We have this Laplacian $$ \mathcal{L} = -\frac{1}{2} \partial_\mu A_\nu \partial^\mu A^\nu -j_\mu A^\mu $...
Fernando Franco Félix's user avatar
2 votes
0 answers
144 views

What this quantum field operator represents $ b_{in}(t) = \frac{1}{\sqrt{2 \pi}} \int e^{-i \omega t} b(\omega)$? [duplicate]

In Input and output in damped quantum systems: Quantum stochastic differential equations and the master equation Physics Department, Uniuersity of Waikato, Hamilton, ¹tuZealand (Received 29 ...
StarBucK's user avatar
  • 1,450
0 votes
1 answer
252 views

Why do we think that the relation $\vec{\mu}_L=\frac{e}{2m_e}\vec{L}$ will be valid in quantum mechanics?

Assuming the electrons to revolve round the nucleus in circular orbits and using the fact from classical electromagnetism that a current loop behaves like a magnetic dipole of dipole moment $\vec{\mu}...
Solidification's user avatar
1 vote
2 answers
327 views

Problem with the Landau gauge

I'm having a very simple problem which probably has an equally simple answer. I'm following the wikipedia article: https://en.wikipedia.org/wiki/Landau_quantization We have a uniform magnetic field ...
Jens Roderus's user avatar
2 votes
1 answer
146 views

How to prove that the quantity appearing in the exponent of the path integral is the Lagrangian?

In Zee's Quantum Field Theory in a Nutshell, it is shown that, if $H = \frac{\hat{p}^2}{2m}$, then \begin{equation} \langle q_F | e^{-iHt} | q_I \rangle = \int e^{i\int \frac{1}{2}m\dot{q}^2 \, dt} ...
Brian Bi's user avatar
  • 6,601

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