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4 votes
2 answers
2k views

Derivatives of Dirac delta function and equation of continuity for a single charge

For a single charge $e$ with position vector $\textbf R$, the charge density $\rho$ and and current density $\textbf{j}$ are given by: \begin{equation} \rho(\textbf{r},t)= e\,\delta^3(r-\textbf{R}(t))...
quark1245's user avatar
  • 1,352
4 votes
1 answer
225 views

Is there a quick way to calculate the derivative of a quantity that uses Einstein's summation convention?

Consider $F_{\mu\nu}=\partial_{\mu}A_\nu-\partial_\nu A_\mu$, I am trying to understand how to fast calculate $$\frac{\partial(F_{\mu\nu}F^{\mu\nu})}{\partial (\partial_\alpha A_\beta)}$$ without ...
Rescy_'s user avatar
  • 838
4 votes
1 answer
108 views

What does $\mathbf{A}\cdot\nabla$ mean here?

What does $\mathbf{A}\cdot\nabla$ mean in an expression like $(\mathbf{A}\cdot\nabla)\mathbf B$? I found this in Griffiths’ Classical Electrodynamics book and cannot figure it out.
Pranshu Khare's user avatar
3 votes
3 answers
113 views

Finding the vector potential

$$\nabla\times\mathbf{B}=\nabla\times\left(\nabla\times\mathbf{A}\right)=\nabla\left(\nabla\cdot\mathbf{A}\right)-\nabla^2\mathbf{A}=\mu_0\mathbf{J}\tag{5.62}$$ Whenever I try to work this out and ...
Phoooebe's user avatar
  • 220
3 votes
1 answer
435 views

Heaviside-Feynman formula derivation

I want to discuss derivation of Feynman-Heaviside formula. The topic has already been discussed here but I can not put there any question that's why I'm making new post. Deriving Heaviside-Feynman ...
Jarogniew Borkowski's user avatar
2 votes
1 answer
2k views

Derivatives with upper and lower indices

I'm studying classical and quantum field theory, but evaluating derivatives of fields (scalar and/or vector) described with upper and lower indices is somewhat new to me. I'm trying to evaluate $$\...
Libertron's user avatar
  • 187
2 votes
2 answers
4k views

Total time derivative of magnetic vector potential $A$

I am looking at this document, which tries to establish the Lagrangian of the Lorentz force. Everything is fine, but I don't see why: $$\frac{dA_i}{dt}=\frac{\partial A_i}{\partial t}+\frac{\partial ...
student1's user avatar
  • 594
2 votes
1 answer
213 views

Tensor Differentiation

In the book "Tensors, Relativity and Cosmology" the author derived Maxwell's Equation in covariant form using the EM field tensor Lagrangian $L=-\frac{1}{4}F^{jl}F_{jl}$ (source=0). One of the steps ...
Chern-Simons's user avatar
  • 1,047
2 votes
3 answers
498 views

About field gradient

I read the term field gradient in most of the article about magnetic field. I search it online but most of the explanation is about the math. I wonder in physics, what the gradient field really mean? ...
user1285419's user avatar
  • 2,383
1 vote
2 answers
4k views

Derivative of the magnetic field to the vector potential

So the magnetic field is defined with the vector potential A as: $$\mathbf{B}=\nabla\times\mathbf{A}.$$ How would I calculate the derivative: $$\frac{\delta}{\delta\mathbf{A}}|\mathbf{B}|^2$$ I ...
Nick's user avatar
  • 3,112
1 vote
3 answers
143 views

Passing from curl to vector product

I don't understand how to obtain second equation with first part in the equation $$ \nabla \times \vec A_0 e^{-j \vec k\cdot \vec r} = -j\vec k\times \vec A_0 e^{-j \vec k\cdot \vec r}. $$ Can you ...
sha's user avatar
  • 13
1 vote
1 answer
226 views

Four-vector differentiation (E-M Euler-Lagrange eq.)

$$\partial_{\mu} \frac{\partial(\partial_{\alpha}A_{\alpha})^2}{\partial(\partial_{\mu}A_{\nu})} = \partial_{\mu}\left[2(\partial_{\alpha}A_{\alpha})\frac{\partial(\partial_{\beta}A_{\gamma})}{\...
Fortinbras's user avatar
1 vote
1 answer
90 views

How to show the equivalence between Lagrangians?

I have a Lagrangian of a form: $$\mathcal{L}=\frac{1}{2}\left (A_\mu g^{\mu\nu}\partial^2 A_\nu-A_\mu \partial^\mu \partial^\nu A_\nu\right ) $$ And I want to show that it is equivalent to the ...
aerospace's user avatar
1 vote
1 answer
836 views

Derivation of curl of magnetic field [closed]

I am having trouble in one part of derivation of curl of magnetic field, from Biot-Savart law. The attached picture is from Griffiths - Introduction to Electrodynamics. I got all the parts, but only ...
solidbastard's user avatar
1 vote
1 answer
285 views

Help with relativistic notation (Derivative of Lagrangian)

I am trying to learn QFT, but I haven't taken a course in general relativity so the relativistic notation stuff is taking me a bit to get used to. I do not understand how to do the following. For a ...
user41178's user avatar
  • 1,001

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