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0 votes
4 answers
129 views

Why should an electron falling into the nucleus, according to the Maxwell's laws of electrodynamics, destroy the atom?

It is often said in physics and chemistry classes and textbooks that atoms must be unstable when the electron continuously loses energy and finally fall into the nucleus according to classical physics....
3 votes
2 answers
129 views

Radiation from accelerated charged in a co-accelerated reference frame

I was wondering if I sit on a accelerated charge particle I will not observe radiation since the particle is at rest according to me. But my friend observes it from outside and he will see radiation ...
1 vote
3 answers
208 views

Would fast oscillating charged object emit light?

If I were able to mechanically oscillate an electrically charged object at frequencies of 430-580 THz, would the object emit light?
0 votes
1 answer
67 views

Paradox in the observation of ripple

What I am going to speak about may not be a paradox but i see a contradiction here so I used used the word "paradox". To begin with, let there be 2 charges A and B which are stationary with ...
1 vote
3 answers
112 views

Accelerated Electric Charges

We know that an accelerated electric charge produces electromagnetic radiation. We also know that acceleration is relative to an observer. Take electrically neutral observers A and B, who are ...
2 votes
2 answers
149 views

Which equations indeed describe moving/accelerated charge field?

The thing that I have not understood completely, for 100%, is how does the field of the electric charge is "updated". If to consider a frame of reference where the charge is static, does ...
3 votes
2 answers
1k views

Why would an orbiting electron lose energy?

Ernest Rutherford proposed that the electrons were orbiting around the nucleus just like planets orbiting around the sun. However, this simple picture defied the laws of physics. Electrons revolving ...
13 votes
2 answers
15k views

Why do accelerating electrons emit radiation?

I know how you can emit light with an alternating current, running back and forth, creating an electric field in addition to the magnetic field. But why does an electron emit light when it gets ...
6 votes
5 answers
2k views

Does a rotating ring of charge radiate power or not?

The Larmor Formula suggests that the power radiated by an accelerating charge is non zero. But we know that a uniformly charged non-conducting ring rotating about its central axis does not radiate. ...
107 votes
5 answers
109k views

How and why do accelerating charges radiate electromagnetic radiation?

Let's consider it case by case: Case 1: Charged particle is at rest. It has an electric field around it. No problem. That is its property. Case 2: Charged particle started moving (it's accelerating)....
1 vote
2 answers
164 views

Energy-work theorem and dissipation of energy by an accelerating charge

By the work energy theorem we have that the total energy of a nonrelativistic point charge, $q_0$ of mass $m$, moving in an electric field $\mathbf{E}$ is $ E = E_k + U_e = \frac{1}{2}mv^2 + q_0V \...
3 votes
2 answers
384 views

Does accelerating magnet emit radiation?

Just like accelerating charge produces emits radiation, does an accelerating magnet emit electromagnetic radiation?
-1 votes
2 answers
65 views

If we vibrate a charged mass, will it radiates or not? [closed]

It is said that electromagnetic radiation created from accelerated charged particle. I want to mechanically vibrate a charged mass , then will it radiates or not?
10 votes
5 answers
6k views

Why does an accelerated charge radiate away energy?

My textbook says: "Neils Bohr objected to the idea of an electron orbiting a nucleus in a circular orbit. An electron experiences centripetal acceleration and an accelerated charge radiates away ...
63 votes
7 answers
12k views

Does a constantly accelerating charged particle emit EM radiation or not?

The Abraham-Lorentz force gives the recoil force, $\mathbf{F_{rad}}$, back on a charged particle $q$ when it emits electromagnetic radiation. It is given by: $$\mathbf{F_{rad}} = \frac{q^2}{6\pi \...

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