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1 vote
1 answer
429 views

What exactly does it mean by gauge-invariant "operators"?

For simplicity, let us consider $U(1)$ gauge theory without matter fields. At classical level, the gauge field $A^\mu$ has the gauge transformation law \begin{equation} A^\mu \to A^\mu +\partial^\mu \...
Keith's user avatar
  • 1,669
1 vote
0 answers
74 views

How does the electromagnetic dipole operator appear in the decay $b \rightarrow s \gamma$?

I was analyzing the effective theory of the process $b \rightarrow s \gamma$ and and I was in doubt about the emergence of the effective operator of photon dipole $$O_7 = e m_b \bar{s}_L \sigma_{\mu\...
Joao Vitor's user avatar
3 votes
2 answers
483 views

Is electric field operator in Schrödinger picture time-dependent?

We know that in the Schrödinger picture, operators are time-independent if they do not have explicit time-dependence. So do electric field and vector potential field operators have time dependence in ...
physshyp's user avatar
  • 1,369
2 votes
0 answers
144 views

What this quantum field operator represents $ b_{in}(t) = \frac{1}{\sqrt{2 \pi}} \int e^{-i \omega t} b(\omega)$? [duplicate]

In Input and output in damped quantum systems: Quantum stochastic differential equations and the master equation Physics Department, Uniuersity of Waikato, Hamilton, ¹tuZealand (Received 29 ...
StarBucK's user avatar
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